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Mathematics : asked on 38amica
 05.12.2021

. When 2 times a number is increased by 4, the answer is the same as when 25is
decreased by the number. Find the number.

. 0

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24.06.2023, solved by verified expert
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Ranjana Bhatt
p PhD
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The number is 7

Step-by-step explanation:

Let x be the [number]

Rephrase the expression

2 times a number is increased by 4, it is the same as 25 decreased by the number

2x+4=25-x

Calculate

Given

2x+4=25-x

Add x on both sides

2x+4+x=25-x+x

3x+4=25

Subtract 4 on both sides

3x+4-4=25-4

3x=21

Divide 3 on both sides

3x/3=21/3

x=7

Hope this helps!! :)

Please let me know if you have any questions

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Mathematics
. When 2 times a number is increased by 4, the answer is the same as when 25is decreased by the number. Find the number.
Step-by-step answer
P Answered by PhD

The number is 7

Step-by-step explanation:

Let x be the [number]

Rephrase the expression

2 times a number is increased by 4, it is the same as 25 decreased by the number

2x+4=25-x

Calculate

Given

2x+4=25-x

Add x on both sides

2x+4+x=25-x+x

3x+4=25

Subtract 4 on both sides

3x+4-4=25-4

3x=21

Divide 3 on both sides

3x/3=21/3

x=7

Hope this helps!! :)

Please let me know if you have any questions

Chemistry
Sort each of the following events based on whether the solubility of the indicated gas will increase, decrease, or stay the same. each phrase specifies the gas involved and the change in its environment. 1. the temperature is increased 2.the partial pressure of an anesthetic gas is increased 3.o2: temperature of a body when water rises 4. the pressure of a gas over a solvent is increased 5. air in blood: a diver descends 10m and pressure increase by 1 am me and tell me which ones gas solubility increase, decrease or the gas stays the same. i got
Step-by-step answer
P Answered by Master

1. The solubility of the anesthetic gas \boxed{{\text{decreases}}} if the temperature is increased.  

2. The solubility of the anesthetic gas \boxed{{\text{increases}}} if its partial pressure is increased.  

3. The solubility of the oxygen \boxed{{\text{decreases}}} if the temperature of the body is increased.

4. The solubility of oxygen  \boxed{{\text{increases}}} if its pressure over the solvent is increased.

5. The solubility of air in blood \boxed{{\text{increases}}} if diver descends 10\;{\text{m}} and the pressure is increased by {\text{1}}\;{\text{atm}}.

Further Explanation:

The chemical property of any substance that makes it capable to dissolve in other substances is called solubility. It is measured in terms of the maximum amount of solute that can be dissolved in the given amount of solvent.

Solubility is directly related to the intermolecular forces. Moreover, temperature and pressure are two other factors that influence the solubility of the gas.

There exist weak intermolecular forces between the gas molecules. With the increase in the temperature, the average kinetic energy also speeds up due to which the molecules start vibrating about their mean positions. This results in overcoming of the weak forces and the molecules re-enter into the gas phase. So solubility decreases with the increase in temperature.

The law that governs the relationship of gas solubility with its partial pressure is Henry’s Law. It states that the solubility \left( {{{\text{S}}_{{\text{gas}}}}} \right) is directly proportional to the partial pressure \left( {{{\text{P}}_{{\text{gas}}}}} \right) of the gas. If the gas has high partial pressure, it will have a higher solubility and vice-versa.

Mathematically, {{\mathbf{S}}_{{\mathbf{gas}}}} \propto {{\mathbf{P}}_{{\mathbf{gas}}}}

We incorporate a proportionality constant in order to remove the sign of proportionality. That constant is known as Henry’s constant, represented by {{\mathbf{k}}_{\mathbf{H}}}.

So Henry’s Law becomes {{\mathbf{S}}_{{\mathbf{gas}}}} = {{\mathbf{k}}_{\mathbf{H}}}{\mathbf{ \times }}\;{{\mathbf{P}}_{{\mathbf{gas}}}}

1. As we know, the solubility of gas is inversely proportional to the temperature. So if the temperature of anesthetic gas is increased, its solubility decreases.

2. According to Henry’s Law, the solubility of gas is directly proportional to the partial pressure of the gas. So the solubility of anesthetic gas also increases with the increase in its partial pressure.

3. As we know, the solubility of gas is inversely proportional to the temperature. So if the temperature of the body is increased, the solubility of oxygen decreases.

4. According to Henry’s Law, the solubility of gas is directly proportional to the partial pressure of the gas. So the solubility of oxygen also increases with the increase in its partial pressure.

5. As the diver descends  10\;{\text{m}} and the pressure is increased by 1\;{\text{atm}}, the solubility of gas increases in accordance with Henry’s Law.

Learn more:  

1. Statement about subatomic particle:

2. The energy of a photon in light:

Answer details:  

Grade: Senior School  

Subject: Chemistry  

Chapter: Solutions

Keywords: solubility, gas, increase, decrease, temperature, partial pressure, diver, air, change, environment, oxygen, blood, Henry's Law, anesthetic gas.

