What is the probability of rolling a number cube, №17886206, 13.04.2021 17:09

Mathematics

What is the probability of rolling a number cube two times and getting 4 each time? A. 2.8% B. 11% C. 44% D. 67%

Step-by-step answer

P Answered by PhD

Step-by-step explanation:

(1/6)(1/6)=1/36

2.777 rounded to 2.8%

Mathematics

Which of the following is the probability of rolling an even number on a 6-sided number cube and flipping a coin twice and getting two heads in a row? 1/2 1/8 1/4 1/3

Step-by-step answer

P Answered by Specialist

21

The answer would be 1/8. It makes the most sense. sorry i just need enough characters to answer the question.

Mathematics

Which of the following is the probability of rolling an even number on a 6-sided number cube and flipping a coin twice and getting two heads in a row? 1/2 1/8 1/4 1/3

Step-by-step answer

P Answered by Master

21

The answer would be 1/8. It makes the most sense. sorry i just need enough characters to answer the question.

Mathematics

An experiment consists of rolling two fair number cubes. what is the probability that the sum of the two numbers will be 8? express your answer as a fraction in simplest form. ⓐ- 5/36 ⓑ- 1/9 ⓒ- 36/5 ⓓ- 31/36 i know that the answer is a, they give us the answer but we need to provide work and i don t understand how we get the answer.

Step-by-step answer

P Answered by Master

29

2-6, 3-5, 4-4, 5-3, 6-2 are all the possible number permutaions that the sum is 8 on two fair dice. There are only 5 ways to make 8. the total number of possible number permutations you would get by squaring 6 to get 36. your answer would then be A. 5/36

Mathematics

An experiment consists of rolling two fair number cubes. what is the probability that the sum of the two numbers will be 8? express your answer as a fraction in simplest form. ⓐ- 5/36 ⓑ- 1/9 ⓒ- 36/5 ⓓ- 31/36 i know that the answer is a, they give us the answer but we need to provide work and i don t understand how we get the answer.

Step-by-step answer

P Answered by Specialist

29

2-6, 3-5, 4-4, 5-3, 6-2 are all the possible number permutaions that the sum is 8 on two fair dice. There are only 5 ways to make 8. the total number of possible number permutations you would get by squaring 6 to get 36. your answer would then be A. 5/36

Mathematics

Robin tosses two number cubes 100 times and gets a pair of 3s 18 times. what is the experimental probability that she will roll a pair of 3s on her next toss? a) 3: 100 b) 18: 50 c) 9: 50 d) 1: 21

Step-by-step answer

P Answered by Master

32

The answer would be C: 9:50
Robin had tossed a pair of 3s 18 times out of 100 trials. Since the formula for experimental probability is number of desirable outcomes:total trials, the experimental probability would results to be 18:100 → 9:50.

Mathematics

Robin tosses two number cubes 100 times and gets a pair of 3s 18 times. what is the experimental probability that she will roll a pair of 3s on her next toss? a) 3: 100 b) 18: 50 c) 9: 50 d) 1: 21

Step-by-step answer

P Answered by Specialist

32

The answer would be C: 9:50
Robin had tossed a pair of 3s 18 times out of 100 trials. Since the formula for experimental probability is number of desirable outcomes:total trials, the experimental probability would results to be 18:100 → 9:50.

Mathematics

Will award 50 points & the brainiest answer 1. one spinner has three equally sized sectors labeled r, s, and t. a second spinner has two equally sized sectors labeled 3 and 5. each spinner is spun once. what is the sample space of outcomes? {rst, 35} {rr, rs, rt, sr, ss, st, tr, ts, tt, 33, 35, 53, 55} {r, s, t, 3, 5} {r3, r5, s3, s5, t3, t5} (my guess) 2. a spinner with three equal sectors is spun three times. what is the number of possible outcomes? 3 6 9 27 3. there are two spinners. the first spinner has three equal sectors labeled 1, 2

Step-by-step answer

P Answered by Specialist

1.
You are right, answer D.

2.
First spin = 3 possible outcomes
Second spin = 3 possible outcomes
Third spin = 3 possible outcomes
so there will be 3*3*3 = 27 possible outcomes.
Answer D.

