What is 0.4 × 16.21 = ?, №17886238, 04.04.2021 22:45

Mathematics

Step-by-step answer

P Answered by PhD

2

6.484

Explanation: used a calculator

Mathematics

1. write a ratio and a percent for the shaded area. a 4x4 grid with 5 blocks shaded (1 point) one over five, 25% five sixteenths, 31.25% one over four, 20% one over four, 25% 2. model 32% on a 5 × 5 grid. (1 point) a 5 by 5 grid has 8 cells shaded. a 5 by 5 grid has 6 cells shaded. a 5 by 5 grid has 7 cells shaded. a 5 by 5 grid has 20 cells shaded. 3. write the ratio as a percent. in a car dealership’s lot, startfraction 6 over 24 endfraction of the cars are silver. (1 point) 0.2 0.25 0.26 0.28 4. write the decimal as a percent. 0.09 (1 point)

Step-by-step answer

P Answered by PhD

31

Here are the answers to the following questions:

1. Write a ratio and a percent for the shaded area.
a 4x4 grid with 5 blocks shaded (1 point)
five sixteenths

2. Model 32% on a 5 × 5 grid. (1 point)
a 5 by 5 grid has 8 cells shaded.

3. Write the ratio as a percent. In a car dealership’s lot, 6 Over 24 EndFraction of the cars are silver. (1 point)
0.25

4. Write the decimal as a percent. 0.09 (1 point) 0.0009

5. Write the percent as a decimal. 37.1% (1 point) 0.371

6. Order from least to greatest. 0.4, four-ninths, 40.5%, eleven-twenty-fifths
0.4, 0.44, 0.405, 0.44
(1 point)
0.4, 40.5%, four-ninths, eleven-twenty-fifths

7. In a candy bar, 165 calories are from sugar. There are 250 calories in the candy bar. What percent of the calories are from sugar? (1 point)
66

For questions 8 and 9, write the fraction as a percent. If necessary, round to the nearest tenth of a percent.

8. 9/15 (1 point) 0.6

9. Write the fraction as a percent. If necessary, round to the nearest tenth of a percent.
4 one fifth (1 point) 0.042

10. Write the percent as a decimal and as a fraction.
215% (1 point) 21.5; 211/2

11. The science club sold 25 T-shirts last week and 18 T-shirts this week. What is the percentage of decrease in the number of T-shirts sold? (1 point)
0.28

12. On a factory floor, 20 of every 170 toy robots are defective. What percent of the toy robots are defective? Round your answer to the nearest hundredth. (1 point)
0.1176

13. A new law requires that 12% of an individual’s income be invested in the stock market. Your accounts show that you need to put $420 in the stock market this year. How much did you earn this year? (1 point)
5040

14. 20% of what number is 47? (1 point) 235

15. Estimate a 15% tip for a meal that cost $26.80. (1 point)
4.05

16. You and some friends rent a limousine for a formal reception. The bill for the evening is $53.00. A tax of 6% will be added to your total, and you want to tip the chauffeur for his excellent driving. You decide to leave him a tip that is 20% of the bill before tax is added. How much will be paid in total? (1 point)
66.78

17. Find the percent of markup. Round to the nearest tenth.
$37.00 to $49.00 (1 point) 0.245

Mathematics

1. write a ratio and a percent for the shaded area. a 4x4 grid with 5 blocks shaded (1 point) one over five, 25% five sixteenths, 31.25% one over four, 20% one over four, 25% 2. model 32% on a 5 × 5 grid. (1 point) a 5 by 5 grid has 8 cells shaded. a 5 by 5 grid has 6 cells shaded. a 5 by 5 grid has 7 cells shaded. a 5 by 5 grid has 20 cells shaded. 3. write the ratio as a percent. in a car dealership’s lot, startfraction 6 over 24 endfraction of the cars are silver. (1 point) 0.2 0.25 0.26 0.28 4. write the decimal as a percent. 0.09 (1 point)

Step-by-step answer

P Answered by PhD

31

Here are the answers to the following questions:

