Mathematics : asked on jojokeys
 14.05.2022

Y=1.5283e^0.011x when x = 2020

. 1

Step-by-step answer

09.07.2023, solved by verified expert

Faq

Mathematics
Step-by-step answer
P Answered by Specialist

This is the answer, and I'm not very sure of it


Y=1.5283e^0.011x when x = 2020
Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

tip=18% of 75.45

     =18/100 * 75.45 = $13.581

Tip = $13.581

Mathematics
Step-by-step answer
P Answered by PhD

Area of rectangle= L*b

here,

L=12.4 cm

b= 8.8 cm

A= L*b

= 12.4 * 8.8 = 109.12 cm^2

Mathematics
Step-by-step answer
P Answered by PhD

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years

Try asking the Studen AI a question.

It will provide an instant answer!

FREE