08.07.2021

Find four consecutive integers such that 8 times the sum of the first and the third is 40 greater than 10 times the fourth.

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24.06.2023, solved by verified expert

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Mathematics
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P Answered by PhD
The consecutive integers are 9,10,11,12.
Mathematics
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P Answered by PhD

An integer number is a Whole number which must not have any decimal. For example -5, -4, -3 -2, -1, 0, 1 2, 3, 4, 5. So an integer can be negative and positive.

Following are the formulas for calculating Even and Odd integers:

Let the even number be = X

consecutive even integers =  X, X + 2, X + 4, X + 6...etc

Odd number integer will be = 2X + 1

Consecutive Odd Integer numbers = (2X+ 1), (2X + 1+ 2), (2X+ 1+2+2)and so on.

Now the answers:

Four consecutive even integers such that the sum of the first and third is 6 less than the largest : Answer is -4, -2, 0, 2

Equation X + X + 2 = (X + 6) - 6

four consecutive odd integers such that the largest equals 2 more than the sum of the other three:  Answer -1, 1, 3, 5

Equation 2X+7 = (2X+1) + (2X+3) + (2X+5) + 2

Two consecutive even integers such that twice the smaller is 26 less than three times the larger: Answer 20, 22

The consecutive integers such that twice the sum of the first and second is 27 more than three times the Third: Answer 31, 32, 33

Three consecutive integers such that three times the smallest added to 7 is 13 less than four times the largest: Answer 12, 13, 14

Three times the first of three consecutive integers is subtracted from twice the second the result is 16 more than the third the integers: Answer 8, 9, 10

Four cons ecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742: Answer 120, 122, 124, 126

The smallest of three consecutive odd integers is added to four times the largest IT produces a result 729 more than four times the middle integer. find the numbers: Answer 721, 723, 727

Three consecutive multiples of 5 have a sum of 75 what are the numbers: Answer 20, 25, 30

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Mathematics
Step-by-step answer
P Answered by PhD

An integer number is a Whole number which must not have any decimal. For example -5, -4, -3 -2, -1, 0, 1 2, 3, 4, 5. So an integer can be negative and positive.

Following are the formulas for calculating Even and Odd integers:

Let the even number be = X

consecutive even integers =  X, X + 2, X + 4, X + 6...etc

Odd number integer will be = 2X + 1

Consecutive Odd Integer numbers = (2X+ 1), (2X + 1+ 2), (2X+ 1+2+2)and so on.

Now the answers:

Four consecutive even integers such that the sum of the first and third is 6 less than the largest : Answer is -4, -2, 0, 2

Equation X + X + 2 = (X + 6) - 6

four consecutive odd integers such that the largest equals 2 more than the sum of the other three:  Answer -1, 1, 3, 5

Equation 2X+7 = (2X+1) + (2X+3) + (2X+5) + 2

Two consecutive even integers such that twice the smaller is 26 less than three times the larger: Answer 20, 22

The consecutive integers such that twice the sum of the first and second is 27 more than three times the Third: Answer 31, 32, 33

Three consecutive integers such that three times the smallest added to 7 is 13 less than four times the largest: Answer 12, 13, 14

Three times the first of three consecutive integers is subtracted from twice the second the result is 16 more than the third the integers: Answer 8, 9, 10

Four cons ecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742: Answer 120, 122, 124, 126

The smallest of three consecutive odd integers is added to four times the largest IT produces a result 729 more than four times the middle integer. find the numbers: Answer 721, 723, 727

Three consecutive multiples of 5 have a sum of 75 what are the numbers: Answer 20, 25, 30

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Mathematics
Step-by-step answer
P Answered by Master

These are indeed quite a lot of exercises, but a lot of them are almost identical - only small computations will change. So, I'm glad to help you with one exercise from every cathegory, but I encourage you to solve the others on your own.

