03.11.2021

A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 S

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24.06.2023, solved by verified expert
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Complete Question:

A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 Seconds.

a. what acceleration is imparted to the paper?

b. if the mass of the paper is 0.003 kg, what force does the boxer exert on it?

c. how much force does the paper exert on the boxer?

a. Acceleration = 454.55m/s².

b. Force = 1.36N

c. Force = -1.36N

Step-by-step explanation:

Given the following data;

Final velocity = 20m/s

Time = 0.044 seconds.

Since the paper is at rest, we know that it's initial velocity is equal to 0m/s.

a. To find acceleration;

Mathematically, acceleration is given by the equation;

A boxer punches a sheet of paper in midair and, №17887875, 03.11.2021 07:31

Substituting into the equation, we have;

A boxer punches a sheet of paper in midair and, №17887875, 03.11.2021 07:31

A boxer punches a sheet of paper in midair and, №17887875, 03.11.2021 07:31

Acceleration = 454.55m/s²

b. To find the force exerted by the boxer;

Mass = 0.003kg

Force = mass * acceleration

Force = 0.003 * 454.55

Force = 1.36N

c. To find the force exerted by the paper;

According to Newton's third law of motion which states that, for every action there is an equal and opposite reaction. Therefore, the paper exerts an equal but opposite force on the boxer.

Force = -1.36N

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Physics
Step-by-step answer
P Answered by PhD

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

Physics
Step-by-step answer
P Answered by PhD

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

Mathematics
Step-by-step answer
P Answered by PhD

Complete Question:

A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 Seconds.

a. what acceleration is imparted to the paper?

b. if the mass of the paper is 0.003 kg, what force does the boxer exert on it?

c. how much force does the paper exert on the boxer?

a. Acceleration = 454.55m/s².

b. Force = 1.36N

c. Force = -1.36N

Step-by-step explanation:

Given the following data;

Final velocity = 20m/s

Time = 0.044 seconds.

Since the paper is at rest, we know that it's initial velocity is equal to 0m/s.

a. To find acceleration;

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation, we have;

a = \frac{20 - 0}{0.044}

a = \frac{20}{0.044}

Acceleration = 454.55m/s²

b. To find the force exerted by the boxer;

Mass = 0.003kg

Force = mass * acceleration

Force = 0.003 * 454.55

Force = 1.36N

c. To find the force exerted by the paper;

According to Newton's third law of motion which states that, for every action there is an equal and opposite reaction. Therefore, the paper exerts an equal but opposite force on the boxer.

Force = -1.36N

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

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