3.
Not 1 on the first spinner (so 2 or 3) = 2 possible outcomes
4 on the second spinner = 1 possible outcome
so there will be 2*1 = 2 possible outcomes.
Answer A.

4.
Answer A. (A six-sided number cube is rolled and a coin is flipped.)
and
Answer B. (Two spinners are spun at the same time.)

5.
First we have 10 slips of paper and there are 3 slips with number that is a multiple of 3 (3, 6 and 9). So:

P(multiple of 3) = 3/10

Now, we have only 9 slips and there are 2 with number that is multiple of 4 (4 and 8) so:

P(multiple of 4) = 2/9

And finally:

P(multiple of 3 and then a multiple of 4) = P(multiple of 3) * P(multiple of 4) =
=3/10 * 2/9 = 1/15
Answer A.

6.
We have 8 possible outcomes but only 4 even (2, 4, 6 and 8), so

P(even number on the first spin) = 4/8 = 1/2

The second spin is the same as the first one

P(even number on the second spin) = 4/8 = 1/2

And

P(even and even) = P(first even) * P(second even) = 1/2 * 1/2 = 1/4
Answer A.

7.
∩ means AND

$P(A)\cdot P(B) = 0.2\cdot0.3=0.06=P(A\cap B)$

so P(A)*P(B) = P(A and B)
A and B are independent.

8.
Let B - like brownies and C - like cupcakes
From the table we know, that (total number):

$P(B)=0.3\\P(C)=0.5\\P(B\cap C)=0.15$

Calculete:

$P(B|C)=\dfrac{P(B\cap C)}{P(C)}=\dfrac{0.15}{0.5}=0.3=P(B)$

and

$P(C|B)=\dfrac{P(B\cap C)}{P(B)}=\dfrac{0.15}{0.3}=0.5=P(C)$

So P(B|C) = P(B) and P(C|B) = P(C) and B, C are independent.
Answer A.

9.
Answer A.

10.
Let G₁ - first ball is green and G₂ - second ball is green. We know that:

$P(G_1\cap G_2)=\dfrac{11}{50}\qquad\qquad P(G_1)=\dfrac{12}{25}$

so:

$P(G_2|G_1)=\dfrac{P(G_1\cap G_2)}{P(G_1)}=\dfrac{\frac{11}{50}}{\frac{12}{25}}=\dfrac{11\cdot25}{50\cdot12}=\boxed{\dfrac{11}{24}}$

Answer B.

11.
All possible outcomes = 8
Number less than 4 = {1, 2, 3}
Multiple of 4 = {4, 8}
There is "number less than 4 OR a multiple of 4", so we take all numbers from both sets = {1, 2, 3, 4, 8} (5 outcomes)

P(less than 4 or a multiple of 4) = 5/8
Answer B.

12.
All possible outcomes = 10
Odd number = {1, 3, 5, 7, 9}
Number greater than 4 = {5, 6, 7, 8, 9, 10}
There is "an odd number AND a number greater than 4" so we take only numbers that are in both sets = {5, 7, 9} (3 outcomes)

P(an odd number and a number greater than 4) = 3/10
Answer C.

Mathematics

Will award 50 points & the brainiest answer 1. one spinner has three equally sized sectors labeled r, s, and t. a second spinner has two equally sized sectors labeled 3 and 5. each spinner is spun once. what is the sample space of outcomes? {rst, 35} {rr, rs, rt, sr, ss, st, tr, ts, tt, 33, 35, 53, 55} {r, s, t, 3, 5} {r3, r5, s3, s5, t3, t5} (my guess) 2. a spinner with three equal sectors is spun three times. what is the number of possible outcomes? 3 6 9 27 3. there are two spinners. the first spinner has three equal sectors labeled 1, 2

Step-by-step answer

P Answered by Specialist

1.
You are right, answer D.

2.
First spin = 3 possible outcomes
Second spin = 3 possible outcomes
Third spin = 3 possible outcomes
so there will be 3*3*3 = 27 possible outcomes.
Answer D.

