Mathematics: What is the square root of 7?

What is the square root of 7?, №17886128, 02.06.2020 01:50

Mathematics

Jana is ordering a list of numbers from least to greatest. StartRoot 7 squared EndRoot, StartRoot 7 EndRoot, Four-fifths, StartRoot 0.8 EndRoot, (StartRoot 5 EndRoot) Squared Which statement can be used to create her list? StartRoot 0.8 EndRoot is less than Four-fifths because 0.8 = four-fifths and the square root of a number less than 1 is less than the number itself. StartRoot 7 EndRoot is greater than StartRoot 7 squared EndRoot because StartRoot 7 squared EndRoot = 7 and the square root of a number greater than 1 is greater than the number

Step-by-step answer

P Answered by Specialist

25

The last list about root 7 being greater than 4/5

Step-by-step explanation:

The explanation is true for that one, all of the other ones have some issue.

Mathematics

Jana is ordering a list of numbers from least to greatest. StartRoot 7 squared EndRoot, StartRoot 7 EndRoot, Four-fifths, StartRoot 0.8 EndRoot, (StartRoot 5 EndRoot) Squared Which statement can be used to create her list? StartRoot 0.8 EndRoot is less than Four-fifths because 0.8 = four-fifths and the square root of a number less than 1 is less than the number itself. StartRoot 7 EndRoot is greater than StartRoot 7 squared EndRoot because StartRoot 7 squared EndRoot = 7 and the square root of a number greater than 1 is greater than the number

Step-by-step answer

P Answered by Master

60

The answer is D

Step-by-step explanation:

$\frac{4}{5}$ = 0.8

$\sqrt{7}$ = 2.64

2.64 > 0.8 because 2 is a whole number while 0.8 is a decimal

Mathematics

Which of the following statements is not true concerning the equation x^2 - c = 0 for c 0 A. A quadratic system in this form can always be solved by factoring. B. This equation is not considered to be a quadratic equation because it is not in the form ax^2 + bx + c = 0 C. The left-hand side of this equation is called a difference of two squares D. A quadratic equation in this form can always be solved using the square root property. Which of the following steps would not be necessary when using the square root property to solve a quadratic equation?

Step-by-step answer

P Answered by PhD

1

The correct option are;

1) D. A quadratic equation of this form can always be solved using the square root property

2) B. Isolate the quantity being squared

3) C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X so divide both sides by 2 before applying the square root property

Step-by-step explanation:

Where the quadratic equation is of the form x² = b, the square root property method can be used to solve the equation. Due to the nature of square roots, putting a plus-minus before the square root of the constant on the right hand side of the equation after taking the square roots of both sides of the equation, two answers are produced.

It is however to first isolate the term with the squared variable, after which the square root of both sides of the equation is taken.

Mathematics

Which of the following statements is not true concerning the equation x^2 - c = 0 for c 0 A. A quadratic system in this form can always be solved by factoring. B. This equation is not considered to be a quadratic equation because it is not in the form ax^2 + bx + c = 0 C. The left-hand side of this equation is called a difference of two squares D. A quadratic equation in this form can always be solved using the square root property. Which of the following steps would not be necessary when using the square root property to solve a quadratic equation?

Step-by-step answer

P Answered by PhD

1

The correct option are;

1) D. A quadratic equation of this form can always be solved using the square root property

2) B. Isolate the quantity being squared

3) C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X so divide both sides by 2 before applying the square root property

Step-by-step explanation:

Where the quadratic equation is of the form x² = b, the square root property method can be used to solve the equation. Due to the nature of square roots, putting a plus-minus before the square root of the constant on the right hand side of the equation after taking the square roots of both sides of the equation, two answers are produced.

It is however to first isolate the term with the squared variable, after which the square root of both sides of the equation is taken.

Mathematics

Need an answer fast sam said the square root of a rational number must be a rational number. jenna disagreed. she said that it is possible that the square root of a rational number can be irrational. who is correct and why? -jenna is correct because all square roots are irrational numbers. -sam is correct because all square roots of rational numbers are rational. an example is (square root of 121 = 11) -jenna is correct because not all square roots are rational. an example is (square root of 2 =1.414213) -sam is correct because the properties of

Step-by-step answer

P Answered by Specialist

57

C is correct because not all square roots are rational.

