01.01.2023

The tolerance limits for a circuit breaker are Amperes. This means that any circuit breaker that breaks at an amperage less than 39.5 breaks at too low a level and any that breaks at an amperage greater than 40.5 breaks at too high a level. If a shipment of circuit breakers possesses break points that are normally distributed with mean 39.3 and standard deviation 0.2, then what percentage of the shipment is defective

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24.06.2023, solved by verified expert
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84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 and standard deviation The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56, the zscore of a measure X is given by:

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

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Mathematics
Step-by-step answer
P Answered by PhD

84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that \mu = 39.3, \sigma = 0.2

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 39.3}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 39.3}{0.2}

Z = 6

Z = 6 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
Step-by-step answer
P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

Mathematics
Step-by-step answer
P Answered by PhD

The solution is in the following image

The solution is in the following image

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