See below
Step-by-step explanation:
4) You made an error in step 3
Step 1: -x³ + 22x² - 121x = 0
Step 2: -x(x² - 22x + 121) = 0
Step 3: -x(x - 11²) = 0 Error!
-x(x - 11)² = 0 Correction
Step 4: -x = 0 (x - 11)² = 0
Step 5: x = 0 x = 11
15) Your work is correct
n = 8, n = -9 BOTH answers are correct
n = 8 Error!
n = 8, n = -9 Correction
18) The formula is: h(t) =at² + vt + h(0)
a = -4.9 acceleration is negative because gravity pushes downv = 24.5 velocity is positive because it states it is "upward"h(0) = 117.6 h(0) is initial height
h(t) = -4.9t² + 24.5t + 117.6 option 3
19) Now that you have the correct equation, you can use the quadratic formula to solve for t
t = -3, t = 8
Since time cannot be negative, t = -3 is not valid
t = 8 option 1
20) It is given that h(t) = 49
Equation: 49 = -4.9t² + 24.5t + 117.6
0 = -4.9t² + 24.5t + 68.6
Use the quadratic equation to solve: t = -2, t = 7
Since time cannot be negative, t = -2 is not valid
t =7