A cylinder has a height of 18 meters and a radius, №18010846, 25.03.2022 10:00

Mathematics

A cylinder has a height of 18 meters and a radius of 19 meters. What is its volume? Use ≈ 3.14 and round your answer to the nearest hundredth.

Step-by-step answer

P Answered by Specialist

$\huge\boxed{\sf 20403.72 \ m^3}$

Step-by-step explanation:

Height = h = 18 m

Radius = r = 19 m

Volume of cylinder:

$= \pi r^2 h\\\\= (3.14)(19)^2(18)\\\\= (3.14)(361)(18)\\\\= 20403.72 \ m^3\\\\\rule[225]{225}{2}$

Mathematics

1.)find the height of a rectangular prism if the surface area is 148 cm2, the width is 4 cm and the length is 5 cm. 2.)find the width of a rectangular prism if the volume is 34 cm3, the length is 1.7 cm, and the height is 0.5 cm. 3.)find the radius of a cylinder with a volume of 118.79 feet3 and height of 5 feet. 4.)find the surface area of the pyramid with square base that measures 8 ft by 8 ft and slant height of 12 ft. 5.)find the slant height of a cone with surface area 63.30 ft2 and diameter 6.2 ft. 6.)find the height of a square pyramid with

Step-by-step answer

P Answered by Specialist

7

1) surface of a rectangular prism=2(length x width)+2(length x height)+2(width x height)

Therefore:
148 cm²=2(5 cm x 4 cm)+2(5 cm x h)+2(4 cm x h)=
148 cm²=40 cm²+10 cm h+8 cm h
18 cm h=148 cm²-40 cm²
18 cm h=108 cm²
h=108 cm² / 18 cm=6 cm.

height=6 cm

2)
Volume of a rectangular prism= length x width x height
therefore:
34 cm³=(1.7 cm)(0.5 cm) h
0.85 cm² h=34 cm³
h=34 cm³/0.85 cm²
h=40 cm.

height=40 cm

3)
volume of a cylinder: πr²h
therefore.
118.79 ft³=πr²(5 ft)
r=√(118.79 ft³/5π ft)≈2.75 ft

radius=2.75 ft

4)

Surface area of the pyramid with square base=4(A side)+A base
A side=(1/2)(8ft)(12 ft)=48 ft²
A base=(8 ft)(8 ft)=64 ft²

surface area=4(48 ft²)+64 ft²=256 ft²

the surface area of this pyramid would be 256 ft².

5)
surface of a cone=πrs+πr²
therefore:
radius=diameter/2=6.2 ft/2=3.1 ft
63.3 ft²=π(3.1 ft) s+π(3.1 ft)²
3.1π ft s=33.109 ft²
s=33.109 ft² /3.1π ft
s≈3.4 ft

the slant height would be 3.4 ft.

6)
volume of a square pyramid=(area of base x heigth)/3
therefore:
area of base=(6 ft)(6 ft)=36 ft²
126.97 ft³=36 ft² h /3
h=126.97 ft³/12 ft²=10.58 ft

the height would be 10.58 ft.

7)
volume of a cone =(base x height)/3
base of a cone=πr²
therefore:
199.23 cm³=πr²(9 cm)/3
r=√(199.23 cm³ / 3π cm)≈4.6 cm

the radius would be 4.6 cm.

Mathematics

1.)find the height of a rectangular prism if the surface area is 148 cm2, the width is 4 cm and the length is 5 cm. 2.)find the width of a rectangular prism if the volume is 34 cm3, the length is 1.7 cm, and the height is 0.5 cm. 3.)find the radius of a cylinder with a volume of 118.79 feet3 and height of 5 feet. 4.)find the surface area of the pyramid with square base that measures 8 ft by 8 ft and slant height of 12 ft. 5.)find the slant height of a cone with surface area 63.30 ft2 and diameter 6.2 ft. 6.)find the height of a square pyramid with

Step-by-step answer

P Answered by Specialist

7

1) surface of a rectangular prism=2(length x width)+2(length x height)+2(width x height)

Therefore:
148 cm²=2(5 cm x 4 cm)+2(5 cm x h)+2(4 cm x h)=
148 cm²=40 cm²+10 cm h+8 cm h
18 cm h=148 cm²-40 cm²
18 cm h=108 cm²
h=108 cm² / 18 cm=6 cm.

