Mathematics: Solve the following equation (x−5)(x+3)=−7

Step-by-step explanation: Given equation (x-5) (x+3) =-7On solving (x^2 +3x -5x -15) = -7Combining the...

Solve the following equation (x−5)(x+3)=−7, №15257795, 02.12.2021 06:52

Mathematics

1) Which is a binomial factor of 8x2 + 26x + 15? A) x − 5 B) 2x − 5 C) 2x + 3 D) 4x + 3 2) Factor x2 + 5x - 24 A) (x + 8)(x - 3) B) (x + 3)(x - 8) C) (x + 6)(x + 4) D) (x + 2)(x - 12) 3) Factor the polynomial. 8x2 - 50 A) 2(4x - 5)(x - 5) B) 2(2x - 5)(2x - 5) C) 2(2x + 5)(2x + 5) D) 2(2x - 5)(2x + 5) 4) Which binomial is a factor of the polynomial? 3x2 + 7x + 2 A) (x − 1) B) (x − 2) C) (x − 2) D) (3x + 1) 5) Solve. x2 − 5x = 14 A) x = 0, x = 5 B) x = 0, x = −5 C) x = 2, x = −7 D) x = 7, x = −2 6) Factor x2 + 5x - 50 A) (x + 25)(x - 2) B) (x - 5)(x

Step-by-step answer

P Answered by PhD

14

Following are the calculation to the given points:

For point 1:

$\bold{8x^2+26x+15}\\\\\bold{8x^2+(20+6)x+15}\\\\\bold{8x^2+20x+6x+15}\\\\\bold{4x(2x+5)+3(2x+5)}\\\\\bold{(2x+5)(4x+3)}\\\\$

Therefore, the answer is "Option D".

For point 2:

$\bold{x^2 + 5x - 24}\\\\\bold{x^2 + (8-3)x - 24}\\\\\bold{x^2 + 8x-3x - 24}\\\\\bold{x(x + 8)-3(x +8)}\\\\\bold{(x + 8) (x-3)}\\\\$

Therefore, the answer is "Option A".

For point 3:

$\bold{8x2 - 50}\\\\\bold{2(4x2 - 25)}\\\\\bold{2((2x)^2 - 5^2)}\\\\\therefore \ \ x^2-y^2=(x+y) (x-y)\\\\\bold{2((2x - 5)(2x+5)}\\\\$

Therefore, the answer is "Option D".

For point 4:

$\bold{3x^2 + 7x + 2}\\\\\bold{3x^2 +(6+1)x + 2}\\\\\bold{3x^2 +6x+1x + 2}\\\\\bold{3x(x +2)+1(x + 2)}\\\\\bold{(x +2) (3x+1)}\\\\$

Therefore, the answer is "Option D".

For point 5:

$\bold{x^2 - 5x = 14}\\\\\bold{x^2 - 5x -14= 0}\\\\\bold{x^2 - (7-2)x -14= 0}\\\\\bold{x^2 -7x+2x -14= 0}\\\\\bold{x(x -7)+2(x -7)= 0}\\\\\bold{(x -7) (x+2)= 0}\\\\\bold{x -7=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x+2= 0}\\\\\bold{x =7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x= -2}\\\\$

Therefore, the answer is "Option D".

For point 6:

$\bold{x^2 + 5x - 50}\\\\\bold{x^2 + (10-5)x - 50}\\\\\bold{x^2 + 10x-5x - 50}\\\\\bold{x(x+ 10)-5(x +10)}\\\\\bold{(x+ 10)(x -5)}\\\\$

Therefore, the answer is "Option B".

For point 7:

$\bold{16x^2 + 24x + 9}\\\\\bold{16x^2 + (12+12)x + 9}\\\\\bold{16x^2 + 12x+12x + 9}\\\\\bold{4x(4x +3)+3(4x + 3)}\\\\\bold{(4x +3)(4x + 3)}\\\\\bold{(4x +3)^2}\\\\$

Therefore, the answer is "Option A".

For point 8:

$\bold{32x^2 - 50}\\\\\bold{2(16x^2 - 25)}\\\\\bold{2((4x)^2 - (5)^2)}\\\\\bold{2((4x-5)(4x+5))}\\\\$

Therefore, the answer is "Option B".

