Subtract equation two 3 digit numbers with different hundreds digits and a difference of less than 100

690 - 595

Step-by-step explanation:

As we know that representation of a 3 digit number = xyz

where x 0

z is at ones place

y is at tens place

x is at hundred place

As, we have to subtract two 3 digits numbers with different hundred digits

So, Let

The hundred digit of first number be 6

The hundred digit of second number be 5

∴

Assume first number with hundred digit 6

Let the number be - 690

Now,

Assume second number with hundred digit 5

Let the number be - 595

Now,

We will check that the difference between both the numbers are less than 100 or not

Now,

690 - 595 = 95 < 100

It satisfies the condition

So, the equation becomes 690 - 595

The three digit number = 951

Step-by-step explanation:

Let suppose the numbers are:

= abc

According to given condition:

a+ b + c = 15  eq1

Also, given the difference between the first two digit = the difference between the last two digits:  

==> l a-b l = l b-cl  

==> (a-b) = (b-c)  

==> (a+c) = 2b

Now we will substitue in eq1

==> a+ b + c = 15

==> 2b + b = 15

==> 3b = 15

Dividing both sides by 3 we get:

b =5

a + c = 2b

a+ c = 10

a = 10 -c (2)

We know that"  

(a-b) = (b-c)

==> a > b+c

==> a > 5 + c

==> 10 -c > 5 +c  

==>5 > 2c

==> 2.5 > c

As c is an odd number so c will be equal to 1

c = 1

a = 10 -1

a = 9

The three digit number = 951

The hundred digit is greater than the sum of the tens and ones digits

i hope it will help you!

The three digit number = 951

Step-by-step explanation:

Let suppose the numbers are:

= abc

According to given condition:

a+ b + c = 15  eq1

Also, given the difference between the first two digit = the difference between the last two digits:  

==> l a-b l = l b-cl  

==> (a-b) = (b-c)  

==> (a+c) = 2b

Now we will substitue in eq1

==> a+ b + c = 15

==> 2b + b = 15

==> 3b = 15

Dividing both sides by 3 we get:

b =5

a + c = 2b

a+ c = 10

a = 10 -c (2)

We know that"  

(a-b) = (b-c)

==> a > b+c

==> a > 5 + c

==> 10 -c > 5 +c  

==>5 > 2c

==> 2.5 > c

As c is an odd number so c will be equal to 1

c = 1

a = 10 -1

a = 9

The three digit number = 951

The hundred digit is greater than the sum of the tens and ones digits

i hope it will help you!

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

The solution is in the following image

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

The answer is in the image