Mathematics

Need an answer fast sam said the square root of a rational number must be a rational number. jenna disagreed. she said that it is possible that the square root of a rational number can be irrational. who is correct and why? -jenna is correct because all square roots are irrational numbers. -sam is correct because all square roots of rational numbers are rational. an example is (square root of 121 = 11) -jenna is correct because not all square roots are rational. an example is (square root of 2 =1.414213) -sam is correct because the properties of

Step-by-step answer

P Answered by Master

57

C is correct because not all square roots are rational.

Mathematics

Question 1 solve for x using the quadratic formula: x2 − 6x + 9 = 0 x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x = 6 x = 3 x = 1 x = 0 question 2 solve: 49x2 − 60 = 0 round your answer to the nearest hundredth. x = 0 x = −3.32 and x = 3.32 x = −1.11 and x = 1.11 x = −0.82 and x = 0.82 question 3 when the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus

Step-by-step answer

P Answered by Master

Part 1) x=3

Part 2) x = −1.11 and x = 1.11

Part 3) 105

Part 4) a = −6, b = 9, c = −7

Part 5) x equals 5 plus or minus the square root of 33, all over 2

Part 6) In the procedure

Part 7) -0.55

Part 8) The denominator is 2

Part 9) a = −6, b = −8, c = 12

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -6x+9=0$

so

$a=1\\b=-6\\c=9$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(9)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{0}} {2}$

$x=\frac{6} {2}=3$

Part 2) in this problem we have

$49x^{2} -60=0$

so

$a=49\\b=0\\c=-60$

substitute in the formula

$x=\frac{0(+/-)\sqrt{0^{2}-4(49)(-60)}} {2(49)}$

$x=\frac{0(+/-)\sqrt{11,760}} {98}$

x=(+/-)1.11

Part 3) When the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r?

in this problem we have

$x^{2} -9x-6=0$

so

$a=1\\b=-9\\c=-6$

substitute in the formula

$x=\frac{-(-9)(+/-)\sqrt{-9^{2}-4(1)(-6)}} {2(1)}$

$x=\frac{9(+/-)\sqrt{105}} {2}$

therefore

r=105

Part 4) What are the values a, b, and c in the following quadratic equation?

−6x2 = −9x + 7

in this problem we have

$-6x^{2}=-9x+7$

$-6x^{2}+9x-7=0$

so

$a=-6\\b=9\\c=-7$

Part 5) Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0.

In this problem we have

$x^{2} -5x-2=0$

so

$a=1\\b=-5\\c=-2$

substitute in the formula

$x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{5(+/-)\sqrt{33}} {2}$

therefore

x equals 5 plus or minus the square root of 33, all over 2

Part 6) Quadratic Formula proof

we have

$ax^{2} +bx+c=0$

Divide both sides by a

$x^{2} +(b/a)x+(c/a)=0$

Complete the square

$x^{2} +(b/a)x=-(c/a)$

$x^{2} +\frac{b}{a}x+\frac{b^{2}}{4a^{2}} =-\frac{c}{a}+\frac{b^{2}}{4a^{2}}$

Rewrite the perfect square trinomial on the left side of the equation as a binomial squared

$(x+\frac{b}{2a})^{2}=-\frac{4ac}{a^{2}}+\frac{b^{2}}{4a^{2}}$

Find a common denominator on the right side of the equation

$(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}$

Take the square root of both sides of the equation

$(x+\frac{b}{2a})=(+/-)\sqrt{\frac{b^{2}-4ac}{4a^{2}}}$

Simplify the right side of the equation

$(x+\frac{b}{2a})=(+/-)\frac{\sqrt{b^{2}-4ac}}{2a}$

Subtract the quantity b over 2 times a from both sides of the equation

$x=-\frac{b}{2a}(+/-)\frac{\sqrt{b^{2}-4ac}}{2a}$

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 7) in this problem we have

$3x^{2} +45x+24=0$

so

$a=3\\b=45\\c=24$

substitute in the formula

$x=\frac{-(45)(+/-)\sqrt{45^{2}-4(3)(24)}} {2(3)}$

$x=\frac{-(45)(+/-)\sqrt{1,737}} {6}$

$x1=\frac{-(45)(+)\sqrt{1,737}} {6}=-0.55$

$x2=\frac{-(45)(-)\sqrt{1,737}} {6}=-14.45$

therefore

The other solution is

-0.55

Part 8) in this problem we have

$2x^{2} -8x+7=0$

so

$a=2\\b=-8\\c=7$

substitute in the formula

$x=\frac{-(-8)(+/-)\sqrt{-8^{2}-4(2)(7)}} {2(2)}$

$x=\frac{8(+/-)\sqrt{8}} {4}$

$x=\frac{8(+/-)2\sqrt{2}} {4}$

$x=\frac{4(+/-)\sqrt{2}} {2}$

therefore

The denominator is 2

Part 9) What are the values a, b, and c in the following quadratic equation?

