Answer:
4.726 gramsStep-by-step explanation:
Given that :
Half-life of gold-195m (t½) = 30.5 seconds
Mass of gold-195 (N0) = 12 grams
The formula for decay is given by :
Nt= N0(1/2)^(t/t½)
Here Nt is the amount left after t seconds and t = 41 seconds.
Thus,
Nt = 12(1/2)^(41/30.5)
= 4.726 grams