For point 9:

$\bold{x^2 + 7x - 18}\\\\\bold{x^2 + (9-2)x - 18}\\\\\bold{x^2 + 9x-2x - 18}\\\\\bold{x(x+ 9)-2(x +9)}\\\\\bold{(x+ 9)(x-2)}\\\\$

Therefore, the answer is "Option C".

For point 10:

$\bold{x^2 + 5x - 14}\\\\\bold{x^2 + (7-2)x - 14}\\\\\bold{x^2 + 7x-2x - 14}\\\\\bold{x(x+7)-2(x +7)}\\\\\bold{(x+7)(x -2)}\\\\$

Therefore, the answer is "Option C".

For point 11:

$\bold{25x^2 - 64}\\\\\bold{(5x)^2 - (8)^2}\\\\\bold{(5x-8)(5x+8)}\\\\$

Therefore, the answer is "Option C".

For point 12:

$\bold{x^2 - 81}\\\\\bold{x^2 - 9^2}\\\\\bold{(x - 9)(x+9)}\\\\$

Therefore, the answer is "Option A".

For point 13:

$\bold{8x^2 + 16x + 8 = 0}\\\\\bold{8(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + x+x + 1) = 0}\\\\\bold{(x(x +1)1(x + 1)) = 0}\\\\\bold{(x +1)(x + 1) = 0}\\\\\bold{(x +1)^2 = 0}\\\\\bold{x +1 = 0}\\\\\bold{x=-1}\\\\$

Therefore, the answer is "Option B".

For point 14:

$\bold{x^2 -x -12 = 0}\\\\\bold{x^2 -(4-3)x -12 = 0}\\\\\bold{x^2 -4x+3x -12 = 0}\\\\\bold{x(x -4)+3(x -4) = 0}\\\\\bold{(x -4) (x+3) = 0}\\\\\bold{(x -4)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x+3) = 0}\\\\\bold{x =4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = -3}\\\\$

Therefore, the answer is "Option C".

For point 15:

$\bold{6x^2 + 8x - 28 = 2x^2 + 4}\\\\\bold{6x^2 + 8x - 28 - 2x^2 - 4=0}\\\\\bold{4x^2 + 8x - 32=0}\\\\\bold{4(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + (4-2)x - 8)=0}\\\\\bold{(x^2 + 4x-2x - 8)=0}\\\\\bold{(x(x + 4)-2(x +4))=0}\\\\\bold{(x + 4)(x -2)=0}\\\\\bold{(x + 4)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x -2)=0}\\\\\bold{x =-4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x =2}\\\\$

Therefore, the answer is "Option B".

For point 14:

$\bold{6z^2 + 18z}\\\\\bold{6z(z + 3)}\\\\$

Therefore, the answer is "Option B".

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1) Which is a binomial factor of 8x2 + 26x + 15? A) x − 5 B) 2x − 5 C) 2x + 3 D) 4x + 3 2) Facto

Mathematics

1) Which is a binomial factor of 8x2 + 26x + 15? A) x − 5 B) 2x − 5 C) 2x + 3 D) 4x + 3 2) Factor x2 + 5x - 24 A) (x + 8)(x - 3) B) (x + 3)(x - 8) C) (x + 6)(x + 4) D) (x + 2)(x - 12) 3) Factor the polynomial. 8x2 - 50 A) 2(4x - 5)(x - 5) B) 2(2x - 5)(2x - 5) C) 2(2x + 5)(2x + 5) D) 2(2x - 5)(2x + 5) 4) Which binomial is a factor of the polynomial? 3x2 + 7x + 2 A) (x − 1) B) (x − 2) C) (x − 2) D) (3x + 1) 5) Solve. x2 − 5x = 14 A) x = 0, x = 5 B) x = 0, x = −5 C) x = 2, x = −7 D) x = 7, x = −2 6) Factor x2 + 5x - 50 A) (x + 25)(x - 2) B) (x - 5)(x

Step-by-step answer

P Answered by PhD

14

Following are the calculation to the given points:

For point 1:

$\bold{8x^2+26x+15}\\\\\bold{8x^2+(20+6)x+15}\\\\\bold{8x^2+20x+6x+15}\\\\\bold{4x(2x+5)+3(2x+5)}\\\\\bold{(2x+5)(4x+3)}\\\\$

Therefore, the answer is "Option D".