−6x2 − 8x + 12

in this problem we have

$-6x^{2} -8x+12=0$

so

$a=-6\\b=-8\\c=12$

Mathematics

8.07a, part 1 1. find the vertex, focus, directrix, and focal width of the parabola. (1 point) negative 1 divided by 40 x squared equals y a) vertex: (0, 0); focus: (0, -10); directrix: y = 10; focal width: 160 b) vertex: (0, 0); focus: (-20, 0); directrix: x = 10; focal width: 160 c) vertex: (0, 0); focus: (0, -10); directrix: y = 10; focal width: 40 d) vertex: (0, 0); focus: (0, 10); directrix: y = -10; focal width: 10 2. find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2. a)y2 = -2x b) y2

Step-by-step answer

P Answered by PhD

41

Note: Please refer to the attached file for the explanation.

Answers:

1. None from the choices, it should be

Vertex: (0, 0); Focus: (0, -10); Directrix: y = 10; Focal width: 10

2. C) y equals negative 1 divided by 8 x squared

3. D) x equals negative 1 divided by 32 y squared

4. C) x2 = -5.3y

5. C) Center: (0, 0); Vertices: (0, -15), (0, 15); Foci: (0, -12), (0, 12)

6. None from the choices, it should be

Center: (0, 0); Vertices: the point negative two square root two comma zero and the point 2 square root two comma zero; Foci: Ordered pair negative square root 6 comma zero and ordered pair square root 6 comma zero

7. B) A vertical ellipse is shown on the coordinate plane centered at the origin with vertices at the point zero comma seven and zero comma negative seven. The minor axis has endpoints at negative six comma zero and six comma zero.

8. D) x squared divided by 16 plus y squared divided by 25 equals 1

9. D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)

Mathematics

I really need help here I am super confused Which of the following steps can be performed so that the square root property may easily be applied to 2x^2=16?(1 point) The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is 16, so divide both sides by 2 before applying the square root property. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.

Step-by-step answer

P Answered by PhD

2

The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.

Step-by-step explanation:

In the above question, we are given the expression: 2x^2=16 and we are asked the proper way to apply the square root property.

2x² = 16 is an algebraic equation

To apply square root property to an expression, there must be only one quantity that is squared.

Step 1

We divide both sides by 2

This is because we have to first eliminate the coefficient of x

2x²/2 = 16/2

x² = 8

Step 2

Now that we have eliminated the coefficient of x², we can apply the square root property now because x is the only quantity that is squared.

√x² = √8

x = √8

Therefore, Option 2 which says: "The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property." is the correct option

Mathematics

8.07a, part 1 1. find the vertex, focus, directrix, and focal width of the parabola. (1 point) negative 1 divided by 40 x squared equals y a) vertex: (0, 0); focus: (0, -10); directrix: y = 10; focal width: 160 b) vertex: (0, 0); focus: (-20, 0); directrix: x = 10; focal width: 160 c) vertex: (0, 0); focus: (0, -10); directrix: y = 10; focal width: 40 d) vertex: (0, 0); focus: (0, 10); directrix: y = -10; focal width: 10 2. find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2. a)y2 = -2x b) y2

Step-by-step answer

P Answered by PhD

41

Note: Please refer to the attached file for the explanation.

Answers:

1. None from the choices, it should be

Vertex: (0, 0); Focus: (0, -10); Directrix: y = 10; Focal width: 10

2. C) y equals negative 1 divided by 8 x squared

3. D) x equals negative 1 divided by 32 y squared

4. C) x2 = -5.3y

5. C) Center: (0, 0); Vertices: (0, -15), (0, 15); Foci: (0, -12), (0, 12)

6. None from the choices, it should be

Center: (0, 0); Vertices: the point negative two square root two comma zero and the point 2 square root two comma zero; Foci: Ordered pair negative square root 6 comma zero and ordered pair square root 6 comma zero

7. B) A vertical ellipse is shown on the coordinate plane centered at the origin with vertices at the point zero comma seven and zero comma negative seven. The minor axis has endpoints at negative six comma zero and six comma zero.

8. D) x squared divided by 16 plus y squared divided by 25 equals 1

9. D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)

What is the square root of 7?

Step-by-step answer

Faq

Try asking the Studen AI a question.