A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

.

Write and solve an inequality which can be used to determine d, the number of days

Jocelyn can afford to rent while staying within her budget.

The number of days is at most 5 days

= d ≤ 5 days

Step-by-step explanation:

A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

At most means Less than or equal to $220

The inequality for expressing this = ≤

Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.

$31 × d + $0.13 × 500 miles ≤ $200

The inequality is given as:

31d + 65 ≤ 220

Solving further

31d ≤ 220 -65

31d ≤ 155

d ≤ 155/31

d ≤ 5

Therefore, the number of days is at most 5 days

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

The answer is in the image 

The total nom of  code that can be used is equal to 5+3 = 8

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

The solution is in the following image

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

The solution is given in the image below

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km