For point 2:

$\bold{x^2 + 5x - 24}\\\\\bold{x^2 + (8-3)x - 24}\\\\\bold{x^2 + 8x-3x - 24}\\\\\bold{x(x + 8)-3(x +8)}\\\\\bold{(x + 8) (x-3)}\\\\$

Therefore, the answer is "Option A".

For point 3:

$\bold{8x2 - 50}\\\\\bold{2(4x2 - 25)}\\\\\bold{2((2x)^2 - 5^2)}\\\\\therefore \ \ x^2-y^2=(x+y) (x-y)\\\\\bold{2((2x - 5)(2x+5)}\\\\$

Therefore, the answer is "Option D".

For point 4:

$\bold{3x^2 + 7x + 2}\\\\\bold{3x^2 +(6+1)x + 2}\\\\\bold{3x^2 +6x+1x + 2}\\\\\bold{3x(x +2)+1(x + 2)}\\\\\bold{(x +2) (3x+1)}\\\\$

Therefore, the answer is "Option D".

For point 5:

$\bold{x^2 - 5x = 14}\\\\\bold{x^2 - 5x -14= 0}\\\\\bold{x^2 - (7-2)x -14= 0}\\\\\bold{x^2 -7x+2x -14= 0}\\\\\bold{x(x -7)+2(x -7)= 0}\\\\\bold{(x -7) (x+2)= 0}\\\\\bold{x -7=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x+2= 0}\\\\\bold{x =7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x= -2}\\\\$

Therefore, the answer is "Option D".

For point 6:

$\bold{x^2 + 5x - 50}\\\\\bold{x^2 + (10-5)x - 50}\\\\\bold{x^2 + 10x-5x - 50}\\\\\bold{x(x+ 10)-5(x +10)}\\\\\bold{(x+ 10)(x -5)}\\\\$

Therefore, the answer is "Option B".

For point 7:

$\bold{16x^2 + 24x + 9}\\\\\bold{16x^2 + (12+12)x + 9}\\\\\bold{16x^2 + 12x+12x + 9}\\\\\bold{4x(4x +3)+3(4x + 3)}\\\\\bold{(4x +3)(4x + 3)}\\\\\bold{(4x +3)^2}\\\\$

Therefore, the answer is "Option A".

For point 8:

$\bold{32x^2 - 50}\\\\\bold{2(16x^2 - 25)}\\\\\bold{2((4x)^2 - (5)^2)}\\\\\bold{2((4x-5)(4x+5))}\\\\$

Therefore, the answer is "Option B".

For point 9:

$\bold{x^2 + 7x - 18}\\\\\bold{x^2 + (9-2)x - 18}\\\\\bold{x^2 + 9x-2x - 18}\\\\\bold{x(x+ 9)-2(x +9)}\\\\\bold{(x+ 9)(x-2)}\\\\$

Therefore, the answer is "Option C".

For point 10:

$\bold{x^2 + 5x - 14}\\\\\bold{x^2 + (7-2)x - 14}\\\\\bold{x^2 + 7x-2x - 14}\\\\\bold{x(x+7)-2(x +7)}\\\\\bold{(x+7)(x -2)}\\\\$

Therefore, the answer is "Option C".

For point 11:

$\bold{25x^2 - 64}\\\\\bold{(5x)^2 - (8)^2}\\\\\bold{(5x-8)(5x+8)}\\\\$

Therefore, the answer is "Option C".

For point 12:

$\bold{x^2 - 81}\\\\\bold{x^2 - 9^2}\\\\\bold{(x - 9)(x+9)}\\\\$

Therefore, the answer is "Option A".

For point 13:

$\bold{8x^2 + 16x + 8 = 0}\\\\\bold{8(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + 2x + 1) = 0}\\\\\bold{(x^2 + x+x + 1) = 0}\\\\\bold{(x(x +1)1(x + 1)) = 0}\\\\\bold{(x +1)(x + 1) = 0}\\\\\bold{(x +1)^2 = 0}\\\\\bold{x +1 = 0}\\\\\bold{x=-1}\\\\$

Therefore, the answer is "Option B".