3.
Not 1 on the first spinner (so 2 or 3) = 2 possible outcomes
4 on the second spinner = 1 possible outcome
so there will be 2*1 = 2 possible outcomes.
Answer A.

4.
Answer A. (A six-sided number cube is rolled and a coin is flipped.)
and
Answer B. (Two spinners are spun at the same time.)

5.
First we have 10 slips of paper and there are 3 slips with number that is a multiple of 3 (3, 6 and 9). So:

P(multiple of 3) = 3/10

Now, we have only 9 slips and there are 2 with number that is multiple of 4 (4 and 8) so:

P(multiple of 4) = 2/9

And finally:

P(multiple of 3 and then a multiple of 4) = P(multiple of 3) * P(multiple of 4) =
=3/10 * 2/9 = 1/15
Answer A.

6.
We have 8 possible outcomes but only 4 even (2, 4, 6 and 8), so

P(even number on the first spin) = 4/8 = 1/2

The second spin is the same as the first one

P(even number on the second spin) = 4/8 = 1/2

And

P(even and even) = P(first even) * P(second even) = 1/2 * 1/2 = 1/4
Answer A.

7.
∩ means AND

$P(A)\cdot P(B) = 0.2\cdot0.3=0.06=P(A\cap B)$

so P(A)*P(B) = P(A and B)
A and B are independent.

8.
Let B - like brownies and C - like cupcakes
From the table we know, that (total number):

$P(B)=0.3\\P(C)=0.5\\P(B\cap C)=0.15$

Calculete:

$P(B|C)=\dfrac{P(B\cap C)}{P(C)}=\dfrac{0.15}{0.5}=0.3=P(B)$

and

$P(C|B)=\dfrac{P(B\cap C)}{P(B)}=\dfrac{0.15}{0.3}=0.5=P(C)$

So P(B|C) = P(B) and P(C|B) = P(C) and B, C are independent.
Answer A.

9.
Answer A.

10.
Let G₁ - first ball is green and G₂ - second ball is green. We know that:

$P(G_1\cap G_2)=\dfrac{11}{50}\qquad\qquad P(G_1)=\dfrac{12}{25}$

so:

$P(G_2|G_1)=\dfrac{P(G_1\cap G_2)}{P(G_1)}=\dfrac{\frac{11}{50}}{\frac{12}{25}}=\dfrac{11\cdot25}{50\cdot12}=\boxed{\dfrac{11}{24}}$

Answer B.

11.
All possible outcomes = 8
Number less than 4 = {1, 2, 3}
Multiple of 4 = {4, 8}
There is "number less than 4 OR a multiple of 4", so we take all numbers from both sets = {1, 2, 3, 4, 8} (5 outcomes)

P(less than 4 or a multiple of 4) = 5/8
Answer B.

12.
All possible outcomes = 10
Odd number = {1, 3, 5, 7, 9}
Number greater than 4 = {5, 6, 7, 8, 9, 10}
There is "an odd number AND a number greater than 4" so we take only numbers that are in both sets = {5, 7, 9} (3 outcomes)

P(an odd number and a number greater than 4) = 3/10
Answer C.

Mathematics

Latoya is using two number cubes during a probability experiment. The faces of each cube are numbered 1 through 6. What is the probability that Latoya will get an outcome of a number less than 3 on the top of each cube on one roll of the pair of cubes?

Step-by-step answer

P Answered by PhD

0.1111 = 11.11%

Step-by-step explanation:

Each cube is numbered from 1 to 6, so each number has 1/6 chance of being in the top.

To get a number less than 3 (that is, 1 or 2), we have 2 options among 6, so the probability is 2/6 = 1/3.

The probability of having a number less than 3 on the top of each cube is the product of the probability for each cube, so we have that:

P = (1/3) * (1/3) = 1/9 = 0.1111 = 11.11%

What is the probability of rolling a number cube two times and getting 4 each time? A. 2.8%
B. 11%
C. 44%
D. 67%

Step-by-step answer

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