A diver is on a diving board 12 meters above the water. He dives vertically from the board with initial velocity of 4.9 meter/sec. how high will the diver get above the water?

13.225 m

Step-by-step explanation:

Given that :

Initial Velocity, u = 4.9m/s

Acceleration due to gravity, a = - 9.8 m/s² (downward)

Distance, S = - 12

According to the motion equation :

S = ut + 0.5at²

S = 4.9t + 0.5(-9.8)t²

S = 4.9t - 4.9t² - - - (1)

At the highest point, v = 0

v² = u + at

0 = 4.9 + - 9.8t

-9.8t = - 4.9

t = 4.9/9.8

t = 0.5s

Put t = 0.5 in (1) above

S = 4.9(0.5) - 4.9(0.5)²

S = 2.45 - 1.225

S = 1.225 m

Total height :

(12 + 1.225) m = 13.225 m

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

The solution is given in the image below

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

The answer is in the image 

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years