height=6 cm

2)
Volume of a rectangular prism= length x width x height
therefore:
34 cm³=(1.7 cm)(0.5 cm) h
0.85 cm² h=34 cm³
h=34 cm³/0.85 cm²
h=40 cm.

height=40 cm

3)
volume of a cylinder: πr²h
therefore.
118.79 ft³=πr²(5 ft)
r=√(118.79 ft³/5π ft)≈2.75 ft

radius=2.75 ft

4)

Surface area of the pyramid with square base=4(A side)+A base
A side=(1/2)(8ft)(12 ft)=48 ft²
A base=(8 ft)(8 ft)=64 ft²

surface area=4(48 ft²)+64 ft²=256 ft²

the surface area of this pyramid would be 256 ft².

5)
surface of a cone=πrs+πr²
therefore:
radius=diameter/2=6.2 ft/2=3.1 ft
63.3 ft²=π(3.1 ft) s+π(3.1 ft)²
3.1π ft s=33.109 ft²
s=33.109 ft² /3.1π ft
s≈3.4 ft

the slant height would be 3.4 ft.

6)
volume of a square pyramid=(area of base x heigth)/3
therefore:
area of base=(6 ft)(6 ft)=36 ft²
126.97 ft³=36 ft² h /3
h=126.97 ft³/12 ft²=10.58 ft

the height would be 10.58 ft.

7)
volume of a cone =(base x height)/3
base of a cone=πr²
therefore:
199.23 cm³=πr²(9 cm)/3
r=√(199.23 cm³ / 3π cm)≈4.6 cm

the radius would be 4.6 cm.

Mathematics

Acylinder-shaped container has a radius of 25 centimeters and a height of 100 centimeters. a glass sphere with a radius of 10 centimeters is placed inside the cylinder shaped container and then the container is completely filled with water. what is the approximate volume of water contained in the cylinder? use 3.14 for pi. 4,187 cm³ 192,063 cm³ 196,250 cm³ 200,437 cm³

Step-by-step answer

P Answered by Master

118

The Awnser is B: 192,063 Hope this Helps : )

Mathematics

Iwill mark as brainliest!im stuck a cylinder shaped drum is used as a garbage container. the drum has a height of 4 ft and a radius of 1.25 ft. how many cubic feet of garbage does the drum hold? use 3.14 to approximate pi. enter your answer as a decimal rounded to the nearest hundredth in the box. a cone has a radius of 2.5 inches and a height of 1.6 inches. what is the volume of the cone to the nearest tenth in³? use 3.14 to approximate pi. 4.0 in³ 10.5 in³ 12.0 in³ 23.1 in³ to apply frosting to a cake, a baker twists a plastic bag containing

Step-by-step answer

P Answered by Specialist

4

Use these formulas and plug in the numbers.

Vcylinder=πR^2hVcone=1/3πR^2hVsphere=4/3πR^3Vhemisphere=2/3πR^3

To help w/number one: You will use Vcylinder=πR^2h
Radius is 1.25 squared is 1.56
You multiply 1.56xheight (4) = 6.25
6.25 x pi (3.14) = 19.625 (rounded to nearest hundred) = 19.63

Mathematics

Acylinder-shaped container has a radius of 25 centimeters and a height of 100 centimeters. a glass sphere with a radius of 10 centimeters is placed inside the cylinder shaped container and then the container is completely filled with water. what is the approximate volume of water contained in the cylinder? use 3.14 for pi. 4,187 cm³ 192,063 cm³ 196,250 cm³ 200,437 cm³

Step-by-step answer

P Answered by Specialist

118

The Awnser is B: 192,063 Hope this Helps : )

Physics

Suppose an automobile engine can produce 180 N*m of torque, and assume this car is suspended so that the wheels can turn freely. Each wheel acts like a 15.5 kg disk that has a 0.175 m radius. The tires act like 1.9-kg rings that have inside radii of 0.19 m and outside radii of 0.315 m. The tread of each tire acts like a 12-kg hoop of radius 0.335 m. The 14.5-kg axle acts like a solid cylinder that has a 1.95-cm radius. The 32.5-kg drive shaft acts like a solid cylinder that has a 2.9-cm radius. (a) calculate the angular acceleration in radians

Step-by-step answer

P Answered by Master

Explanation:

