19.10.2021

What is x?
5x - 1 = - 8

. 0

Step-by-step answer

09.07.2023, solved by verified expert
Unlock the full answer

x = -1.4, -7/5, or -1 2/5 (all same answer, just in different forms)

Step-by-step explanation:

Step 1: Add 1 to both sides.

What is x? 5x - 1 = - 8, №18010280, 19.10.2021 13:15What is x? 5x - 1 = - 8, №18010280, 19.10.2021 13:15

Step 2: Divide both sides by 5.

What is x? 5x - 1 = - 8, №18010280, 19.10.2021 13:15x = -1.4, -7/5, or -1 2/5.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

It is was helpful?

Faq

Mathematics
Step-by-step answer
P Answered by Specialist

x = -1.4, -7/5, or -1 2/5 (all same answer, just in different forms)

Step-by-step explanation:

Step 1: Add 1 to both sides.

5x-1+1=-8+15x=-7

Step 2: Divide both sides by 5.

5x/5=-7/5x = -1.4, -7/5, or -1 2/5.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

Mathematics
Step-by-step answer
P Answered by Master

  Solved.


Step-by-step explanation: The calculations are as follows -

(12) Given zeroes are 5, -3 and -1 + 3i. So, the other conjugate of -1 + 3i, i.e., -1 - 3i will also be a root of the polynomial. So the polynomial f(x) will be of degree 4 and is given by

f(x)=(x-5)(x+3)(x+1-3i)(x+1+3i)\\\\\Rightarrow f(x)=(x^2-2x-15)(x^2+2x+1-9i^2)\\\\\Rightarrow f(x)=(x^2-2x-15)(x^2+2x+10)\\\\\Rightarrow f(x)=x^4-9x^2-50x-150.

(13) Given polynomial is

f(x)=x^3-7x^2+9x-24.

Now, we will substitute the rational numbers in place of 'x' and check whether the value of f(x) becomes zero or not.

We will see that

f(-1)\neq 0,~~f(1)\neq 0,~~f(2)\neq 0,~~f(-2)\neq 0, ~~f(3)\neq 0, ~~f(-3)\neq 0,~~etc

Also, the polynomial is not zero for any rational number.

(14) Given, f(x)=7x+6~~\textup{and}~~g(x) = 4x^2.

So,

(f+g)(x)=f(x)+g(x)=7x+6+4x^2.

Thus, the problems are solved.

Mathematics
Step-by-step answer
P Answered by Specialist

Q1 - D. f(x) = x^4-9x^2-50x-150

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. 7x+6+4x^{2}

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is (x-5)(x+3)(x+1-3i)(x+1+3i)=0

i.e. (x^2-2x-15)(x+1-3i)(x+1+3i)=0

i.e. (x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0

i.e. x^4-9x^2-50x-150=0

Hence, the polynomial function is f(x)=x^4-9x^2-50x-150.

Question 13:  

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if \frac{p}{q} is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, \frac{p}{q} is a zero of x^3-7x^2+9x-24=0. Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of \frac{p}{q} are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = 4x^{2}

Then, (f+g)(x) = f(x) + g(x) =  7x + 6 + 4x^{2}

So, (f+g)(x) = 7x+6+4x^{2}

Mathematics
Step-by-step answer
P Answered by Specialist

Q1 - D. f(x) = x^4-9x^2-50x-150

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. 7x+6+4x^{2}

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is (x-5)(x+3)(x+1-3i)(x+1+3i)=0

i.e. (x^2-2x-15)(x+1-3i)(x+1+3i)=0

i.e. (x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0

i.e. x^4-9x^2-50x-150=0

Hence, the polynomial function is f(x)=x^4-9x^2-50x-150.

Question 13:  

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if \frac{p}{q} is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, \frac{p}{q} is a zero of x^3-7x^2+9x-24=0. Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of \frac{p}{q} are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = 4x^{2}

Then, (f+g)(x) = f(x) + g(x) =  7x + 6 + 4x^{2}

So, (f+g)(x) = 7x+6+4x^{2}

Mathematics
Step-by-step answer
P Answered by Specialist

  Solved.


Step-by-step explanation: The calculations are as follows -

(12) Given zeroes are 5, -3 and -1 + 3i. So, the other conjugate of -1 + 3i, i.e., -1 - 3i will also be a root of the polynomial. So the polynomial f(x) will be of degree 4 and is given by

f(x)=(x-5)(x+3)(x+1-3i)(x+1+3i)\\\\\Rightarrow f(x)=(x^2-2x-15)(x^2+2x+1-9i^2)\\\\\Rightarrow f(x)=(x^2-2x-15)(x^2+2x+10)\\\\\Rightarrow f(x)=x^4-9x^2-50x-150.

(13) Given polynomial is

f(x)=x^3-7x^2+9x-24.

Now, we will substitute the rational numbers in place of 'x' and check whether the value of f(x) becomes zero or not.

We will see that

f(-1)\neq 0,~~f(1)\neq 0,~~f(2)\neq 0,~~f(-2)\neq 0, ~~f(3)\neq 0, ~~f(-3)\neq 0,~~etc

Also, the polynomial is not zero for any rational number.

(14) Given, f(x)=7x+6~~\textup{and}~~g(x) = 4x^2.

So,

(f+g)(x)=f(x)+g(x)=7x+6+4x^2.

Thus, the problems are solved.

Mathematics
Step-by-step answer
P Answered by PhD
If it has the roots -1,2, and 4 it is:

(x+1)(x-2)(x-4)

(x^2-x-2)(x-4)

x^3-4x^2-x^2+4x-2x+8

x^3-5x^2_2x+8

Only C is equal to the equation with the roots provided and it is of degree 3
Mathematics
Step-by-step answer
P Answered by PhD
If it has the roots -1,2, and 4 it is:

(x+1)(x-2)(x-4)

(x^2-x-2)(x-4)

x^3-4x^2-x^2+4x-2x+8

x^3-5x^2_2x+8

Only C is equal to the equation with the roots provided and it is of degree 3

Try asking the Studen AI a question.

It will provide an instant answer!

FREE