The total perimeter of the fence is 68 ft and the area is 240 square feet. Based on this information, what are the dimensions of the fence?

6ft by 40ft

Step-by-step explanation:

Perimeter = 2(L+W)

Area = LW

L is the length of the fence

W is the width

Given

P = 68ft

A = 240ft²

Substitute into the formula

68 = 2L+2W ... 1

240 = LW... 2

From 1;

34 = L+W

L = 34-W ... 3

Substitute 3 into 2

From 2;

LW = 240

(34-W)W = 240

34W - W² = 240

- W²+34W = 240

W²-34W - 240 = 0

W²+6W-40W - 240 = 0

W(W+6)-40(W+6) = 0

W-40 = 0

W = 40feet

Since

34 = L+W

34 = L + 34

L = 6ft

Hence the dimension of the fence is 6ft by 40ft

The answer is in the image 

The solution is in the following image

The answer is in the image 

The answer is in the image 

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

The answer is in the image 

Area of rectangle= L*b

here,

L=12.4 cm

b= 8.8 cm

A= L*b

= 12.4 * 8.8 = 109.12 cm^2

Volume of rectangular prism=length * width * height

Given,

length=3/8cm

breadth=5/8cm

height=7/8cm

therefore volume=(3/8)*(5/8)*(7/8)

                           =105/512 cm3