A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

.

Write and solve an inequality which can be used to determine d, the number of days

Jocelyn can afford to rent while staying within her budget.

The number of days is at most 5 days

= d ≤ 5 days

Step-by-step explanation:

A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

At most means Less than or equal to $220

The inequality for expressing this = ≤

Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.

$31 × d + $0.13 × 500 miles ≤ $200

The inequality is given as:

31d + 65 ≤ 220

Solving further

31d ≤ 220 -65

31d ≤ 155

d ≤ 155/31

d ≤ 5

Therefore, the number of days is at most 5 days

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

The answer is in the image 

The solution is in the following image

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The answer is in the image 

The answer is in the image 

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.