09.06.2021

One prepaid cell phone company charges $0.029 per minute and a $2 monthly fee. another company charges $0.033 per minute with no monthly fee. for what number of minutes per month are the charges for the first company cheaper?

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30.05.2023, solved by verified expert
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For more than 500 minutes

Step-by-step explanation:

Let x be the number of minutes.

First company charges:

$0.029 per minute, then $0.029x for x minutes

and a $2 monthly fee.

In total, $(0.029x+2)

Second company charges:

$0.033 per minute, then $0.033x for x minutes

with no monthly fee.

If the charges for the first company are cheaper, then

One prepaid cell phone company charges <img src=

Multiply this inequality by 1,000:

One prepaid cell phone company charges <img src=

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Mathematics
Step-by-step answer
P Answered by PhD

For more than 500 minutes

Step-by-step explanation:

Let x be the number of minutes.

First company charges:

$0.029 per minute, then $0.029x for x minutes

and a $2 monthly fee.

In total, $(0.029x+2)

Second company charges:

$0.033 per minute, then $0.033x for x minutes

with no monthly fee.

If the charges for the first company are cheaper, then

0.029x+2

Multiply this inequality by 1,000:

29x+2,0002,000\\ \\4x2,000\\ \\x500

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
Step-by-step answer
P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD
The answer is in the image 

The answer is in the image 

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

The solution is given in the image below

The solution is given in the image below
Mathematics
Step-by-step answer
P Answered by PhD

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years

Mathematics
Step-by-step answer
P Answered by PhD

The solution is given below

The solution is given below

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