24.11.2020

For a soccer party Kaleb collects $70 for pizza. He must buy more than 4 pizzas to feed the team. Pizzas are $6.25 for a small pizza and $10.50 for a large pizza. Let:

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26.03.2023, solved by verified expert
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Answer:

6.25S + 10.50L ≤ 70
S + L ≥ 4
S, L ≥ 0

Step-by-step explanation:

Let S be the number of small pizzas and L be the number of large pizzas that Kaleb buys.

The cost of each small pizza is $6.25 and the cost of each large pizza is $10.50. So, the total cost of S small pizzas and L large pizzas will be:

Total Cost = (6.25S) + (10.50L)

Kaleb must buy at least 4 pizzas. So, the total number of pizzas must be at least 4.

Total Pizzas = S + L

Now, we can write the system of inequalities as:

Total Cost ≤ $70
Total Pizzas ≥ 4
S, L ≥ 0 (since we can't have negative pizzas)

Substituting the expressions for Total Cost and Total Pizzas in terms of S and L, we get:

(6.25S) + (10.50L) ≤ 70
S + L ≥ 4
S, L ≥ 0

Therefore, the system of inequalities representing this situation is:

6.25S + 10.50L ≤ 70
S + L ≥ 4
S, L ≥ 0

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