Complete Question:
A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 20m/s in 0.044 Seconds.
a. what acceleration is imparted to the paper?
b. if the mass of the paper is 0.003 kg, what force does the boxer exert on it?
c. how much force does the paper exert on the boxer?
a. Acceleration = 454.55m/s².
b. Force = 1.36N
c. Force = -1.36N
Step-by-step explanation:
Given the following data;
Final velocity = 20m/s
Time = 0.044 seconds.
Since the paper is at rest, we know that it's initial velocity is equal to 0m/s.
a. To find acceleration;
Mathematically, acceleration is given by the equation;
Substituting into the equation, we have;
Acceleration = 454.55m/s²
b. To find the force exerted by the boxer;
Mass = 0.003kg
Force = mass * acceleration
Force = 0.003 * 454.55
Force = 1.36N
c. To find the force exerted by the paper;
According to Newton's third law of motion which states that, for every action there is an equal and opposite reaction. Therefore, the paper exerts an equal but opposite force on the boxer.
Force = -1.36N