Chemistry
Sort each of the following events based on whether the solubility of the indicated gas will increase, decrease, or stay the same. each phrase specifies the gas involved and the change in its environment. 1. the temperature is increased 2.the partial pressure of an anesthetic gas is increased 3.o2: temperature of a body when water rises 4. the pressure of a gas over a solvent is increased 5. air in blood: a diver descends 10m and pressure increase by 1 am me and tell me which ones gas solubility increase, decrease or the gas stays the same. i got
Step-by-step answer
P Answered by Specialist

1. The solubility of the anesthetic gas \boxed{{\text{decreases}}} if the temperature is increased.  

2. The solubility of the anesthetic gas \boxed{{\text{increases}}} if its partial pressure is increased.  

3. The solubility of the oxygen \boxed{{\text{decreases}}} if the temperature of the body is increased.

4. The solubility of oxygen  \boxed{{\text{increases}}} if its pressure over the solvent is increased.

5. The solubility of air in blood \boxed{{\text{increases}}} if diver descends 10\;{\text{m}} and the pressure is increased by {\text{1}}\;{\text{atm}}.

Further Explanation:

The chemical property of any substance that makes it capable to dissolve in other substances is called solubility. It is measured in terms of the maximum amount of solute that can be dissolved in the given amount of solvent.

Solubility is directly related to the intermolecular forces. Moreover, temperature and pressure are two other factors that influence the solubility of the gas.

There exist weak intermolecular forces between the gas molecules. With the increase in the temperature, the average kinetic energy also speeds up due to which the molecules start vibrating about their mean positions. This results in overcoming of the weak forces and the molecules re-enter into the gas phase. So solubility decreases with the increase in temperature.

The law that governs the relationship of gas solubility with its partial pressure is Henry’s Law. It states that the solubility \left( {{{\text{S}}_{{\text{gas}}}}} \right) is directly proportional to the partial pressure \left( {{{\text{P}}_{{\text{gas}}}}} \right) of the gas. If the gas has high partial pressure, it will have a higher solubility and vice-versa.

Mathematically, {{\mathbf{S}}_{{\mathbf{gas}}}} \propto {{\mathbf{P}}_{{\mathbf{gas}}}}

We incorporate a proportionality constant in order to remove the sign of proportionality. That constant is known as Henry’s constant, represented by {{\mathbf{k}}_{\mathbf{H}}}.

So Henry’s Law becomes {{\mathbf{S}}_{{\mathbf{gas}}}} = {{\mathbf{k}}_{\mathbf{H}}}{\mathbf{ \times }}\;{{\mathbf{P}}_{{\mathbf{gas}}}}

1. As we know, the solubility of gas is inversely proportional to the temperature. So if the temperature of anesthetic gas is increased, its solubility decreases.

2. According to Henry’s Law, the solubility of gas is directly proportional to the partial pressure of the gas. So the solubility of anesthetic gas also increases with the increase in its partial pressure.

3. As we know, the solubility of gas is inversely proportional to the temperature. So if the temperature of the body is increased, the solubility of oxygen decreases.

4. According to Henry’s Law, the solubility of gas is directly proportional to the partial pressure of the gas. So the solubility of oxygen also increases with the increase in its partial pressure.

5. As the diver descends  10\;{\text{m}} and the pressure is increased by 1\;{\text{atm}}, the solubility of gas increases in accordance with Henry’s Law.

Learn more:  

1. Statement about subatomic particle:

2. The energy of a photon in light:

Answer details:  

Grade: Senior School  

Subject: Chemistry  

Chapter: Solutions

Keywords: solubility, gas, increase, decrease, temperature, partial pressure, diver, air, change, environment, oxygen, blood, Henry's Law, anesthetic gas.

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Step-by-step answer
P Answered by Specialist

1) 1  2) 1 3)4  4) 1  5) 1 6)1  7)3  8)3  9)2   10)3

Explanation:

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If I fail, I get an F and I have a time limit. PLEASE HELP!! 1. The gravitational force of the sun affects the planets in our solar system. Which of these is influenced the most by this force. 1. Orbit path. 2. Axial tilt. 3. The mass of the planets. 4. The number of moons per planet 2. A student recorded the following information about two magnets: When magnet 1 was held above a collection of paper clips, 8 paper clips jumped to the magnets. When the magnet was held above same collection of paper clips. 14 paper clips jumped to the magnet. What
Step-by-step answer
P Answered by Master

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Explanation:

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Step-by-step answer
P Answered by PhD

(1) A) the number of electrons surrounding the nucleus.

(2) A) valence or conduction electrons.

(3) B) reduced by a factor of 4.

(4) E) quadrupled

(5) B) It remains the same.

