Mathematics : asked on imhacking2048

01.01.2020

I need to know what the difference of this expression is.

(4 - 5i) - (12 + 11i)

0

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24.06.2023, solved by verified expert

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-10-16i

Step-by-step explanation:

Given

(4-5i)-(12+11i)

Expand parenthesis

2-5i-12-11i

Put like terms together

(2-12)-(5i+11i)

Combine like terms

-10-16i

Hope this helps!! :)

Please let me know if you have any questions

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Mathematics

I need to know what the difference of this expression is. (4 - 5i) - (12 + 11i)

Step-by-step answer

P Answered by PhD

1

-10-16i

Step-by-step explanation:

Given

(4-5i)-(12+11i)

Expand parenthesis

2-5i-12-11i

Put like terms together

(2-12)-(5i+11i)

Combine like terms

-10-16i

Hope this helps!! :)

Please let me know if you have any questions

Mathematics

Simplify. 9y + 11z + 7y - 4z what is the answer? 16y + 7z which expression shows the result of applying the distributive property to 12(5y + 4) ? 60y + 48 which expression shows the result of applying the distributive property to -2(1/3x - 1/5) ? -2/3x + 2/5 factor the expression. 24 - 18y enter your answers in the boxes to complete the factored expression. 6(4) - 3y) which expression is the factored form of 2/3x + 4 ? 2/3 (x + 6) simplify. 8u + 9u + 3u - 5u what is the answer? 11u + 4v which expression shows the result of applying the distributive

Step-by-step answer

P Answered by Master

7

Thanks so much! =^-^= Really helped a lot.

Mathematics

Simplify. 9y + 11z + 7y - 4z what is the answer? 16y + 7z which expression shows the result of applying the distributive property to 12(5y + 4) ? 60y + 48 which expression shows the result of applying the distributive property to -2(1/3x - 1/5) ? -2/3x + 2/5 factor the expression. 24 - 18y enter your answers in the boxes to complete the factored expression. 6(4) - 3y) which expression is the factored form of 2/3x + 4 ? 2/3 (x + 6) simplify. 8u + 9u + 3u - 5u what is the answer? 11u + 4v which expression shows the result of applying the distributive

Step-by-step answer

P Answered by Specialist

7

Thanks so much! =^-^= Really helped a lot.

Mathematics

How to find nth term for a sequence of following numbers; 1,9,36, i know that this is square sequence and i use the formula a+(n-1)d+1/2×(n-1)×(n-2)c where a=the first term of first sequence d=difference between first two terms in first sequence and c=common difference between terms in the second difference. how to express c in this example if the terms in the second sequence are cube numbers?

Step-by-step answer

P Answered by PhD

1

Let a_n denote the given sequence. a_n has forward differences

{9 - 1, 36 - 9, 100 - 36, ...} = {8, 27, 64, ...} = {2^3, 3^3, 4^3, ...}

If we call the sequence of forward differences b_n , then for $n\ge1$ ,

b_n=(n+1)^3

b_n is defined in terms of a_n for all $n\ge1$ by

$b_n=a_{n+1}-a_n$

and so a_n is defined recursively by

$a_n=\begin{cases}a_1=1\\a_{n+1}=a_n+(n+1)^3&\text{for }n\ge1\end{cases}$

We can deduce a pattern for the general -th term:

a_2=a_1+2^3

$a_3=a_2+3^3=a_1+\displaystyle\sum_{i=1}^2(i+1)^3$

$a_4=a_3+4^3=a_1+\displaystyle\sum_{i=1}^3(i+1)^3$

and so on, up to

$a_n=a_1+\displaystyle\sum_{i=1}^{n-1}(i+1)^3$

We can simplify the right hand side a bit, noticing that a_1=1=1^3 matches (i+1)^3 for i=0 :

$a_n=\displaystyle\sum_{i=0}^{n-1}(i+1)^3$

and to simplify things a bit more, we shift the index of summation:

$a_n=\displaystyle\sum_{i=1}^ni^3$

You should know that the right side has a nice closed form (look up "Faulhaber's formula" if you don't):

$a_n=\dfrac{n^2(n+1)^2}4$

Mathematics

Write three different single-term expressions that are equivalent to x^-2. at least on expression should use division and another should use multipucation. show how you know that your expressions are equivalent.

Step-by-step answer

P Answered by PhD

2

X^-2 = 1/x^2

Mathematics

Which of these statements about algebra are true? a. algebra uses abstract symbols to represent concrete elements in the real world. b. in an algebraic equation, the same variable can represent two different unknowns. c. many great mathematicians were also philosophers. d. an algebraic expression contains an equal sign, but an algebraic equation does not. e. the same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step answer

P Answered by PhD

1

A.

Step-by-step explanation:

The symbols are usually letters.

The most commonly used are x, y and z.

Mathematics

Which of these statements about algebra are true? a. algebra uses abstract symbols to represent concrete elements in the real world. b. in an algebraic equation, the same variable can represent two different unknowns. c. many great mathematicians were also philosophers. d. an algebraic expression contains an equal sign, but an algebraic equation does not. e. the same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step answer

P Answered by PhD

1

A.

Step-by-step explanation:

The symbols are usually letters.

The most commonly used are x, y and z.

Mathematics

How to find nth term for a sequence of following numbers; 1,9,36, i know that this is square sequence and i use the formula a+(n-1)d+1/2×(n-1)×(n-2)c where a=the first term of first sequence d=difference between first two terms in first sequence and c=common difference between terms in the second difference. how to express c in this example if the terms in the second sequence are cube numbers?

Step-by-step answer

P Answered by PhD

1

Let a_n denote the given sequence. a_n has forward differences

{9 - 1, 36 - 9, 100 - 36, ...} = {8, 27, 64, ...} = {2^3, 3^3, 4^3, ...}

If we call the sequence of forward differences b_n , then for $n\ge1$ ,

b_n=(n+1)^3

b_n is defined in terms of a_n for all $n\ge1$ by

$b_n=a_{n+1}-a_n$

and so a_n is defined recursively by

$a_n=\begin{cases}a_1=1\\a_{n+1}=a_n+(n+1)^3&\text{for }n\ge1\end{cases}$

We can deduce a pattern for the general -th term:

a_2=a_1+2^3

$a_3=a_2+3^3=a_1+\displaystyle\sum_{i=1}^2(i+1)^3$

$a_4=a_3+4^3=a_1+\displaystyle\sum_{i=1}^3(i+1)^3$

and so on, up to

$a_n=a_1+\displaystyle\sum_{i=1}^{n-1}(i+1)^3$

We can simplify the right hand side a bit, noticing that a_1=1=1^3 matches (i+1)^3 for i=0 :

$a_n=\displaystyle\sum_{i=0}^{n-1}(i+1)^3$

and to simplify things a bit more, we shift the index of summation:

$a_n=\displaystyle\sum_{i=1}^ni^3$

You should know that the right side has a nice closed form (look up "Faulhaber's formula" if you don't):

$a_n=\dfrac{n^2(n+1)^2}4$

Mathematics

Which of these statements about algebra are true? algebra uses abstract symbols to represent concrete elements in the real world. in an algebraic equation, the same variable can represent two different unknowns. many great mathematicians were also philosophers. an algebraic expression contains an equal sign, but an algebraic equation does not. the same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step answer

P Answered by Master

6

Algebra uses abstract symbols to represent concrete elements in the real world.Many great mathematicians were also philosophers.The same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step explanation:

Mathematics

Owing as an algebraic expression using x as your unknown variable The difference of three times a number and one.

Step-by-step answer

P Answered by PhD

3x-1

Step-by-step explanation:

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