07.02.2021

What is the solution to the system of linear equations?

2x + y = 7

x - 2y = 16

. 0

Step-by-step answer

09.07.2023, solved by verified expert
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Step-by-step explanation:

Reform the first equation: y = 7 - 2x; y = -2x + 7Reform the second equation: -2y = -x + 16; y = 0.5x + 8Equate: -2x + 7 = 0.5x + 8; -4x + 14 = x + 16; -3x + 14 = 16; -3x = 2; x = -What is the solution to the system of linear, №18010567, 07.02.2021 17:58Calculate y: y = -2 * - 2/3 + 7 = 4/3 + 7; y = What is the solution to the system of linear, №18010567, 07.02.2021 17:58Define S(What is the solution to the system of linear, №18010567, 07.02.2021 17:58)
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Mathematics
Step-by-step answer
P Answered by Specialist

Step-by-step explanation:

Reform the first equation: y = 7 - 2x; y = -2x + 7Reform the second equation: -2y = -x + 16; y = 0.5x + 8Equate: -2x + 7 = 0.5x + 8; -4x + 14 = x + 16; -3x + 14 = 16; -3x = 2; x = -\frac{2}{3}Calculate y: y = -2 * - 2/3 + 7 = 4/3 + 7; y = \frac{25}{3}Define S(-\frac{2}{3} ; \frac{25}{3})
Mathematics
Step-by-step answer
P Answered by PhD

(6, -5)  (Answer C)

Step-by-step explanation:

Multiply the first equation by 2.  We get the following equivalent system:

4x + 2y = 14

 x - 2y  = 16

  5x = 30, or x = 6.

Substituting 6 for x in the second equation, we get

6 - 2y = 16, or

  -  2y = 10, so that y = -5

and the solution is (6, -5)  (Answer C)

Mathematics
Step-by-step answer
P Answered by Specialist

(6,-5)

Step-by-step explanation:

I used a graphing tool to graph the system. When graphed, the lines cross at point (6, -5). Therefore, the solution to the system of linear equations is (6,-5).


What is the solution to the system of linear equations?

2x + y = 7
x - 2y = 16
(4.-1)
(-1.9)
16.-5)
Mathematics
Step-by-step answer
P Answered by PhD

(6, -5)  (Answer C)

Step-by-step explanation:

Multiply the first equation by 2.  We get the following equivalent system:

4x + 2y = 14

 x - 2y  = 16

  5x = 30, or x = 6.

Substituting 6 for x in the second equation, we get

6 - 2y = 16, or

  -  2y = 10, so that y = -5

and the solution is (6, -5)  (Answer C)

Mathematics
Step-by-step answer
P Answered by PhD

1) C s=\left \{ (-2,-9) \right \}2) (-2,0) 3)S=\left \{ (14,10) \right \}4) S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \} 5) c )S={(0,3)} 6) (0,2) 7) A) S=\left \{ \left ( 1,4 \right ) \right \}8) Missing graph 9) Vertical line (check below) 10) B 11)

Step-by-step explanation:

1) Solving by the Addition/Elimination Method. Firstly, let's reduce one variable by making some algebraic adjustments and then adding it up:

\left\{\begin{matrix}-2x&+y&=5 *(3)\\ 3x&-2y&=12 *(2)\end{matrix}\right.\Rightarrow \left\{\begin{matrix}-6x&+3y&=15  \\6x&-4y&=24 \end{matrix}\right.\Rightarrow -y=9\Rightarrow y=-9\Rightarrow 6x-4(-9)=24\Rightarrow 6x+36=24\Rightarrow 6x=-36+24\Rightarrow 6x=-12\Rightarrow x=-2\Rightarrow s=\left \{ -2,-9 \right \}

2) Solving by Substitution Method. Where y=x+2 is plugged in the 2nd equation.

