30.06.2021

The half-life of gold-195m is approximately 30.5
seconds.

Step 2 of 3 : How much of a 12
gram sample of gold-195m would remain after 41
seconds? Round to three decimal places.

. 1

Step-by-step answer

28.04.2023, solved by verified expert
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1 students found this answer . helpful

Answer:

4.726 grams

Step-by-step explanation:

Given that :

Half-life of gold-195m (t½) = 30.5 seconds

Mass of gold-195 (N0) = 12 grams

The formula for decay is given by :

Nt= N0(1/2)^(t/t½) 

Here Nt is the amount left after t seconds and t = 41 seconds. 

Thus, 

Nt = 12(1/2)^(41/30.5) 

= 4.726 grams

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