For point 14:

$\bold{x^2 -x -12 = 0}\\\\\bold{x^2 -(4-3)x -12 = 0}\\\\\bold{x^2 -4x+3x -12 = 0}\\\\\bold{x(x -4)+3(x -4) = 0}\\\\\bold{(x -4) (x+3) = 0}\\\\\bold{(x -4)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x+3) = 0}\\\\\bold{x =4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = -3}\\\\$

Therefore, the answer is "Option C".

For point 15:

$\bold{6x^2 + 8x - 28 = 2x^2 + 4}\\\\\bold{6x^2 + 8x - 28 - 2x^2 - 4=0}\\\\\bold{4x^2 + 8x - 32=0}\\\\\bold{4(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + 2x - 8)=0}\\\\\bold{(x^2 + (4-2)x - 8)=0}\\\\\bold{(x^2 + 4x-2x - 8)=0}\\\\\bold{(x(x + 4)-2(x +4))=0}\\\\\bold{(x + 4)(x -2)=0}\\\\\bold{(x + 4)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (x -2)=0}\\\\\bold{x =-4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x =2}\\\\$

Therefore, the answer is "Option B".

For point 14:

$\bold{6z^2 + 18z}\\\\\bold{6z(z + 3)}\\\\$

Therefore, the answer is "Option B".

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Mathematics

1. which of the following is the factored form of the expression: 3x2 – 4x? a. x(3x - 4) b. x(3 – 4x) c. (3x -1) (x -1) d. (3x +1)(x -1) 2. which is a completely factored form of the expression: x2 + 21x +20 ? a. (x + 5)(x + 4) b. (x + 10)(x + 2) c. (x + 20)(x + 1) d. (x + 21)(x - 1) 3. which expression is factored form of 4x2 -9? a. 2(x - 3)2 b. (x - 3)2 c. 2(x + 3)(x - 3) d. (2x + 3)(2x - 3) 4. below are factored forms of the expression: 12x3 – 36x2 . which expression has the greatest common factor as the first term? a. 3x (4x2 – 12x) b. 4x2(3x

Step-by-step answer

P Answered by PhD

34

1. 3x^2-4x=x(3x-4) - A.

2. x^2 + 21x +20=(x-x_1)(x-x_2)

Find the roots:

$D=21^2-4\cdot 20=441-80=361, \ \sqrt{D}=19,\\ \\x_1=\dfrac{-21-19}{2}=-20, \ x_2=\dfrac{-21+19}{2}=-1$ ,

then

x^2 + 21x +20=(x+20)(x+1) - C.

3. 4x^2 -9=(2x)^2-3^2=(2x-3)(2x+3) - D.

4. 12x^3-36x^2=12x^2(x-3) - C.

5. x^2 -5x -6=(x-x_1)(x-x_2)

Find the roots:

$D=(-5)^2-4\cdot (-6)=25+24=49, \ \sqrt{D}=7,\\ \\x_1=\dfrac{5-7}{2}=-1, \ x_2=\dfrac{5+7}{2}=6$ ,

then

x^2 -5x -6=(x-6)(x+1) and the width of the lawn is x-6 - A.

6. Since x^2 + 5x -24=(x+8)(x-3) the length and width are x+8 and x-3 - A.

7. 32 -8z^2=8(4-z^2)=8(2^2-z^2)=8(2-z)(2+z) - B.

8. $12x^2=2\cdot 2\cdot 3\cdot x\cdot x, \\24x^2y^2=2\cdot 2\cdot 2\cdot3\cdot x\cdot x\cdot y\cdot y , \\ 46xy=2\cdot 23\cdot x\cdot y$ .

So the greatest common divisor is $2\cdot x=2x$ - D.

9. 2x^2 -3x -35=2(x-x_1)(x-x_2)

Find the roots:

$D=(-3)^2-4\cdot (-35)\cdot 2=9+280=289, \ \sqrt{D}=17,\\ \\x_1=\dfrac{3-17}{2\cdot 2}=-\dfrac{7}{2}, \ x_2=\dfrac{3+17}{2\cdot 2}=5$ ,

then

$2x^2 -3x -35=2(x+\dfrac{7}{2})(x-5)=(2x+7)(x-5)$ - A.