1. Write a ratio and a percent for the shaded area.
a 4x4 grid with 5 blocks shaded (1 point)
five sixteenths

2. Model 32% on a 5 × 5 grid. (1 point)
a 5 by 5 grid has 8 cells shaded.

3. Write the ratio as a percent. In a car dealership’s lot, 6 Over 24 EndFraction of the cars are silver. (1 point)
0.25

4. Write the decimal as a percent. 0.09 (1 point) 0.0009

5. Write the percent as a decimal. 37.1% (1 point) 0.371

6. Order from least to greatest. 0.4, four-ninths, 40.5%, eleven-twenty-fifths
0.4, 0.44, 0.405, 0.44
(1 point)
0.4, 40.5%, four-ninths, eleven-twenty-fifths

7. In a candy bar, 165 calories are from sugar. There are 250 calories in the candy bar. What percent of the calories are from sugar? (1 point)
66

For questions 8 and 9, write the fraction as a percent. If necessary, round to the nearest tenth of a percent.

8. 9/15 (1 point) 0.6

9. Write the fraction as a percent. If necessary, round to the nearest tenth of a percent.
4 one fifth (1 point) 0.042

10. Write the percent as a decimal and as a fraction.
215% (1 point) 21.5; 211/2

11. The science club sold 25 T-shirts last week and 18 T-shirts this week. What is the percentage of decrease in the number of T-shirts sold? (1 point)
0.28

12. On a factory floor, 20 of every 170 toy robots are defective. What percent of the toy robots are defective? Round your answer to the nearest hundredth. (1 point)
0.1176

13. A new law requires that 12% of an individual’s income be invested in the stock market. Your accounts show that you need to put $420 in the stock market this year. How much did you earn this year? (1 point)
5040

14. 20% of what number is 47? (1 point) 235

15. Estimate a 15% tip for a meal that cost $26.80. (1 point)
4.05

16. You and some friends rent a limousine for a formal reception. The bill for the evening is $53.00. A tax of 6% will be added to your total, and you want to tip the chauffeur for his excellent driving. You decide to leave him a tip that is 20% of the bill before tax is added. How much will be paid in total? (1 point)
66.78

17. Find the percent of markup. Round to the nearest tenth.
$37.00 to $49.00 (1 point) 0.245

Physics

14. a block rests on a frictionless table on earth. after a 20-n horizontal force is applied to the block, it accelerates at 3.9 m/s2. then the block and table are carried to the moon, where the acceleration due to gravity is 1.62 m/s2. a horizontal force of 10 n is then applied to the block. what is the acceleration? a. 1.8 m/s2 b. 2.5 m/s2 c. 2.1 m/s2 d. 2.3 m/s2 e. 2.0 m/s2 15. workers are trying to free an suv stuck in the mud. to move the vehicle, they use three ropes held parallel to the ground, producing the force vectors shown in the figure.

Step-by-step answer

P Answered by PhD

5

14. E 2.0 m/s^2

Initially, a 20 N force is applied to the block, so it has an acceleration of 3.9 m/s^2. According to Newton's law, the mass of the block is:

$m=\frac{F}{a}=\frac{20 N}{3.9 m/s^2}=5.13 kg$

In the second situation, a force of 10 N is applied to the block. Since the mass is still the same, the acceleration now is:

$a=\frac{F}{m}=\frac{10 N}{5.13 kg}=1.95 m/s^2$

So, approximately 2.0 m/s^2.

15. C. 866 N at 78.1° counterclockwise to the x-axis

Resultant along the x- and y-axis:

$R_x = (985 N)(cos 31^{\circ})-(788 N)(sin 32^{\circ})-(411 N)(cos 53^{\circ})=179.4 N$

$R_y = (985 N)(sin 31^{\circ})+(788 N)(cos 32^{\circ})-(411 N)(sin 53^{\circ})=847.3 N$

Magnitude and direction of the resultant:

$R=\sqrt{R_x^2+R_y^2}=\sqrt{(179.4 N)^2+(847.3 N)^2}=866.0 N$

$\theta=arctan(\frac{R_y}{R_x})=\arctan(\frac{847.3 N}{179.4 N})=78.1^{\circ}$

16. D. 1720 N

Since the sphere is suspended, it is in equilibrium, therefore the tension in the chain is equal to the weight of the sphere attached to it, therefore:

T=mg=(175 kg)(9.81 m/s^2)=1720 N

17. C. A

This arrangement generates the largest tension in the chain, because in all other arrangements the weight of the object is split between the two chains, while in this case all the weight is hold by one chain, therefore the tension in this case is larger.

