14.01.2023

Solve 2^X = 64

6
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8

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Step-by-step answer

24.06.2023, solved by verified expert
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Step-by-step explanation:

The only number that will equal 64 if it is the power of 2

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Engineering
Step-by-step answer
P Answered by Specialist

See explaination

Explanation:

This function reverses the position

of the consonants keeping the

position of vowel constant.

Parameters:

data : type(str)

The string on which operation

needs to be performed

start : type(int)

Starting index of the string

end : type(int)

Ending index of the string

"""

def consonantReverse(data, start = 0, end = None):

# By default user will psas the data only.

# End will be none which will be set to length of string - 1

if(end == None):

return consonantReverse(data, 0, len(data)-1)

# return as this is invalid

if(start >= end):

return data

# split the data into list

if type(data)== str:

data = list(data)

# initialize index1 and index2

index1 = len(data)

index2 = -1

# find out the first index from beggining

# where consonant is present

for i in range(start, end+1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index1 = i

break

# find out the index from the end

# where consonant is present

for i in range(end, start-1, -1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index2 = i

break

# return as this is not valid case

if(index1 >= index2):

return ''.join(data)

# swap the data in the two index

data[index1], data[index2] = data[index2], data[index1]

# call the function recursively

data = consonantReverse(data, index1+1, index2-1)

# if it is a list, join the list into string

if(type(data) == list):

return ''.join(data)

# otherwise return the data

else:

return data

Engineering
Step-by-step answer
P Answered by Specialist

See explaination

Explanation:

This function reverses the position

of the consonants keeping the

position of vowel constant.

Parameters:

data : type(str)

The string on which operation

needs to be performed

start : type(int)

Starting index of the string

end : type(int)

Ending index of the string

"""

def consonantReverse(data, start = 0, end = None):

# By default user will psas the data only.

# End will be none which will be set to length of string - 1

if(end == None):

return consonantReverse(data, 0, len(data)-1)

# return as this is invalid

if(start >= end):

return data

# split the data into list

if type(data)== str:

data = list(data)

# initialize index1 and index2

index1 = len(data)

index2 = -1

# find out the first index from beggining

# where consonant is present

for i in range(start, end+1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index1 = i

break

# find out the index from the end

# where consonant is present

for i in range(end, start-1, -1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index2 = i

break

# return as this is not valid case

if(index1 >= index2):

return ''.join(data)

# swap the data in the two index

data[index1], data[index2] = data[index2], data[index1]

# call the function recursively

data = consonantReverse(data, index1+1, index2-1)

# if it is a list, join the list into string

if(type(data) == list):

return ''.join(data)

# otherwise return the data

else:

return data

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