10. $81x^2 + 36x + 4=(9x)^2+2\cdot 9x\cdot 2+2^2=(9x+2)^2$ - B.

11. $18x^2+ 69x +60=3(6x^2+23x+20)=3\cdot 6(x+\dfrac{5}{2})(x+\dfrac{4}{3})=(6x+15)(3x+4)$ , the length is 6x+15.

12. $(x^2 +2x)(5x -3) =x^2\cdot 5x-x^2\cdot 3+2x\cdot 5x-2x\cdot 3=5x^3-3x^2+10x^2-6x=5x^3+7x^2-6x$ - C.

13. 30g^5 +24g^3h- 35g^2h^2 - 28h^3=(30g^5 +24g^3h)-(35g^2h^2+ 28h^3)=6g^3(5g^2+4h)-7h^2(5g^2+4h)=(5g^2+4h)(6g^3-7h^2) .

14. x^2 -16=(x-4)(x+4) - B.

15. $81p^2 + 90p +25=(9p)^2+2\cdot 9p\cdot 5+5^2=(9p+5)^2$ , the length of one side is 9p+5.

Mathematics

1. which of the following is the factored form of the expression: 3x2 – 4x? a. x(3x - 4) b. x(3 – 4x) c. (3x -1) (x -1) d. (3x +1)(x -1) 2. which is a completely factored form of the expression: x2 + 21x +20 ? a. (x + 5)(x + 4) b. (x + 10)(x + 2) c. (x + 20)(x + 1) d. (x + 21)(x - 1) 3. which expression is factored form of 4x2 -9? a. 2(x - 3)2 b. (x - 3)2 c. 2(x + 3)(x - 3) d. (2x + 3)(2x - 3) 4. below are factored forms of the expression: 12x3 – 36x2 . which expression has the greatest common factor as the first term? a. 3x (4x2 – 12x) b. 4x2(3x

Step-by-step answer

P Answered by PhD

34

1. 3x^2-4x=x(3x-4) - A.

2. x^2 + 21x +20=(x-x_1)(x-x_2)

Find the roots:

$D=21^2-4\cdot 20=441-80=361, \ \sqrt{D}=19,\\ \\x_1=\dfrac{-21-19}{2}=-20, \ x_2=\dfrac{-21+19}{2}=-1$ ,

then

x^2 + 21x +20=(x+20)(x+1) - C.

3. 4x^2 -9=(2x)^2-3^2=(2x-3)(2x+3) - D.

4. 12x^3-36x^2=12x^2(x-3) - C.

5. x^2 -5x -6=(x-x_1)(x-x_2)

Find the roots:

$D=(-5)^2-4\cdot (-6)=25+24=49, \ \sqrt{D}=7,\\ \\x_1=\dfrac{5-7}{2}=-1, \ x_2=\dfrac{5+7}{2}=6$ ,

then

x^2 -5x -6=(x-6)(x+1) and the width of the lawn is x-6 - A.

6. Since x^2 + 5x -24=(x+8)(x-3) the length and width are x+8 and x-3 - A.

7. 32 -8z^2=8(4-z^2)=8(2^2-z^2)=8(2-z)(2+z) - B.

8. $12x^2=2\cdot 2\cdot 3\cdot x\cdot x, \\24x^2y^2=2\cdot 2\cdot 2\cdot3\cdot x\cdot x\cdot y\cdot y , \\ 46xy=2\cdot 23\cdot x\cdot y$ .

So the greatest common divisor is $2\cdot x=2x$ - D.

9. 2x^2 -3x -35=2(x-x_1)(x-x_2)

Find the roots:

$D=(-3)^2-4\cdot (-35)\cdot 2=9+280=289, \ \sqrt{D}=17,\\ \\x_1=\dfrac{3-17}{2\cdot 2}=-\dfrac{7}{2}, \ x_2=\dfrac{3+17}{2\cdot 2}=5$ ,

then

$2x^2 -3x -35=2(x+\dfrac{7}{2})(x-5)=(2x+7)(x-5)$ - A.