Explanation:

(1) The number of protons in the nucleus of an electrically neutral atom is equal to _________

protons are found in the nucleus while electrons surround the nucleus

A) the number of electrons surrounding the nucleus.

2) The main difference between conductors and insulators is in terms of _________.

conductors have mobile or free electrons while insulators have none.

A) valence or conduction electrons.

3) When the distance between the two charges is doubled, the force between them is ___________.

According to Coulomb's law;

F = \frac{Kq_1q_2}{r^2}

where;

F is the force between the charges

q₁ and q₂ are the two charges

r is the distance between the two charges

k is coulomb's constant

F = \frac{C}{r^2} , \ C = kq_1q_2\\\\F_1r_1^2 = F_2r_2^2, \ But \ r_2 = 2r_1\\\\F_2=\frac{F_1r_1^2}{r_2^2} = \frac{F_1r_1^2}{(2r_1)^2}= \frac{F_1r_1^2}{4r_1^2}\\\\F_2 = \frac{F_1}{4}

B) reduced by a factor of 4.

4) When the magnitude of both interacting charges is increased by a factor of 2, the electrical forces between these charges is _________

Apply Coulomb's law again;

F =\frac{kq_1q_2}{r^2} \\\\F = Cq_1q_2, \ C = \frac{k}{r^2} \\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{(q_1q_2)_2} \\\\But \ (q_1q_2)_2 = (2q_12q_2)_1 = 4(q_1q_2)_1\\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{4(q_1q_2)_1} \\\\F_2 = 4 F_1

E) quadrupled

5) Two charges, Q1 and Q2, are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges?

Apply Coulomb's law;

F = \frac{kQ_1Q_2}{R^2} \\\\k = \frac{FR^2}{Q_1Q_2} \\\\\frac{F_1R^2}{Q_1Q_2} = \frac{F_2(R/2)^2}{(Q_1/2)(Q_2/2)} \\\\\frac{F_1R^2}{Q_1Q_2} =\frac{F_2(\frac{1}{4}R^2 )}{\frac{1}{4} (Q_1Q_2)}\\\\F_2 = F_1

B) It remains the same.

Physics
Multiple Choice Questions. 1) The number of protons in the nucleus of an electrically neutral atom is equal to . A) the number of electrons surrounding the nucleus. B) the number of neutrons in the nucleus. C) the number of neutrons surrounding the nucleus. D) the number of electrons in the nucleus. E) None of the other choices is correct. 2) The main difference between conductors and insulators is in terms of . A) valence or conduction electrons. B) protons. C) atoms. D) neutrons. E) None of the other choices is correct. 3) When the distance between
Step-by-step answer
P Answered by PhD

(1) A) the number of electrons surrounding the nucleus.

(2) A) valence or conduction electrons.

(3) B) reduced by a factor of 4.

(4) E) quadrupled

(5) B) It remains the same.

Explanation:

(1) The number of protons in the nucleus of an electrically neutral atom is equal to _________

protons are found in the nucleus while electrons surround the nucleus

A) the number of electrons surrounding the nucleus.

2) The main difference between conductors and insulators is in terms of _________.

conductors have mobile or free electrons while insulators have none.

A) valence or conduction electrons.

3) When the distance between the two charges is doubled, the force between them is ___________.

According to Coulomb's law;

F = \frac{Kq_1q_2}{r^2}

where;

F is the force between the charges

q₁ and q₂ are the two charges

r is the distance between the two charges

k is coulomb's constant

F = \frac{C}{r^2} , \ C = kq_1q_2\\\\F_1r_1^2 = F_2r_2^2, \ But \ r_2 = 2r_1\\\\F_2=\frac{F_1r_1^2}{r_2^2} = \frac{F_1r_1^2}{(2r_1)^2}= \frac{F_1r_1^2}{4r_1^2}\\\\F_2 = \frac{F_1}{4}

B) reduced by a factor of 4.

4) When the magnitude of both interacting charges is increased by a factor of 2, the electrical forces between these charges is _________

Apply Coulomb's law again;

F =\frac{kq_1q_2}{r^2} \\\\F = Cq_1q_2, \ C = \frac{k}{r^2} \\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{(q_1q_2)_2} \\\\But \ (q_1q_2)_2 = (2q_12q_2)_1 = 4(q_1q_2)_1\\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{4(q_1q_2)_1} \\\\F_2 = 4 F_1

E) quadrupled

5) Two charges, Q1 and Q2, are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges?

Apply Coulomb's law;

F = \frac{kQ_1Q_2}{R^2} \\\\k = \frac{FR^2}{Q_1Q_2} \\\\\frac{F_1R^2}{Q_1Q_2} = \frac{F_2(R/2)^2}{(Q_1/2)(Q_2/2)} \\\\\frac{F_1R^2}{Q_1Q_2} =\frac{F_2(\frac{1}{4}R^2 )}{\frac{1}{4} (Q_1Q_2)}\\\\F_2 = F_1

B) It remains the same.

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