A 0.025 kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 109 m/s. If the melon was

originally at rest, then what speed will it have as the bullet leaves its

opposite side?

1.15m/s

Step-by-step explanation:

Given data

m1=0.025 kg

m2= 2.35kg

u1= 217 m/s

v1= 109 m/s

u2= 0

v2=???

Applying the law of conservation of linear momentum

m1u1+m2u2=m1v1+m2v2

substitute

0.025*217+2.35*0= 0.025*109+2.35*v2

5.425= 2.725+ 2.35v2

5.425-2.725=2.35v2

2.7=2.35v2

divide both sides by 2.35

v2= 2.7/2.35

v2=1.15 m/s

Hence the speed of the watermelon will be 1.15m/s

The answer is in the image 

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

The answer is in the image 

The answer is in the image 

The answer is in the image 

The answer is in the image 

The solution is given in the image below

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.