10. $81x^2 + 36x + 4=(9x)^2+2\cdot 9x\cdot 2+2^2=(9x+2)^2$ - B.

11. $18x^2+ 69x +60=3(6x^2+23x+20)=3\cdot 6(x+\dfrac{5}{2})(x+\dfrac{4}{3})=(6x+15)(3x+4)$ , the length is 6x+15.

12. $(x^2 +2x)(5x -3) =x^2\cdot 5x-x^2\cdot 3+2x\cdot 5x-2x\cdot 3=5x^3-3x^2+10x^2-6x=5x^3+7x^2-6x$ - C.

13. 30g^5 +24g^3h- 35g^2h^2 - 28h^3=(30g^5 +24g^3h)-(35g^2h^2+ 28h^3)=6g^3(5g^2+4h)-7h^2(5g^2+4h)=(5g^2+4h)(6g^3-7h^2) .

14. x^2 -16=(x-4)(x+4) - B.

15. $81p^2 + 90p +25=(9p)^2+2\cdot 9p\cdot 5+5^2=(9p+5)^2$ , the length of one side is 9p+5.

Mathematics

Ray and Kelsey have summer internships at an engineering firm. As part of their internship, they get to assist in the planning of a brand new roller coaster. For this assignment, you help Ray and Kelsey as they tackle the math behind some simple curves in the coaster s track. Part A The first part of Ray and Kelsey s roller coaster is a curved pattern that can be represented by a polynomial function. 1. Ray and Kelsey are working to graph a third-degree polynomial function that represents the first pattern in the coaster plan. Ray says the third-degree

Step-by-step answer

P Answered by Master

Part A

1. Third degree polynomial: f(x) = ax^3 + bx^2 + cx + d

The function can have as many as 3 zeroes only, but it can have 4 intercepts if you include the y-intercept.

2. g(x) = (x + 2)(x - 1)(x - 2) =x^3-x^2-4x+4

Zeroes at: x = -2, x = 1 and x = 2

y-intercept at (0, 4)

End behavior:

$x \rightarrow-\infty, f(x) \rightarrow-\infty\\\\x \rightarrow\infty, f(x) \rightarrow\infty$

3. see attached

Part B

4. f(x)=(x-2)(x-5)=x^2-7x+10

Direction: opens upwards

y-intercept: (0, 10)

zeros: x = 2, x = 5

5. see attached

**unfortunately I am unable to answer any additional questions as has a 5-question rule**

Ray and Kelsey have summer internships at an engineering firm. As part of their internship, they get

Mathematics

Which of the following show the factored equivalent of f(x) = (2x2 +7x + 3)(x - 3) and its zeros? f(x) = (x + 5)(x + 7)(x - 3); -5, -7, 3 f(x) = (x + 3)(2x + 1)(x - 3); -3, -0.5, 3 f(x) = (x + 5)(x + 7)(x - 3); 5, 7, -3 f(x) = (x + 3)(2x + 1)(x - 3); 3, 0.5, -3

Step-by-step answer

P Answered by Specialist

20

The second answer. f(x)=(2x+1)(x+3)(x-3)

Mathematics

WILL GIVE BRAINLIEST!! Directions: Solve using the FOIL method. Hint: Watch out for any negative signs and follow rules for signed numbers! 1. (x - 2)(x + 8) 2. (x + 6)(x - 12) 3. (x + 9)(x + 4) 4. (x + 6)(x + 2) 5. (x + 6)(x + 9) 6. (x - 4)(x + 5) 7. (x + 3)(x - 3) 8. (x + 10)(x + 10) 9. (x - 3)(x + 12) 10. (x + 4)(x - 3) 11. (x + 5)(x + 2) 12. (x - 3)(x - 4) 13. (x + 8)(x - 8) 14. (x -6)(x+3) 15. (x + 1)(x - 5)

Step-by-step answer

P Answered by PhD

1

Bet...but you really need to learn how to to this bc you use this in all types of math
All you have to do is distribute then combine like terms
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WILL GIVE BRAINLIEST!!

Directions: Solve using the FOIL method. Hint: Watch out for any negative si