Mathematics
: asked on dee071165

30.06.2021

seconds.

Step 2 of 3 : How much of a 12

gram sample of gold-195m would remain after 41

seconds? Round to three decimal places.

1

28.04.2023, solved by verified expert

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**Answer:**

**Step-by-step explanation:**

Given that :

Half-life of gold-195m (t½) = 30.5 seconds

Mass of gold-195 (N0) = 12 grams

The formula for decay is given by :

Nt= N0(1/2)^(t/t½)

Here Nt is the amount left after t seconds and t = 41 seconds.

Thus,

Nt = 12(1/2)^(41/30.5)

= **4.726 grams**

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