\left\{\begin{matrix}y =&x+2 & \\ 2x-y &=-4 & \end{matrix}\right.\Rightarrow 2x-(x+2)=-4\Rightarrow 2x-x-2=-4\Rightarrow x=-4+2\Rightarrow x=-2\: and\: y=-2+2\Rightarrow y=0\Rightarrow S=\left \{ \left ( -2,0 \right ) \right \}

3) Solving it, again, by the Substitution Method due to the I equation form:

\left\{\begin{matrix}x=y+4& \\ 2x-3y=-2& \end{matrix}\right.\Rightarrow 2(y+4)-3y=-2\Rightarrow 2y+8-3y=-2\Rightarrow y=10\: \: x=10+4\Rightarrow x=14\Rightarrow S=\left \{ (14,10) \right \}

4) By the Addition Method

\left\{\begin{matrix}x+2y &=3 \\ 3x-2y &=5 \end{matrix}\right.\Rightarrow 4x=8\Rightarrow x=2\Rightarrow 2+2y=3\Rightarrow 2y=1\Rightarrow y=\frac{1}{2}\: S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}

5) To use the graph method to solve the system of Linear equations is possible by graphing each equation on the Cartesian Plane.

Check the graph below, this system has only one solution.

c)S={(0,3)}

6) Solving y=-1/3x+2 y=x+2

(Check the graph below)

A) A) (0, 2)

7) Solving by Substitution Method:

\left\{\begin{matrix}x=y-3 & \\ x+3y=13& \end{matrix}\right.\Rightarrow y-3+3y=13\Rightarrow 4y=13+3\Rightarrow 4y=16\Rightarrow y=4\: \: \\x=4-3\Rightarrow x=1 \\S=\left \{ \left ( 1,4 \right ) \right \}

8) Missing graph

9)

\frac{1}{2}x+x=1+2\Rightarrow \frac{3}{2}x=3\Rightarrow x=2\\ S=\{2}\\

Check the graph below its answer

10) Solving by the Addition Method

\left\{\begin{matrix}x+3y=5 & \\ -x+6y=4& \end{matrix}\right.\Rightarrow 9y=9\Rightarrow y=1  \: \: And \: \: x+3(1)=5\Rightarrow x=5-3\Rightarrow x=2\\S=\left \{ \left ( 2,1 \right ) \right \}

11) Sorry, missing graph for the question.

12) Sorry, missing graph for the question.

13) D Check the graph below

14) Sorry, missing graph for the question.


1)  what is the solution to the system of equations?  -2x + y = -5 3x – 2y = 12 a) (3, 1)  b) (6, 3)
Mathematics
Step-by-step answer
P Answered by PhD

1) C s=\left \{ (-2,-9) \right \}2) (-2,0) 3)S=\left \{ (14,10) \right \}4) S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \} 5) c )S={(0,3)} 6) (0,2) 7) A) S=\left \{ \left ( 1,4 \right ) \right \}8) Missing graph 9) Vertical line (check below) 10) B 11)

Step-by-step explanation:

1) Solving by the Addition/Elimination Method. Firstly, let's reduce one variable by making some algebraic adjustments and then adding it up:

\left\{\begin{matrix}-2x&+y&=5 *(3)\\ 3x&-2y&=12 *(2)\end{matrix}\right.\Rightarrow \left\{\begin{matrix}-6x&+3y&=15  \\6x&-4y&=24 \end{matrix}\right.\Rightarrow -y=9\Rightarrow y=-9\Rightarrow 6x-4(-9)=24\Rightarrow 6x+36=24\Rightarrow 6x=-36+24\Rightarrow 6x=-12\Rightarrow x=-2\Rightarrow s=\left \{ -2,-9 \right \}

2) Solving by Substitution Method. Where y=x+2 is plugged in the 2nd equation.

\left\{\begin{matrix}y =&x+2 & \\ 2x-y &=-4 & \end{matrix}\right.\Rightarrow 2x-(x+2)=-4\Rightarrow 2x-x-2=-4\Rightarrow x=-4+2\Rightarrow x=-2\: and\: y=-2+2\Rightarrow y=0\Rightarrow S=\left \{ \left ( -2,0 \right ) \right \}

3) Solving it, again, by the Substitution Method due to the I equation form:

\left\{\begin{matrix}x=y+4& \\ 2x-3y=-2& \end{matrix}\right.\Rightarrow 2(y+4)-3y=-2\Rightarrow 2y+8-3y=-2\Rightarrow y=10\: \: x=10+4\Rightarrow x=14\Rightarrow S=\left \{ (14,10) \right \}

4) By the Addition Method

\left\{\begin{matrix}x+2y &=3 \\ 3x-2y &=5 \end{matrix}\right.\Rightarrow 4x=8\Rightarrow x=2\Rightarrow 2+2y=3\Rightarrow 2y=1\Rightarrow y=\frac{1}{2}\: S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}

5) To use the graph method to solve the system of Linear equations is possible by graphing each equation on the Cartesian Plane.

