Mathematics : asked on sky81428

30.04.2023

What is the product
3
7

×

2
5
?

0

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09.07.2023, solved by verified expert

Mathematics, DAV Post Graduate College

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6/35

or if u want it like easy to read lol

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Mathematics

What is the product 3 7 × 2 5 ?

Step-by-step answer

P Answered by Master

6/35

or if u want it like easy to read lol

$\frac{6}{35}$

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let me know if I need to explain

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Mathematics

Determine where the decimal point belongs in each product. 1.7 × 2.5 = 425 The decimal point belongs after the . 3.62 × 1.7 = 6154 The decimal point belongs after the .

Step-by-step answer

P Answered by PhD

1

Decimal point in product is the sum of the decimal points in the numbers which we are multiplying.

For ex :

2.6 × 6.7 = 17.42

1 + 1 = 2

For, 1.7 × 2.5 the sum of decimal in each number is 1 and 1 .

So, decimal in product is at 2 i.e 4.25 .

For, 3.62 × 1.7 the sum of decimal in each number is 2 and 1.

Decimal in product is at 2 + 1 = 3 i.e 6.154 .

Therefore, solution is 1.7 × 2.5 = 4.25 and 3.62 × 1.7 = 6.154 .

Hence, this is the required solution.

Mathematics

Determine where the decimal point belongs in each product. 1.7 × 2.5 = 425 The decimal point belongs after the . 3.62 × 1.7 = 6154 The decimal point belongs after the .

Step-by-step answer

P Answered by PhD

1

Decimal point in product is the sum of the decimal points in the numbers which we are multiplying.

For ex :

2.6 × 6.7 = 17.42

1 + 1 = 2

For, 1.7 × 2.5 the sum of decimal in each number is 1 and 1 .

So, decimal in product is at 2 i.e 4.25 .

For, 3.62 × 1.7 the sum of decimal in each number is 2 and 1.

Decimal in product is at 2 + 1 = 3 i.e 6.154 .

Therefore, solution is 1.7 × 2.5 = 4.25 and 3.62 × 1.7 = 6.154 .

Hence, this is the required solution.

Mathematics

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Step-by-step answer

P Answered by Master

1

Step-by-step explanation:

The complete solution is given in attachment below.

As part 4 and 5 is not clear in question so I have solved with 2 different data.

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Mathematics

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Step-by-step answer

P Answered by Master

1

Step-by-step explanation:

The complete solution is given in attachment below.

As part 4 and 5 is not clear in question so I have solved with 2 different data.

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Find each product 5/6 × 10, 3/7 × 2/3, 5/8 × 2/3, 3 3/4 × 2 2/3, 2 5/6 × 1 7/8 answer all

Chemistry

In a solution of pure water, the dissociation of water can be expressed by the following: h2o(l) + h2o(l) ⇌ h3o+(aq) + oh−(aq) the equilibrium constant for the ionization of water, kw, is called the ion-product of water. in pure water at 25 °c, kw has a value of 1.0 × 10−14. the dissociation of water gives one h3o+ ion and one oh− ion and thus their concentrations are equal. the concentration of each is 1.0 × 10−7 m. kw = [h3o+][oh−] kw = (1.0 × 10-7)(1.0 × 10-7) = 1.0 × 10-14 [h3o+][oh−] = 1.0 × 10-14 a solution has a [oh−] = 3.4 × 10−5 m at 25

Step-by-step answer

P Answered by PhD

[H₃O⁺] = 2.90 × 10⁻¹⁰ M

Explanation:

1) Ionization equilibrium equation: given

H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

2) Ionization equilibrium constant, at 25°C, Kw: given

Kw = 1.0 × 10⁻¹⁴

3) Stoichiometric mole ratio:

As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:

[H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M ⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷ × 1.0 × 10⁻⁷ = 1.0 × 10⁻¹⁴ M

4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C and you need to calculate what the [H₃O⁺(aq)] is.

Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:

Kw = 1.0 × 10⁻¹⁴ M², and Kw = [H3O⁺] [OH⁻]

Then you can substitute the known values and solve for the unknown:

1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M ⇒ [H₃O⁺] = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.

Chemistry

In a solution of pure water, the dissociation of water can be expressed by the following: h2o(l) + h2o(l) ⇌ h3o+(aq) + oh−(aq) the equilibrium constant for the ionization of water, kw, is called the ion-product of water. in pure water at 25 °c, kw has a value of 1.0 × 10−14. the dissociation of water gives one h3o+ ion and one oh− ion and thus their concentrations are equal. the concentration of each is 1.0 × 10−7 m. kw = [h3o+][oh−] kw = (1.0 × 10-7)(1.0 × 10-7) = 1.0 × 10-14 [h3o+][oh−] = 1.0 × 10-14 a solution has a [oh−] = 3.4 × 10−5 m at 25

Step-by-step answer

P Answered by PhD

[H₃O⁺] = 2.90 × 10⁻¹⁰ M

Explanation:

1) Ionization equilibrium equation: given

H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

2) Ionization equilibrium constant, at 25°C, Kw: given

Kw = 1.0 × 10⁻¹⁴

3) Stoichiometric mole ratio:

As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:

[H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M ⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷ × 1.0 × 10⁻⁷ = 1.0 × 10⁻¹⁴ M

4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C and you need to calculate what the [H₃O⁺(aq)] is.

Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:

Kw = 1.0 × 10⁻¹⁴ M², and Kw = [H3O⁺] [OH⁻]

Then you can substitute the known values and solve for the unknown:

1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M ⇒ [H₃O⁺] = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.

Mathematics

Lesson 6 homework practice the distributive property find each product mentally. show the steps you used. 1. 8 × 34 2. 5 × 47 3. 12 × 4 3 − 4 4. 8 × 3 3 − 4 5. 6 × 4.4 6. 7 × 2.9 use the distributive property to rewrite each algebraic expression. 7. 6(n + 4) 8. 15(2 + r) 9. 8(s + 5) 10. 3(b + 8) 11. 5(6 + b) 12. 9(3 + v) 13. 7(r - 7) 14. 12(4 - v) 15. 11(3 - s) 16. movies use the table that shows the prices of tickets and various food items at the movie theater. a. four friends each bought a ticket and a bag of popcorn. how much total money did

Step-by-step answer

P Answered by PhD

12

Products: Each product can be mentally solved, we need to multiply each factor by the units digit and then add it to the product with the tenths, as follows

1. $8 \times 34 \implies (8\times 4)+ (8 \times 30)=32+240=272$

2. $5 \times 47 = (5 \times 7)+ (5 \times 40)=35+200=235$

3. $12 \times 43= (12 \times 3)+(12 \times 40)=36+480=516$

4. $8 \times 33=(8 \times 3) + (8 \times 30)=24+240=264$

5. $6 \times 4.4=60 \times 44=(60 \times 4)+(60 \times 40)=240+2400=2640 \implies 26.40$

6. $7 \times 2.9= 70 \times 29=(70 \times +9)+(70 \times 20)=630+1400=2030 \implies 20.30$

Distributive property: Remember, distributive property is about "distributing" the outside factor with each term in side the parenthesis, as follows

7. $6(n+4)=6\times n + 6\times 4=6n+24$

8. $15(2+r)=15 \times 2 + 15 \times r=30+15r$

9. $8(s+5)=8 \times s + 8 \times 5= 8s+40$

10. 3(b+8)=3b+24

11. 5(6+b)=60+5b

12. 9(3+v)=27+9v

13. 7(r-7)=7r-49

14. 12(4-v)=48-12v

15. 11(3-s)=33-3s

The given table shows the prices. Ticket $8.50, Popcorn $5.25, Soda $4.00, Candy $3.75 and Nachos $6.

a. Each of four bought a tickets and a bag of popcorn, the money spent is

$4(tickets)+4(popcorn)=4(8.50)+4(5.25)=34+21=\$55$

They spend $55 in total.

b. 12 kids buy a box of candy and a soda.

