In a housing project there are 180 households in which English is usually spoken, 80 in which Spanish is usually spoken, and 40 in which the language is other than English or Spanish. A researcher approaches a house at random to conduct an interview. What is the chance that the usual language in that household will NOT be English

The chance that the usual language in that household will NOT be English = 0.4

Step-by-step explanation:

As given ,

Total households in which languages spoken is English = 180

Total households in which languages spoken is Spanish = 80

Total households in which languages spoken is other than English or Spanish  = 40

So,

Total households = 180 + 80 + 40 = 300

Now,

Household in which English language is not spoken = 80 + 40 = 120

So,

The chances that the usual language in that household will NOT be English =

∴ we get

The chance that the usual language in that household will NOT be English = 0.4

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

The answer is in the image 

The total nom of  code that can be used is equal to 5+3 = 8

The answer is in the image 

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The solution is given in the image below

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years