25.07.2020

An alloy contains 26 % of copper. What quantity of alloy is required to get 260 g of copper?

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09.07.2023, solved by verified expert

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Mathematics
Step-by-step answer
P Answered by Master
Solution:

Let the quantity of alloy required = m g

Then 26 % of m =260 g

\small\bold\green{⇒}\small\bold{\frac{(26)}{100} × m = 260 g}

\small\bold\green{⇒}\small\bold{m =  \frac{(260 × 100)}{26} g}

\small\bold\green{⇒}\small\bold{m =  \frac{26000}{26} g}

\small\bold\green{⇒}\small\bold{m = 1000 g}

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

Let the father's age be x and son's be y

10 years before-

Father age=x-10

sons age=y-10

Given,

x-10=10(y-10)

x-10=10y-100

Given present age of father=40

therefore,

x=40

40-10=10y-100

10y-100=30

10y=130

y=130/10

y=13

Therefore present age of son=13years

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