18. Straight path

The gravity "holds" the planets keeping them in a circular orbit. If we remove gravity, the planets would continue in a straight path with constant speed, because now there are no more forces acting on it, so by inertia they will continue their uniform motion with constant speed.

19. B. 1.6 × 104 N

First we can find the deceleration of the car by using the SUVAT equation:

v^2 -u^2 =2aS

where v=0 m/s, u=2 m/s, and S=15 cm=0.15 m. Re-arranging, we have

$a=\frac{-u^2}{2S}=\frac{-(2 m/s)^2}{2(0.15 m)}=-13.3 m/s^2$

And now we can calculate the average force exerted on the car, by using Newton's second law:

$F=ma=(1200 kg)(-13.3 m/s^2)=-15960 N=-1.6 \cdot 10^4 N$

(the negative sign means that the force's direction is opposite to the motion of the car)

20. A. magnetism

Magnetism is part of the electromagnetic force, which is one of the fundamental forces which act also through empty space. All the other forces need some object in order to act.

21. E. 45 N

The magnitude of the force in link A is equal to the weight of the rod plus the weight of the lower block, therefore:

W=(m_1 + m_2)g=(0.6 kg+4.0 kg)(9.8 m/s^2)=45 N

22. C. on Earth at sea level

The weight of the bowling ball is given by: W=mg , where m is the mass of the ball and g is the acceleration due to gravity. The value of g increases when moving from the Earth's center to the Earth's surface, then decreases when moving far from the surface, so the point where g is greatest is at sea level, where it is 9.81 m/s^2. On the surface of the Moon, g is much smaller (about 1/6 of the value on Earth).

23. A. 0.5 m/s2

The acceleration of the block is given by Newton's second law:

$a=\frac{F}{m}=\frac{20 N}{40 kg}=0.5 m/s^2$

24. D. Both forces are equal in magnitude but opposite in direction.

According to Newton's third law: if an object A exerts a force on an object B, then object B exerts a force equal and opposite on object B. In this case, objects A and B are the bat and the baseball, therefore the two forces are equal in magnitude and opposite in direction.

25. B. 2940 N

The mass of the boulder is equal to its weight divided by the acceleration of gravity (9.81 m/s^2):

$m=\frac{W}{g}=\frac{2400 N}{9.81 m/s^2}=245 kg$

So now we can calculate the force needed to accelerate the boulder to 12.0 m/s^2:

F=ma=(245 kg)(12.0 m/s^2)=2940 N

26. D. 32.2 N

The weight of the object on Mercury is given by:

W=mg=(8.69 kg)(3.71 m/s^2)=32.2 N

Physics

14. a block rests on a frictionless table on earth. after a 20-n horizontal force is applied to the block, it accelerates at 3.9 m/s2. then the block and table are carried to the moon, where the acceleration due to gravity is 1.62 m/s2. a horizontal force of 10 n is then applied to the block. what is the acceleration? a. 1.8 m/s2 b. 2.5 m/s2 c. 2.1 m/s2 d. 2.3 m/s2 e. 2.0 m/s2 15. workers are trying to free an suv stuck in the mud. to move the vehicle, they use three ropes held parallel to the ground, producing the force vectors shown in the figure.

Step-by-step answer

P Answered by PhD

5

14. E 2.0 m/s^2

Initially, a 20 N force is applied to the block, so it has an acceleration of 3.9 m/s^2. According to Newton's law, the mass of the block is:

$m=\frac{F}{a}=\frac{20 N}{3.9 m/s^2}=5.13 kg$

In the second situation, a force of 10 N is applied to the block. Since the mass is still the same, the acceleration now is:

$a=\frac{F}{m}=\frac{10 N}{5.13 kg}=1.95 m/s^2$

So, approximately 2.0 m/s^2.

