09.04.2023

In a housing project there are 180 households in which English is usually spoken, 80 in which Spanish is usually spoken, and 40 in which the language is other than English or Spanish. A researcher approaches a house at random to conduct an interview. What is the chance that the usual language in that household will NOT be English

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24.06.2023, solved by verified expert
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The chance that the usual language in that household will NOT be English = 0.4

Step-by-step explanation:

As given ,

Total households in which languages spoken is English = 180

Total households in which languages spoken is Spanish = 80

Total households in which languages spoken is other than English or Spanish  = 40

So,

Total households = 180 + 80 + 40 = 300

Now,

Household in which English language is not spoken = 80 + 40 = 120

So,

The chances that the usual language in that household will NOT be English = In a housing project there are 180 households, №17886904, 09.04.2023 20:39

∴ we get

The chance that the usual language in that household will NOT be English = 0.4

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Mathematics
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P Answered by PhD

The chance that the usual language in that household will NOT be English = 0.4

Step-by-step explanation:

As given ,

Total households in which languages spoken is English = 180

Total households in which languages spoken is Spanish = 80

Total households in which languages spoken is other than English or Spanish  = 40

So,

Total households = 180 + 80 + 40 = 300

Now,

Household in which English language is not spoken = 80 + 40 = 120

So,

The chances that the usual language in that household will NOT be English = \frac{120}{300} = \frac{12}{30} = \frac{4}{10} = 0.4

∴ we get

The chance that the usual language in that household will NOT be English = 0.4

Mathematics
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P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
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P Answered by PhD
The answer is in the image 

The answer is in the image 

Mathematics
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P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
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P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km

Mathematics
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P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

30% of 420 are first year students

first year students = (30/100 )*420

=126 students

Student who are not in first year = 420-126

=294 students  

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