5 red, 4 green, and 3 blue marbles. A bag contains, №18010149, 02.02.2022 21:42

Mathematics

Abag contains 5 red,4 green, and 3 blue marbles. what is the probability of randomly selecting a blue marble, replacing it in the bag, and then randomly selecting a red marble a. 1/48 b. 1/12 c.5/48 d.5/12

Step-by-step answer

P Answered by PhD

50

C. 5/48

There are 12 marbles in the bag total. 3/12, or 1/4 marbles are blue. 5/12 marbles are red.

Multiply these two probabilities together to get 5/48. There’s the answer.

Please consider marking this answer as Brainliest to help me advance.

Mathematics

Abag contains 5 red,4 green, and 3 blue marbles. what is the probability of randomly selecting a blue marble, replacing it in the bag, and then randomly selecting a red marble a. 1/48 b. 1/12 c.5/48 d.5/12

Step-by-step answer

P Answered by PhD

50

C. 5/48

There are 12 marbles in the bag total. 3/12, or 1/4 marbles are blue. 5/12 marbles are red.

Multiply these two probabilities together to get 5/48. There’s the answer.

Please consider marking this answer as Brainliest to help me advance.

Mathematics

5 red, 4 green, and 3 blue marbles. A bag contains 5 red, 4 green, and 3 blue marbles. What is the probability of randomly selecting a blue marble, replacing it in the bag, and then randomly selecting a red marble? StartFraction 1 over 48 EndFraction StartFraction 1 over 12 EndFraction StartFraction 5 over 48 EndFraction StartFraction 5 over 12 EndFraction

Step-by-step answer

P Answered by Master

$\frac{1}{4}$

$\frac{3}{12}$

25%

Mathematics

Abag contains 5 red 3 green 4 blue and 8 yellow marbles find the probability of randomly selecting a green marble and then a yellow marble if the first marble is replaced

Step-by-step answer

P Answered by Master

4

The probability of picking a green marble the first time is 3/20 and the probability of picking a yellow marble the second time is 8/20.
probabilities are heavily related to percents so it would make sense that the probability of picking a color would be the number of that color divided by the total number.

note that it is really important that the problem said that the marble was replaced. If the marble was not replaced, the probability of picking a yellow marble the second time would be 8/19 if the first marble picked was not a yellow one.

I hope this helps.

Mathematics

Aspinner is divided into nine equal sections numbered 1 through 9. predict how many times out of 270 spins the spinner is most likely to stop on an odd number. question 1 options: 70 150 200 240 rowan has a bag containing 20 marbles. the table below shows the number of marbles of each color in the bag. as part of a probability experiment for his math class, rowan randomly picks a marble from the bag and then replaces it. he repeats this 200 times. predict the number of times out of 200 rowan will pick a blue marble. question 2 options: 5 50 135

Step-by-step answer

P Answered by Specialist

34

Question 1: 150

Question 2: 50

Question 3: 58% chance

Question 4: Choosing a set of parallel side on a polygon.

Question 5: 1/6

Question 6: 1/5

Question 7: ?

Question 8: Rolling a number greater than 1

Question 9: 1/12

Question 10: 30

Question 11: ?

Question 12: A green marble is selected.

Hope I helped I tried as much as possible.

Mathematics

Aspinner is divided into nine equal sections numbered 1 through 9. predict how many times out of 270 spins the spinner is most likely to stop on an odd number. question 1 options: 70 150 200 240 rowan has a bag containing 20 marbles. the table below shows the number of marbles of each color in the bag. as part of a probability experiment for his math class, rowan randomly picks a marble from the bag and then replaces it. he repeats this 200 times. predict the number of times out of 200 rowan will pick a blue marble. question 2 options: 5 50 135

Step-by-step answer

P Answered by Specialist

34

Question 1: 150

Question 2: 50

Question 3: 58% chance

Question 4: Choosing a set of parallel side on a polygon.

Question 5: 1/6

Question 6: 1/5

Question 7: ?

Question 8: Rolling a number greater than 1

Question 9: 1/12

Question 10: 30

Question 11: ?

Question 12: A green marble is selected.

Hope I helped I tried as much as possible.

Mathematics

Abag contains 3 red marbles, 2 blue marbles, and 5 green marbles. what is the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble? a. 1/9 b. 1/6 c. 7/10 d. 4/5

Step-by-step answer

P Answered by Specialist

17

The answer to this is A.) 1/9.

The answer was found as follows:

1. Count all of the total probabilities, make it the denominator of your fraction under your favorable possibilities. In this case, you favorable possibility would be the marble you select, so lets start with the blue marble. But, we would repeat this with the other color later. Now, we have 2/10, or 1/5.

2. After you set up your proportion, do the same for the next marble color. The only difference this time is that because you did not replace that one marble you might've picked up before, your denominator would be nine, subtracting that one marble from your total possibilities. Now you would put your total green marbles over your total possibilities. You should get 5/9.

3. Now, set up both the proportions so you multiply them together, 1/5 x 5/9.

4. Your number now should be 5/45, but we will simplify it to get our final answer of 1/9.

Mathematics

4.) a bag contains 10 red marbles and 5 blue marbles. you randomly select 3 marbles from the bag. what is the probability that all 3 marbles are blue when (a) you replace each marble before selecting the next one and (b) you do not replace each marble before selecting the next one?

Step-by-step answer

P Answered by PhD

1

a) 1/27

b) 2/91

Step-by-step explanation:

A bag contains 10 red marbles and 5 blue marbles (15 marbles in total). You randomly select 3 marbles from the bag.

a) You replace each marble before selecting the next one.

The probability of selecting one blue marble is

$\dfrac{5}{15}=\dfrac{1}{3},$

then the probability that all 3 marbles are blue is

$\dfrac{1}{3}\times \dfrac{1}{3}\times \dfrac{1}{3}=\dfrac{1}{27}$

b) You do not replace each marble before selecting the next one. Each time the number of blue marbles decreases by 1 and the total number of marbles decreases by 1 too. So the probability that all 3 marbles are blue is

$\dfrac{5}{15}\times \dfrac{4}{14}\times \dfrac{3}{13}=\dfrac{2}{91}$

Mathematics

Abag contains 3 red marbles, 2 blue marbles, and 5 green marbles. what is the probability of randomly selecting a blue marble, then without replacing it, randomly selecting a green marble? a. 1/9 b. 1/6 c. 7/10 d. 4/5

Step-by-step answer

P Answered by Master

17

The answer to this is A.) 1/9.

The answer was found as follows:

1. Count all of the total probabilities, make it the denominator of your fraction under your favorable possibilities. In this case, you favorable possibility would be the marble you select, so lets start with the blue marble. But, we would repeat this with the other color later. Now, we have 2/10, or 1/5.

2. After you set up your proportion, do the same for the next marble color. The only difference this time is that because you did not replace that one marble you might've picked up before, your denominator would be nine, subtracting that one marble from your total possibilities. Now you would put your total green marbles over your total possibilities. You should get 5/9.

3. Now, set up both the proportions so you multiply them together, 1/5 x 5/9.

4. Your number now should be 5/45, but we will simplify it to get our final answer of 1/9.

Mathematics

Imran is paid ?286 per week Every week he puts 20% of his wage into a savings account How much does he put into his savings each week

Step-by-step answer

P Answered by PhD

The answer is in the image

Step-by-step answer

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