$12(candy)+12(soda)=12(3.75)+12(4)=45+48=\$93$

They spent $93 in total.

c. The difference between three orders of nachos and three bags of popcorn.

$3(nachos)-3(popcorn)=3(6)-3(5.25)=18-15.75=\$2.25$

So, the difference between both orders is $2.25.

Mathematics

Lesson 6 homework practice the distributive property find each product mentally. show the steps you used. 1. 8 × 34 2. 5 × 47 3. 12 × 4 3 − 4 4. 8 × 3 3 − 4 5. 6 × 4.4 6. 7 × 2.9 use the distributive property to rewrite each algebraic expression. 7. 6(n + 4) 8. 15(2 + r) 9. 8(s + 5) 10. 3(b + 8) 11. 5(6 + b) 12. 9(3 + v) 13. 7(r - 7) 14. 12(4 - v) 15. 11(3 - s) 16. movies use the table that shows the prices of tickets and various food items at the movie theater. a. four friends each bought a ticket and a bag of popcorn. how much total money did

Step-by-step answer

P Answered by PhD

12

Products: Each product can be mentally solved, we need to multiply each factor by the units digit and then add it to the product with the tenths, as follows

1. $8 \times 34 \implies (8\times 4)+ (8 \times 30)=32+240=272$

2. $5 \times 47 = (5 \times 7)+ (5 \times 40)=35+200=235$

3. $12 \times 43= (12 \times 3)+(12 \times 40)=36+480=516$

4. $8 \times 33=(8 \times 3) + (8 \times 30)=24+240=264$

5. $6 \times 4.4=60 \times 44=(60 \times 4)+(60 \times 40)=240+2400=2640 \implies 26.40$

6. $7 \times 2.9= 70 \times 29=(70 \times +9)+(70 \times 20)=630+1400=2030 \implies 20.30$

Distributive property: Remember, distributive property is about "distributing" the outside factor with each term in side the parenthesis, as follows

7. $6(n+4)=6\times n + 6\times 4=6n+24$

8. $15(2+r)=15 \times 2 + 15 \times r=30+15r$

9. $8(s+5)=8 \times s + 8 \times 5= 8s+40$

10. 3(b+8)=3b+24

11. 5(6+b)=60+5b

12. 9(3+v)=27+9v

13. 7(r-7)=7r-49

14. 12(4-v)=48-12v

15. 11(3-s)=33-3s

The given table shows the prices. Ticket $8.50, Popcorn $5.25, Soda $4.00, Candy $3.75 and Nachos $6.

a. Each of four bought a tickets and a bag of popcorn, the money spent is

$4(tickets)+4(popcorn)=4(8.50)+4(5.25)=34+21=\$55$

They spend $55 in total.

b. 12 kids buy a box of candy and a soda.

$12(candy)+12(soda)=12(3.75)+12(4)=45+48=\$93$

They spent $93 in total.

c. The difference between three orders of nachos and three bags of popcorn.

$3(nachos)-3(popcorn)=3(6)-3(5.25)=18-15.75=\$2.25$

So, the difference between both orders is $2.25.

Chemistry

What is the molar solubility of calcium carbonate ( CaCO3 ) in water? The solubility-product constant for CaCO3 is 4.5 × 10-9 at 25 °C. A) 8.35 B) 9.5 × 10-5 C) 9.0 × 10-9 D) 2.3 × 10-9 E) 6.7 × 10-5

Step-by-step answer

P Answered by PhD

1

Option E)

$6.7\times 10^{-5}M$

Explanation:

1. Write the solubility equation:

CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻

2. Write the concentrations below the equation:

CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻

A - s s s

3. Write the Ksp equation:

Ksp = [Ca²⁺] . [CO₃²⁻] ↔ the solid substances do not appearKsp = s × s4.5 × 10⁻⁹ = s²

4. Solve the equation:

$s=\sqrt{4.5\times 10^{-9}M^2}=6.7\times 10^{-5}M$

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