Mathematics : asked on rschaum08

17.08.2022

If x varies inversely as t, and x = 8 when t = 6, find t when x = 12-
=

0

Step-by-step answer

09.07.2023, solved by verified expert

Chemistry, Q&A Expert, I am a Assistant Professor in Maharaj Singh College Saharanpur, Uttar Pradesh, India

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t = 4

Step-by-step explanation:

given x varies inversely as t , then the equation relating them is

x = ← k is the constant of variation

To find k use the condition x = 8 when t = 6 , then

8 = ( multiply both sides by 6 )

48 = k

x = ← equation of variation

when x = 12 , then

12 = ( multiply both sides by t )

12t = 48 ( divide both sides by 12 )

t = 4

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Mathematics

If x varies inversely as t, and x = 8 when t = 6, find t when x = 12- =

Step-by-step answer

P Answered by Specialist

t = 4

Step-by-step explanation:

given x varies inversely as t , then the equation relating them is

x = $\frac{k}{t}$ ← k is the constant of variation

To find k use the condition x = 8 when t = 6 , then

8 = $\frac{k}{6}$ ( multiply both sides by 6 )

48 = k

x = $\frac{48}{t}$ ← equation of variation

when x = 12 , then

12 = $\frac{48}{t}$ ( multiply both sides by t )

12t = 48 ( divide both sides by 12 )

t = 4

Mathematics

Inverse variation if i varies inversely with r and i = 0.15 when r = 50, which equation should be used to show this relationship? a.i=7.5/r b.i=7.5r c.ir=0.75 d.i=r/7.5 if x varies inversely with y and x = 8 when y = 6, find y when x =10. a. y=40/3 b.y=5/12 c.y = 7.5 d.y = 4.8 xy = –12. what is the constant of variation for this relationship? a.–1.2 b. -1/4 c.–0.12 d.–12 v varies inversely with t and v = 18 when t = 3. which equation shows this relationship? a.v=6/t b.v=6t c.v=54/t d.v=54t the 4 is in the doc.

Step-by-step answer

P Answered by PhD

7

$(1)\\R\cdot I=a\ \ \ \ and\ \ \ 50\cdot 0.15=a\\\\ \ \Rightarrow\ \ \ a=7.5\ \ \ \Rightarrow\ \ I= \frac{7.5}{R} \ \ \ \Rightarrow\ \ \ Ans.\ A.\\\\(2)\\x\cdot y=a\ \ \ and\ \ \ 8\cdot6=a\\\\ \ \Rightarrow\ \ \ a=48\ \Rightarrow\ \ \ xy=48\ \ \ \Rightarrow\ \ \ 10y=48\ \Rightarrow\ \ \ y=4.8\ \Rightarrow\ \ \ Ans.\ D.\\\\(3)\\xy=-12\ \ \Rightarrow\ \ \ constant=-12\ \ \Rightarrow\ \ \ Ans.\ D.\\\\$

$(4)\\xy=-12\\\\e.g.:\ \ \ x=3\ \ and\ \ y=-4\ \ \ \ or\ \ \ \ x=-3\ \ and\ \ y=4\ \ \Rightarrow\ \ Ans.\ A.\\\\(5)\\V\cdot T=a\ \ \ and\ \ \ 18\cdot 3=a\\\\ \ \ \Rightarrow\ \ \ a=54\ \ \ \Rightarrow\ \ \ V\cdot T=54\ \ \ \Rightarrow\ \ \ V= \frac{54}{T} \ \ \ \Rightarrow\ \ \ Ans.\ C.$

Mathematics

Inverse variation if i varies inversely with r and i = 0.15 when r = 50, which equation should be used to show this relationship? a.i=7.5/r b.i=7.5r c.ir=0.75 d.i=r/7.5 if x varies inversely with y and x = 8 when y = 6, find y when x =10. a. y=40/3 b.y=5/12 c.y = 7.5 d.y = 4.8 xy = –12. what is the constant of variation for this relationship? a.–1.2 b. -1/4 c.–0.12 d.–12 v varies inversely with t and v = 18 when t = 3. which equation shows this relationship? a.v=6/t b.v=6t c.v=54/t d.v=54t the 4 is in the doc.

Step-by-step answer

P Answered by PhD

7

$(1)\\R\cdot I=a\ \ \ \ and\ \ \ 50\cdot 0.15=a\\\\ \ \Rightarrow\ \ \ a=7.5\ \ \ \Rightarrow\ \ I= \frac{7.5}{R} \ \ \ \Rightarrow\ \ \ Ans.\ A.\\\\(2)\\x\cdot y=a\ \ \ and\ \ \ 8\cdot6=a\\\\ \ \Rightarrow\ \ \ a=48\ \Rightarrow\ \ \ xy=48\ \ \ \Rightarrow\ \ \ 10y=48\ \Rightarrow\ \ \ y=4.8\ \Rightarrow\ \ \ Ans.\ D.\\\\(3)\\xy=-12\ \ \Rightarrow\ \ \ constant=-12\ \ \Rightarrow\ \ \ Ans.\ D.\\\\$

$(4)\\xy=-12\\\\e.g.:\ \ \ x=3\ \ and\ \ y=-4\ \ \ \ or\ \ \ \ x=-3\ \ and\ \ y=4\ \ \Rightarrow\ \ Ans.\ A.\\\\(5)\\V\cdot T=a\ \ \ and\ \ \ 18\cdot 3=a\\\\ \ \ \Rightarrow\ \ \ a=54\ \ \ \Rightarrow\ \ \ V\cdot T=54\ \ \ \Rightarrow\ \ \ V= \frac{54}{T} \ \ \ \Rightarrow\ \ \ Ans.\ C.$

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Imran is paid ?286 per week Every week he puts 20% of his wage into a savings account How much does he put into his savings each week

Step-by-step answer

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The answer is in the image

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Neil places £2000 in a bank account that pays 1.5% simple interest per year. How much interest will he earn in 6 years?

Step-by-step answer

P Answered by PhD

SI=(P*R*T)/100

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SI=(2000*1.5*6)/100

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Step-by-step answer

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Step-by-step answer

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The solution is in the following image

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Step-by-step answer

P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

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m=F/a

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