15. C. 866 N at 78.1° counterclockwise to the x-axis

Resultant along the x- and y-axis:

$R_x = (985 N)(cos 31^{\circ})-(788 N)(sin 32^{\circ})-(411 N)(cos 53^{\circ})=179.4 N$

$R_y = (985 N)(sin 31^{\circ})+(788 N)(cos 32^{\circ})-(411 N)(sin 53^{\circ})=847.3 N$

Magnitude and direction of the resultant:

$R=\sqrt{R_x^2+R_y^2}=\sqrt{(179.4 N)^2+(847.3 N)^2}=866.0 N$

$\theta=arctan(\frac{R_y}{R_x})=\arctan(\frac{847.3 N}{179.4 N})=78.1^{\circ}$

16. D. 1720 N

Since the sphere is suspended, it is in equilibrium, therefore the tension in the chain is equal to the weight of the sphere attached to it, therefore:

T=mg=(175 kg)(9.81 m/s^2)=1720 N

17. C. A

This arrangement generates the largest tension in the chain, because in all other arrangements the weight of the object is split between the two chains, while in this case all the weight is hold by one chain, therefore the tension in this case is larger.

18. Straight path

The gravity "holds" the planets keeping them in a circular orbit. If we remove gravity, the planets would continue in a straight path with constant speed, because now there are no more forces acting on it, so by inertia they will continue their uniform motion with constant speed.

19. B. 1.6 × 104 N

First we can find the deceleration of the car by using the SUVAT equation:

v^2 -u^2 =2aS

where v=0 m/s, u=2 m/s, and S=15 cm=0.15 m. Re-arranging, we have

$a=\frac{-u^2}{2S}=\frac{-(2 m/s)^2}{2(0.15 m)}=-13.3 m/s^2$

And now we can calculate the average force exerted on the car, by using Newton's second law:

$F=ma=(1200 kg)(-13.3 m/s^2)=-15960 N=-1.6 \cdot 10^4 N$

(the negative sign means that the force's direction is opposite to the motion of the car)

20. A. magnetism

Magnetism is part of the electromagnetic force, which is one of the fundamental forces which act also through empty space. All the other forces need some object in order to act.

21. E. 45 N

The magnitude of the force in link A is equal to the weight of the rod plus the weight of the lower block, therefore:

W=(m_1 + m_2)g=(0.6 kg+4.0 kg)(9.8 m/s^2)=45 N

22. C. on Earth at sea level

The weight of the bowling ball is given by: W=mg , where m is the mass of the ball and g is the acceleration due to gravity. The value of g increases when moving from the Earth's center to the Earth's surface, then decreases when moving far from the surface, so the point where g is greatest is at sea level, where it is 9.81 m/s^2. On the surface of the Moon, g is much smaller (about 1/6 of the value on Earth).

23. A. 0.5 m/s2

The acceleration of the block is given by Newton's second law:

$a=\frac{F}{m}=\frac{20 N}{40 kg}=0.5 m/s^2$

24. D. Both forces are equal in magnitude but opposite in direction.

According to Newton's third law: if an object A exerts a force on an object B, then object B exerts a force equal and opposite on object B. In this case, objects A and B are the bat and the baseball, therefore the two forces are equal in magnitude and opposite in direction.

25. B. 2940 N

The mass of the boulder is equal to its weight divided by the acceleration of gravity (9.81 m/s^2):

$m=\frac{W}{g}=\frac{2400 N}{9.81 m/s^2}=245 kg$

So now we can calculate the force needed to accelerate the boulder to 12.0 m/s^2:

F=ma=(245 kg)(12.0 m/s^2)=2940 N

26. D. 32.2 N

The weight of the object on Mercury is given by:

W=mg=(8.69 kg)(3.71 m/s^2)=32.2 N

Mathematics

1. the property measures as follows: north property line = 766.0 feet east property line = 361.5 feet south property line = 738.67 feet west property line = 370.0 feet a. determine the total linear feet of the perimeter of the property. b. determine the combined east and west property line length. 2. a delivery of lumber is made that includes 31,368 linear feet of 2x4, df #2. the load also includes some 2x6, df #2. the total linear feet of lumber delivered is 104,572 linear feet. determine the quantity of 2x6 delivered. 3. calculate the following.

