Max p = 28x + 41y
Subject to
59x + 58y ≤ 3660
21x + 34y ≤ 4020
x ≥ 0, y ≥ 0
Step-by-step explanation:
As given ,
Windbreakers Rain breakers Total
Finishing time 59 min 58 min 61 hr
Packaging time 21 min 34 min 68 hr
Profit 28 41
Let
The number of windbreaker jackets they should produce = x
The number of rain breaker jackets they should produce = y
As given,
The company wants to maximize profit.
⇒ Maximum Profit , p = 28x + 41 y
Now,
As 1 hour = 60 min
⇒61 hours = 61×60 = 3660 min
and 67 hours = 67×60 = 4020 min
∴ we get
The equations become
59x + 58y ≤ 3660
21x + 34y ≤ 4020
x ≥ 0, y ≥ 0
So, the Linear Programming Problem (LPP) for this problem is -
Max p = 28x + 41y
Subject to
59x + 58y ≤ 3660
21x + 34y ≤ 4020
x ≥ 0, y ≥ 0