Exercise 1

You can call four consecutive integers as

x,\ x+1,\ x+2,\ x+3

So, the sum of the first and third is x+(x+2) = 2x+2

We want this quantity to be six less than the largest, i.e. (x+3)-6 = x-3

So, the equality is

2x+2 = x-3

Subtract x from both sides:

x+2 = -3

Subtract 2 from both sides:

x = -5

So, the consecutive integers are

-5,\ -4,\ -3,\ -2

In fact, the sum of the first and third is -5-3 = -8, which is indeed six less than the largest: -8 = -2-6

Exercise 2

If you call the first odd number x, the next consecutive odd numbers will be x,\ x+2,\ x+4,\ x+6

In fact, we have to count skipping two's, because we only want odd integers. From here, you go on like exercise 1: you write the largest (which is x+6), and set it to be two more than the sum of the other three (x, x+2 and x+4)

Exercise 3

By the same logic of exercise 2, two consecutive even integers are x,\ x+2, assuming that x is even.

So, you set the equation as usual: the smaller (which is x) is 26 less than three times the larger (which means 3(x+2)-26)

Exercise 4 to 8

These are all pretty identical to exercise 1: you start by listing three or four consecutive integers:

x,\ x+1,\ x+2\quad\text{or}\quad  x,\ x+1,\ x+2\ x+3

and then you translate the request of each exercise accordingly. Remember that expressions like "three times the second number" means that you have to multiply: 3(x+1), while expression like "six more than the first" or "thirteen less than the first" imply adding/subtracting: x+6 or x-13.

Exercise 9

A multiple of 5 can be written as 5k, for some integer k.

So, three consecutive multiples of 5 are

5k, 5(k+1), 5(k+2) = 5k, 5k+5, 5k+10

We want these three numbers to have a sum of 75. So, we have

5k, 5k+5, 5k+10 = 75 \iff 15k+15 = 75 \iff 15k = 60 \iff k = 4

So, the three numbers are

5k, 5(k+1), 5(k+2) = 5\cdot 4, 5\cdot 5, 5\cdot 6 = 20, 25, 30

Mathematics
Step-by-step answer
P Answered by PhD
1. Three consecutive integers: x, x+1, x+2, such that:
x + x + 1 + x + 2 = 120
3 x + 3 = 120
3 x = 117
x = 117:3= 39
The integers are: 39,40,41.
2.
 x + x + 2 = x +1 +21
 2 x - x = 22 - 2
 x = 20
The integers are: 20,21,22.
3. Four consecutive even integers: x, x+2, x+4, x+6
4 ( x + x + 2 ) = 7 (x + 6 ) - 8
8 x + 8 = 7 x + 42 - 8
8 x - 7 x = 34 - 8
x = 26
The integers are: 26, 28, 30 , 32. 
Mathematics
Step-by-step answer
P Answered by PhD
1. Three consecutive integers: x, x+1, x+2, such that:
x + x + 1 + x + 2 = 120
3 x + 3 = 120
3 x = 117
x = 117:3= 39
The integers are: 39,40,41.
2.
 x + x + 2 = x +1 +21
 2 x - x = 22 - 2
 x = 20
The integers are: 20,21,22.
3. Four consecutive even integers: x, x+2, x+4, x+6
4 ( x + x + 2 ) = 7 (x + 6 ) - 8
8 x + 8 = 7 x + 42 - 8
8 x - 7 x = 34 - 8
x = 26
The integers are: 26, 28, 30 , 32. 
Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

-8-10,-12-14

-8 plus -12 is -20

-20 times 5 is -100

-14 times 8 is -112

-100 is 12 more than -112

Mathematics
Step-by-step answer
P Answered by PhD

-8-10,-12-14

-8 plus -12 is -20

-20 times 5 is -100

-14 times 8 is -112

-100 is 12 more than -112

Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

-8-10,-12-14

-8 plus -12 is -20

-20 times 5 is -100

-14 times 8 is -112

-100 is 12 more than -112

Mathematics
Step-by-step answer
P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram

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