Step-by-step answer

P Answered by PhD

1. A. Total linear feet of the perimeter = 2,236.18 lf : add all the property line to get the linear feet of the perimeter.
B. Combined east and west = 731.5 lf : add the east and west property line.

2. The quantity of 2X6 delivered = 73,204 lf : deduct the lf of 2X4 from the total linear feet of lumber that was delivered.

3. A. 26 7/16 : add all fractions together
B. 11 : deduct the following fractions from 52 7/8
C. -35.34 : follow MDAS, add first before subtracting 90.99 and 200.17

4. A. 5/8 or 0.625
B. 29/118 or 0.2458 : since there are no parentheses in the equation, we will follow the MDAS rule. So we'll first multiply then divide.
C. 12.9629... cu ft or 0.4801097393... cu yd

5. A. 32,585' 0" : to get the area, multiply the given measurements
B. 3,027.15: convert ft^2 to m^2 (1 ft2 = 0.0929m2)

6. A. 38 : add both values
B. 452 : add all sides (161 + 161 + 65 + 65)
C. 766’ + 738.67’=1504.67’x 370’= 556727.9 / 2= 278,363.95
D. Using East property line = 361.5 feet 361.5*xSouth property line = 738.67 feet x 6= 1,602,175.23 yd3
1. the property measures as follows: north property line = 766.0 feet east property line = 361.5 f

1. the property measures as follows: north property line = 766.0 feet east property line = 361.5 f

Mathematics

1. the property measures as follows: north property line = 766.0 feet east property line = 361.5 feet south property line = 738.67 feet west property line = 370.0 feet a. determine the total linear feet of the perimeter of the property. b. determine the combined east and west property line length. 2. a delivery of lumber is made that includes 31,368 linear feet of 2x4, df #2. the load also includes some 2x6, df #2. the total linear feet of lumber delivered is 104,572 linear feet. determine the quantity of 2x6 delivered. 3. calculate the following.

Step-by-step answer

P Answered by PhD

1. A. Total linear feet of the perimeter = 2,236.18 lf : add all the property line to get the linear feet of the perimeter.
B. Combined east and west = 731.5 lf : add the east and west property line.

2. The quantity of 2X6 delivered = 73,204 lf : deduct the lf of 2X4 from the total linear feet of lumber that was delivered.

3. A. 26 7/16 : add all fractions together
B. 11 : deduct the following fractions from 52 7/8
C. -35.34 : follow MDAS, add first before subtracting 90.99 and 200.17

4. A. 5/8 or 0.625
B. 29/118 or 0.2458 : since there are no parentheses in the equation, we will follow the MDAS rule. So we'll first multiply then divide.
C. 12.9629... cu ft or 0.4801097393... cu yd

5. A. 32,585' 0" : to get the area, multiply the given measurements
B. 3,027.15: convert ft^2 to m^2 (1 ft2 = 0.0929m2)

6. A. 38 : add both values
B. 452 : add all sides (161 + 161 + 65 + 65)
C. 766’ + 738.67’=1504.67’x 370’= 556727.9 / 2= 278,363.95
D. Using East property line = 361.5 feet 361.5*xSouth property line = 738.67 feet x 6= 1,602,175.23 yd3
1. the property measures as follows: north property line = 766.0 feet east property line = 361.5 f

Mathematics

PLEASE HELP I LL GIVE BRAINLIEST According to the Census Bureau, in 2014 California had an estimated population of 3.88 × 107 and Wyoming had a population of 5.84 × 105. Complete the following sentences. 3.8216 × 107 0.38216 × 107 3.8216 × 106 38.216 × 107 0.66 × 101 66.4 × 101 6.64 × 101 The population of California is more than the population of Wyoming Alternatively, the population of California is times the population of Wyoming.