Check the graph below, this system has only one solution.

c)S={(0,3)}

6) Solving y=-1/3x+2 y=x+2

(Check the graph below)

A) A) (0, 2)

7) Solving by Substitution Method:

\left\{\begin{matrix}x=y-3 & \\ x+3y=13& \end{matrix}\right.\Rightarrow y-3+3y=13\Rightarrow 4y=13+3\Rightarrow 4y=16\Rightarrow y=4\: \: \\x=4-3\Rightarrow x=1 \\S=\left \{ \left ( 1,4 \right ) \right \}

8) Missing graph

9)

\frac{1}{2}x+x=1+2\Rightarrow \frac{3}{2}x=3\Rightarrow x=2\\ S=\{2}\\

Check the graph below its answer

10) Solving by the Addition Method

\left\{\begin{matrix}x+3y=5 & \\ -x+6y=4& \end{matrix}\right.\Rightarrow 9y=9\Rightarrow y=1  \: \: And \: \: x+3(1)=5\Rightarrow x=5-3\Rightarrow x=2\\S=\left \{ \left ( 2,1 \right ) \right \}

11) Sorry, missing graph for the question.

12) Sorry, missing graph for the question.

13) D Check the graph below

14) Sorry, missing graph for the question.


1)  what is the solution to the system of equations?  -2x + y = -5 3x – 2y = 12 a) (3, 1)  b) (6, 3)
Mathematics
Step-by-step answer
P Answered by Specialist

here ya go

Sponsored by calderonj4588pics.org


Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Mathematics
Step-by-step answer
P Answered by Specialist

here ya go

Sponsored by calderonj4588pics.org


Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Write the linear system of equations

as a
single matrix equation.
x - 2y - 5z = -1
y + 2x + 2z = 7
Mathematics
Step-by-step answer
P Answered by Master

Answer with explanation:

1. x+0=x

0 is the identity element.When number is added to identity the resultant is number.

Option D : Identity

2.

3x-2=60

Adding 2 on both sides

→3x-2+2=60+2

→3x=62

Dividing by 3, on both sides

x=\frac{62}{3}

Option (B.)→ Add 2 . Divide by 3

3.

y> -2,

y=(-2, Infinity)

So, -3 is not the solution of ,y>-2.

Option A: False

4.

The equation in slope-intercept form, is, y = mx + b.

4x-2y=10

4x=2y+10

2y=4x-10

Dividing by 2, on both sides

y=2x-5

Option A:→y=2x-5

5.

The equation of line is

 y=2x-11

We have to check whether point (3,0) lies on the line or not.

LHS=y=0

RHS=2x-11

       =2 ×3-11

       =6-11

       = -5

So, point (3,0) does not lie on the line,→y=2x-11.

Option B : False

6.

Slope of line joining the points (-2,-1) and (3,4) is

 m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m=\frac{4+1}{3-(-2)}\\\\m=\frac{5}{5}\\\\m=1

Slope=1

Option A

7.

When solving a system of equations, you are finding the

Option C: Intersection point

8.

3x + 2y = 10------(1) \\\\2x + 3y = \frac{15}{12}-----------(2)\\\\1+2\\\\5x+5y=\frac{135}{12}\\\\x+y=\frac{27}{12}-----(3)\\\\1-2\\\\x-y=\frac{105}{12}-----(4)\\\\ 3+4\\\\2x=\frac{132}{12}\\\\2x=11\\\\x=\frac{11}{2}\\\\y+\frac{11}{2}=\frac{27}{12}\\\\y=-\frac{11}{2}+\frac{27}{12}\\\\y=\frac{-39}{12}

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