0Problem 1
The roots are x = 0, x = 2, x = -3
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Explanation:
The term "root" is another way of saying "zeros of a function" or "x intercept".
To find the roots, set each factor equal to zero and solve for x.
x-2 = 0 solves to x = 2, while x+3 = 0 solves to x = -3
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Problem 2
Roots are x = 1, 
and 
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Explanation:
Factor by grouping
x^3 - x^2 + 5x - 5 = 0
(x^3 - x^2) + (5x - 5) = 0
x^2(x - 1) + 5(x - 1) = 0
(x^2 + 5)(x - 1) = 0
x^2 + 5 = 0 solves to the roots and
x-1 = 0 solves to x = 1
Note: 
1) Wat are the real zeros of the function y=x(x-2)(x+3):
To find the x-intercept, set y = 0:
x( x -2 ) ( x + 3) = 0
Apply the Zero Product Property:
x - 2 = 0 or x + 3 = 0
x = 2 or x = -3
Find the union of solutions:
x = 0 or x = 2 or x = -3
2) Find all of the solutions of the equation
x^3 -x^2 +5x - 5 = 0
x = 1 or no real solution
Apply grouping:
Factor out common factor:
Factor out --> 
Apply zero product property:
or 
x - 1 = 0
Rearrange variables to the left side of the equation--> x=1 or no real solutions.
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