10.09.2022

# Kylie has 80% of the total points possible in her science class. if 350 points are possible, how many points does kylie have?

0

30.05.2023, solved by verified expert

280

Step-by-step explanation: In order to figure out how many points Kyle has in her science class, we need to find 80% of all the possible points which is 350 points.

To find 80% of 350, first write 80% as a decimal by moving the decimal point two places to the left to get .80.

Next, the word "of" means multiply, so we multiply .80 by 350.

(.80) (350) = 280

Therefore, Kylie has 280 points in he science class.

### Faq

Mathematics

280

Step-by-step explanation: In order to figure out how many points Kyle has in her science class, we need to find 80% of all the possible points which is 350 points.

To find 80% of 350, first write 80% as a decimal by moving the decimal point two places to the left to get .80.

Next, the word "of" means multiply, so we multiply .80 by 350.

(.80) (350) = 280

Therefore, Kylie has 280 points in he science class.

Mathematics

Step-by-step explanation:

Score = Σ(tests) + Σ(exams) = (7 + 8 + 7 + 5) + (81 + 80 + x) = 35 + 161  + x = 196 + x

To receive an A, the student must score at least 0.9 × 350 = 315 points

To receive a B, the student must score at least   0.8 × 350 = 280 points.

1. Can the student receive an A?

2. Minimum score for an A

3. Minimum score for a B

Mathematics

a) The student cannot receive an A in the class.

b) The student must score 119 in the third exams to make an A.  This is clearly not possible, since he cannot make 119 in a 100-points exam.

c) The student can make a B but he must score at least 84 in the third exam.

Step-by-step explanation:

To make an A, the student must score 315 (350 x 90%) in both home and the three exams.

The student who scored 35 (7 + 8 + 7 + 5 + 8) in the homework and 161 (81 + 80), getting a total of 196, is short by 119 (315 - 196) scores in making an A.

To make a B, the student must score 280 (350 x 80%) or higher but not reaching 315.

B ≥ 280 and < 315.

Since, the student had scored 196, he needs to score 84 and above to make a B in the last exam.

Mathematics

1. It is not possible, so the student cannot make an A, since he cannot make 119 scores in the third test.

2. Minimum score to make an A in the test is 315 - (35 + 161) = 119

3. The student can make a B, if he can score 84 and above in the third test.

Step-by-step explanation:

1. To get an A, a student must score 90% (0.9) and above

≥ 90% of 350 ≥ 315 scores,

Total Scores in the homework = 35 ((7 x 2) + (8 x 2) + 5) or 70% (35/50)

Total Scores in the two tests = 161 (81 + 80) or 80.5% (161/200)

Total scores by the student in homework and the two tests so far  = 196 (35 + 161).

However, he needs to score 315 (350 x 90%) to make an A.

Therefore, he is short by 119 (350 - 196), he cannot make an A.

2. To get a B, the student must score ≥ 80% or < 90%,

ideally, the student must score 280 (80% of 350) or above.

He would need to score 84 (280 - 196) in the third test to make 280 scores or 80% average of the total.

Therefore, he can make a B if he can score 84 in the third test.

Mathematics

i) it is not possible for the student to receive an A in the class

ii) 119 points

iii) 84points

Step-by-step explanation:

Total exam scores = 350points

homework scores of 7, 8, 7, 5, and 8

Let the third exam score =y

Exam scores = 81, 80, x

i) To know if the student would get an A in class, we would find the third exam score

(Scores received by a student)/ (total scores) = least of the grade percentage to get an A

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.9

(196+x)/350 = 0.9

196+x = 350 × 0.9

196+x = 315

x = 315-196

x = 119

119 > 100

Since the maximum grade for each of the exam score is 100points, it is not possible for the student to receive an A in the class.

ii) Since the least of the grade percentage that would guarantee an A is 0.9, the minimum score on the third exam that will give an A = 119points

iii) (Scores received by a student)/ (total scores) = least of the grade percentage to get a B

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.8

(196+x)/350 = 0.8

196+x = 350 × 0.8 = 280

x = 280-196

x = 84

The minimum score on the third exam that will give a B = 84points

Mathematics

It is not possible for the student to receive an A grade in the class.

It is possible for the student to receive a B grade in the class.

Step-by-step explanation:

We are given that in the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each.

A student has received homework scores of 7, 8, 7, 5, and 8, and the first two exam scores are 81 and 80.

Firstly, we will calculate how many points have been scored by the student.

Number of possible points = 350

The points scored by the student in homework = 7 + 8 + 7 + 5 + 8 = 35 points.

The scores of the student on the two exams = 81 + 80 = 161 points

So, the total points scored by the students = 35 + 161 = 196 points.

As it is given in the question that if the grade percentage is 0.9 or higher then the student will get an A, i.e;

If the total possible points are 350 points;

This means that the student must have to score 315 points to get an A grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 < 315, this means that it is not possible for the student to receive an A in the class.

Also, it is given in the question that if the grade percentage is between 0.8 and 0.9 the student will get a B, i.e, the student must obtain a minimum of 80% to get B grade.

If the total possible points are 350 points;

This means that the student must have to score a minimum of 280 points to get a B grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 > 280, this means that it is possible for the student to receive a B grade in the class.

Mathematics
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics

The answer is in the image

Mathematics

The solution is in the following image

Mathematics

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

=4300/3.3

=1303.03kg

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