Find the lower quartile, upper Quartile and inter quartile range for the data : 9, 11, 15, 19, 17, 13, 7.

On arranging the given data in ascending order of their magnitudes, we get :

➙ 7 , 9 , 11 , 13 , 15 , 17 , 19

Clearly, n = 7, which is an odd number.

★ Lower Quartile (Q¹)

★ Upper Quartile (Q³)

★ Inter-Quartile range

⇒ Q³- Q¹

⇒ 17 - 9

⇒ 8

The answer should be B.

The lower quartile is the one that is  45, the upper quartile is the one on 50, and the interquartile range is the difference between upper and lower quartile, which is 5.

Hope this helps!

The answer should be B.

The lower quartile is the one that is  45, the upper quartile is the one on 50, and the interquartile range is the difference between upper and lower quartile, which is 5.

Hope this helps!

Median = 31

Q1 = 24

Q3 = 38

Interquartile range = 14

Step-by-step explanation:

Let us arrange the data set:

17, 20, 24, 25, 30, 32, 35, 38, 40, 42

There are 10 data points.

The median is the average of the sum of the two middle data:

(30 + 32) / 2 = 62/2 = 31

The lower quartile is given as:

Q1 = (N + 1) * 1/4

Q1 = (10 + 1) * 1/4 = 11 / 4 = 2 3/4

i.e. we have to pick the 3rd data point

Q1 = 24

The upper quartile is given as:

Q3 = (N + 1) * 3/4

Q3 = (10 + 1) * 3/4 = 33/4 = 8 1/4

i.e. we have to pick the 8th data point

Q3 = 38

Interquartile range is given as:

Q3 - Q1 = 38 - 24 = 14