Moment of inertia of each wheel = 1/2 m R²

m is mass and R is radius of wheel

= .5 x 15.5 x .175²

= .2373 kg m²

moment of inertia of tyre

1/2 m ( r₁² + r₂² )

= 1/2 x 1.9 x ( .315² + .19²)

= 1/2 x 1.9 x ( .099+ .036)

= .12825 kg m²

moment of inertia of tread

= 1/2 m r²

= .5 x 12 x .335²

= .67335 kg m²

moment of inertia of axle

= 1/2 m r ²

= .5 x 14.5 x .0195²

= .00275

moment of inertia of drive shaft

= 1/2 x 32.5 x .029²

= .0137 kg m ²

Total moment of inertia of one tyre

= 1.05535 kg m²

total moment of inertia of two rear wheels

= 2.1107 kg m²

95 % of torque

= .95 x 180

= 171 Nm

angular acceleration

= torque / moment of inertia

= 171 / 2.1107

= 81.01 radian /s²

Mathematics

Acylinder shaped container has a diameter of 50 cm and a height of 100 cm. a glass sphere with a radius of 10 cm is placed inside the cylinder shaped container and then the container is completely filled with water. what is the approximate volume of water contained in the cylinder? use 3.14 as an approximation for pi. 4,187 cm³ 192,063 cm³ 196,250 cm³ 200,437 cm³

Step-by-step answer

P Answered by Specialist

5

Volume of a cylinder = πr²h
π=3.14
r=25
h=100

v = (3.14)(25)²(100)
v = (3.14)(625)(100)
v = 196,250 cm³

volume of a sphere = (4/3)πr³

v = (4/3)(3.14)(10)³
v = 4,186.67

196,250 - 4,186 = 192,063

the correct answer is the second choice, 192,063 cm³

Physics

Suppose an automobile engine can produce 180 N*m of torque, and assume this car is suspended so that the wheels can turn freely. Each wheel acts like a 15.5 kg disk that has a 0.175 m radius. The tires act like 1.9-kg rings that have inside radii of 0.19 m and outside radii of 0.315 m. The tread of each tire acts like a 12-kg hoop of radius 0.335 m. The 14.5-kg axle acts like a solid cylinder that has a 1.95-cm radius. The 32.5-kg drive shaft acts like a solid cylinder that has a 2.9-cm radius. (a) calculate the angular acceleration in radians

Step-by-step answer

P Answered by Master

Explanation:

Moment of inertia of each wheel = 1/2 m R²

m is mass and R is radius of wheel

= .5 x 15.5 x .175²

= .2373 kg m²

moment of inertia of tyre

1/2 m ( r₁² + r₂² )

= 1/2 x 1.9 x ( .315² + .19²)

= 1/2 x 1.9 x ( .099+ .036)

= .12825 kg m²

moment of inertia of tread

= 1/2 m r²

= .5 x 12 x .335²

= .67335 kg m²

moment of inertia of axle

= 1/2 m r ²

= .5 x 14.5 x .0195²

= .00275

moment of inertia of drive shaft

= 1/2 x 32.5 x .029²

= .0137 kg m ²

Total moment of inertia of one tyre

= 1.05535 kg m²

total moment of inertia of two rear wheels

= 2.1107 kg m²

95 % of torque

= .95 x 180

= 171 Nm

angular acceleration

= torque / moment of inertia

= 171 / 2.1107

= 81.01 radian /s²

Mathematics

Acylinder shaped container has a diameter of 50 cm and a height of 100 cm. a glass sphere with a radius of 10 cm is placed inside the cylinder shaped container and then the container is completely filled with water. what is the approximate volume of water contained in the cylinder? use 3.14 as an approximation for pi. 4,187 cm³ 192,063 cm³ 196,250 cm³ 200,437 cm³

Step-by-step answer

P Answered by Specialist

5

Volume of a cylinder = πr²h
π=3.14
r=25
h=100

v = (3.14)(25)²(100)
v = (3.14)(625)(100)
v = 196,250 cm³

volume of a sphere = (4/3)πr³

v = (4/3)(3.14)(10)³
v = 4,186.67

196,250 - 4,186 = 192,063

the correct answer is the second choice, 192,063 cm³

A cylinder has a height of 18 meters and a radius of 19 meters. What is its volume? Use ≈ 3.14 and round your answer to the nearest hundredth.

Step-by-step answer

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