Step-by-step answer

P Answered by Master

The population of California is $3.3216 * 10^{7}$ more than the population of Wyoming.

Alternatively, the population of California is $6.64 * 10^{1}$ times the population of Wyoming.

Step-by-step explanation:

The first part is to take the numbers out of the scientific notation. The estimated population of California is 38,800,000, and the population of Wyoming is 584,000.

Not that we've done that, let's start with the first part of the problem.

"The population of California is __________ more than the population of Wyoming."

This is a statement of subtraction, because it's not asking how many TIMES more. So, we subtract Wyoming's population from California's population.

38,800,000 - 584,000 = 38,216,000.

Putting that number into scientific notation is easy: move the decimal to the place in the number where there will only be one number in front of the decimal: 3.3216. How many number slots until you have only one number in front of the decimal? 7. So, we know that the power of 10 is going to be 7. So, the first part of the question answers to:

$3.8216 * 10^{7} .$

Now for the second part.

"Alternatively, the population of California is _________ times the population of Wyoming."

This is a problem of division. The question is asking us to divide California's population by Wyoming's population.

$\frac{38,800,000}{584,000} = 0.664383562 * 10^{2} .$

We need to have one number in front of the decimal point, so we move it behind the first 6, giving us 6.64. Because we did this, we need to bump the exponent from 2 to 1, leaving us with:

$6.64 * 10^{1}.$

So, the answer to the question is:

1. $3.8216 * 10^{7}.$

2. $6.64 * 10^{1}.$

Hope this helped you, and I hope you get a perfect score!! :)

Mathematics

PLEASE HELP I LL GIVE BRAINLIEST According to the Census Bureau, in 2014 California had an estimated population of 3.88 × 107 and Wyoming had a population of 5.84 × 105. Complete the following sentences. 3.8216 × 107 0.38216 × 107 3.8216 × 106 38.216 × 107 0.66 × 101 66.4 × 101 6.64 × 101 The population of California is more than the population of Wyoming Alternatively, the population of California is times the population of Wyoming.

Step-by-step answer

P Answered by Master

The population of California is $3.3216 * 10^{7}$ more than the population of Wyoming.

Alternatively, the population of California is $6.64 * 10^{1}$ times the population of Wyoming.

Step-by-step explanation:

The first part is to take the numbers out of the scientific notation. The estimated population of California is 38,800,000, and the population of Wyoming is 584,000.

Not that we've done that, let's start with the first part of the problem.

"The population of California is __________ more than the population of Wyoming."

This is a statement of subtraction, because it's not asking how many TIMES more. So, we subtract Wyoming's population from California's population.

38,800,000 - 584,000 = 38,216,000.

Putting that number into scientific notation is easy: move the decimal to the place in the number where there will only be one number in front of the decimal: 3.3216. How many number slots until you have only one number in front of the decimal? 7. So, we know that the power of 10 is going to be 7. So, the first part of the question answers to:

$3.8216 * 10^{7} .$

Now for the second part.

"Alternatively, the population of California is _________ times the population of Wyoming."

This is a problem of division. The question is asking us to divide California's population by Wyoming's population.

$\frac{38,800,000}{584,000} = 0.664383562 * 10^{2} .$

We need to have one number in front of the decimal point, so we move it behind the first 6, giving us 6.64. Because we did this, we need to bump the exponent from 2 to 1, leaving us with:

$6.64 * 10^{1}.$

So, the answer to the question is:

1. $3.8216 * 10^{7}.$

2. $6.64 * 10^{1}.$

Hope this helped you, and I hope you get a perfect score!! :)

Physics

Asolar heated house loses about 5.4 × 107 cal through its outer surfaces on a typical 24-h winter day. what mass of storage rock is needed to provide this amount of heat if it is brought up to initial temperature of 62°c by the solar collectors and the house is maintained at 20°c? (specific heat of rock is 0.21 cal/g⋅°c.) a. 163 kg b. 1 230 kg c. 6 100 kg d. 12 700 kg

Step-by-step answer

P Answered by Master

C

Explanation:

Q=mcΔθ