01.01.2023

The tolerance limits for a circuit breaker are Amperes. This means that any circuit breaker that breaks at an amperage less than 39.5 breaks at too low a level and any that breaks at an amperage greater than 40.5 breaks at too high a level. If a shipment of circuit breakers possesses break points that are normally distributed with mean 39.3 and standard deviation 0.2, then what percentage of the shipment is defective

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24.06.2023, solved by verified expert
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84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 and standard deviation The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56, the zscore of a measure X is given by:

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

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Mathematics
Step-by-step answer
P Answered by PhD

84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that \mu = 39.3, \sigma = 0.2

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 39.3}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 39.3}{0.2}

Z = 6

Z = 6 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
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P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

Mathematics
Step-by-step answer
P Answered by PhD

The solution is given in the image below

The solution is given in the image below
Mathematics
Step-by-step answer
P Answered by PhD

30% of 420 are first year students

first year students = (30/100 )*420

=126 students

Student who are not in first year = 420-126

=294 students  

Mathematics
Step-by-step answer
P Answered by PhD

Area of rectangle= L*b

here,

L=12.4 cm

b= 8.8 cm

A= L*b

= 12.4 * 8.8 = 109.12 cm^2

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