3x^2+ 7x +2, can I get help with this one also ?

(3x + 1)(2x + 1)

Step-by-step explanation:

Remark

This thing really does factor.

Both the first and last coefficients are prime, so if it factors easily 1 and 3 and 1 and 2 must be there somewhere.

(3x + 1)(x + 2)    would be the logical guess. That turns out to be correct.

A) All of Joe's work is correct. The solution is x = 26.

A) All of Joe's work is correct. The solution is x = 26.

1. Raffi forgot to place the substituted expression in parentheses.

2. (2, 8)

Step-by-step explanation:

If you are taking the Solving Systems With Substitution Quick Check from Connexus here are all of the answers:

1. Solve one linear function in terms of one of its variables.

2. Substitute 3y from the second equation for x in the first equation.

3. Raffi forgot to place the substituted expression in parentheses.

4. Yes, because substituting the given ordered pair yields two true expressions.

5. (2, 8)

1. Raffi forgot to place the substituted expression in parentheses.

2. (2, 8)

Step-by-step explanation:

If you are taking the Solving Systems With Substitution Quick Check from Connexus here are all of the answers:

1. Solve one linear function in terms of one of its variables.

2. Substitute 3y from the second equation for x in the first equation.

3. Raffi forgot to place the substituted expression in parentheses.

4. Yes, because substituting the given ordered pair yields two true expressions.

5. (2, 8)

replace x^2 with m and try to solve

-3 m^2 +27 m +1200 =0

factor out -3

-3(m^2 -9m-400)=0

-3 (m-25) (m+16) =0

using the zero product property

m-25 =0 m+16=0

m=25  m=-16

then substitute m=x^2 back in

x^2 = 25   x^2 = -16

x take the square root of each side

x = +- sqrt (25)   if you know complex number  x = +- sqrt (-16)

x = +-5      x = +- 4i

 +5, -5 , +4i, -4i

replace x^2 with m and try to solve

-3 m^2 +27 m +1200 =0

factor out -3

-3(m^2 -9m-400)=0

-3 (m-25) (m+16) =0

using the zero product property

m-25 =0 m+16=0

m=25  m=-16

then substitute m=x^2 back in

x^2 = 25   x^2 = -16

x take the square root of each side

x = +- sqrt (25)   if you know complex number  x = +- sqrt (-16)

x = +-5      x = +- 4i

 +5, -5 , +4i, -4i

Number 3,  4, and 5 are polynomials

Step-by-step explanation:

Polynomials do not  contain fractions as in expression 1 nor radicals as in expression 2.

Also they do not contain negative exponents as in expression 6.

Polynomials contain integer coefficients only.

The answer to your question is below

Step-by-step explanation:

                 (2x⁴ + 7x³ - 3x + 9) - (6x⁴ - 3x³ - 6x² - 17)

Step 1. take out the parenthesis, in the second term, change the signs

                  2x⁴ + 7x³ - 3x + 9 - 6x⁴ + 3x³ + 6x² + 17

Step 2. Group like terms

                  (2x⁴ - 6x⁴) + (7x³ + 3x³) + (6x²) + (-3x) + (9 + 17)

Step 3. Simplify like terms

                          -2x⁴ + 10x³ + 6x² - 3x + 26

C. The second equation in system B is   .The solution to system B will be the same as the solution to system A.

Step-by-step explanation:

Given  

System A:

System B:

When we multiply I equation of system A by -2 then we get new equation

( III equation )

Adding equation II  of system A and eqaution III then we get

Hence, II equation of system B

By division property of equality

x=-2

Substitute the value of x=-2 in equation I of system B then we get

-10-y=-11

By simplification

=-1

y=1

By simplification

Therefore, the solution of system B is (-2,1).

Hence, option C is correct .

C. The second equation in system B is -7x=14 . The solution to system B will be the same as the solution to system A.