01.01.2023

The tolerance limits for a circuit breaker are Amperes. This means that any circuit breaker that breaks at an amperage less than 39.5 breaks at too low a level and any that breaks at an amperage greater than 40.5 breaks at too high a level. If a shipment of circuit breakers possesses break points that are normally distributed with mean 39.3 and standard deviation 0.2, then what percentage of the shipment is defective

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24.06.2023, solved by verified expert
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84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 and standard deviation The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56, the zscore of a measure X is given by:

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56

The tolerance limits for a circuit breaker are, №17886365, 01.01.2023 04:56 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

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Mathematics
Step-by-step answer
P Answered by PhD

84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that \mu = 39.3, \sigma = 0.2

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 39.3}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 39.3}{0.2}

Z = 6

Z = 6 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD
The answer is in the image 

The answer is in the image 

Mathematics
Step-by-step answer
P Answered by PhD

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

Volume of rectangular prism=length * width * height

Given,

length=3/8cm

breadth=5/8cm

height=7/8cm

therefore volume=(3/8)*(5/8)*(7/8)

                           =105/512 cm3

Mathematics
Step-by-step answer
P Answered by PhD

The solution is given below

The solution is given below

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