Mathematics : asked on oktacos
 14.04.2023

Subtract equation two 3 digit numbers with different hundreds digits and a difference of less than 100

. 1

Step-by-step answer

24.06.2023, solved by verified expert
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690 - 595

Step-by-step explanation:

As we know that representation of a 3 digit number = xyz

where x Subtract equation two 3 digit numbers with different, №17887830, 14.04.2023 14:03 0

z is at ones place

y is at tens place

x is at hundred place

As, we have to subtract two 3 digits numbers with different hundred digits

So, Let

The hundred digit of first number be 6

The hundred digit of second number be 5

Assume first number with hundred digit 6

Let the number be - 690

Now,

Assume second number with hundred digit 5

Let the number be - 595

Now,

We will check that the difference between both the numbers are less than 100 or not

Now,

690 - 595 = 95 < 100

It satisfies the condition

So, the equation becomes 690 - 595

It is was helpful?

Faq

Mathematics
Step-by-step answer
P Answered by PhD

690 - 595

Step-by-step explanation:

As we know that representation of a 3 digit number = xyz

where x \neq 0

z is at ones place

y is at tens place

x is at hundred place

As, we have to subtract two 3 digits numbers with different hundred digits

So, Let

The hundred digit of first number be 6

The hundred digit of second number be 5

Assume first number with hundred digit 6

Let the number be - 690

Now,

Assume second number with hundred digit 5

Let the number be - 595

Now,

We will check that the difference between both the numbers are less than 100 or not

Now,

690 - 595 = 95 < 100

It satisfies the condition

So, the equation becomes 690 - 595

Mathematics
Step-by-step answer
P Answered by PhD

The three digit number = 951

Step-by-step explanation:

Let suppose the numbers are:

= abc

According to given condition:

a+ b + c = 15  eq1

Also, given the difference between the first two digit = the difference between the last two digits:  

==> l a-b l = l b-cl  

==> (a-b) = (b-c)  

==> (a+c) = 2b

Now we will substitue in eq1

==> a+ b + c = 15

==> 2b + b = 15

==> 3b = 15

Dividing both sides by 3 we get:

b =5

a + c = 2b

a+ c = 10

a = 10 -c (2)

We know that"  

(a-b) = (b-c)

==> a > b+c

==> a > 5 + c

==> 10 -c > 5 +c  

==>5 > 2c

==> 2.5 > c

As c is an odd number so c will be equal to 1

c = 1

a = 10 -1

a = 9

The three digit number = 951

The hundred digit is greater than the sum of the tens and ones digits

i hope it will help you!

Mathematics
Step-by-step answer
P Answered by PhD

The three digit number = 951

Step-by-step explanation:

Let suppose the numbers are:

= abc

According to given condition:

a+ b + c = 15  eq1

Also, given the difference between the first two digit = the difference between the last two digits:  

==> l a-b l = l b-cl  

==> (a-b) = (b-c)  

==> (a+c) = 2b

Now we will substitue in eq1

==> a+ b + c = 15

==> 2b + b = 15

==> 3b = 15

Dividing both sides by 3 we get:

b =5

a + c = 2b

a+ c = 10

a = 10 -c (2)

We know that"  

(a-b) = (b-c)

==> a > b+c

==> a > 5 + c

==> 10 -c > 5 +c  

==>5 > 2c

==> 2.5 > c

As c is an odd number so c will be equal to 1

c = 1

a = 10 -1

a = 9

The three digit number = 951

The hundred digit is greater than the sum of the tens and ones digits

i hope it will help you!

Mathematics
Step-by-step answer
P Answered by Specialist
Hello!

The Correct Answer are:

1. C. 31,536,000 seconds

2. C. 7,700,000

3. 90,000 meters

4. A. 1,260 and 151,200

5. 67 feet

6. B and D

7. 15 x 24 = 360 rings and in another case we have 12 rows and each has 18 rings so in total we have : 12 * 18 = 216 so jewelry store has (360 - 216) rings more than other case so jewelry store has 144 rings more than other case.

8. 23 because 195 + 127 = 322 322/14 = 23

9. B and C

10. We know that 1 hundred= 100= 1*10^2. Therefore, 6,000 hundreds is equal to:
6,000*(1*10^2)= 600,000

Because 600,000 ≠ 6,000,000, Carlos is wrong.

Hope this All Helps! Took me Time!
Have A Wonderful Day! :)
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where F=force

m=mass

a=acceleration

Here,

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