a particle moves in a straight line such that its velocity after t seconds is (2t²-t) m/s. find the distance gone in the first 3 seconds.

22.5 m

Step-by-step explanation:

Calculate initial velocity (u) when t = 0, and velocity when t = 3:

when t = 0,  v = 2(0)² - 0 = 0  ⇒  u = 0

when t = 3,  v = 2(3)² - 3 = 15  ⇒  v = 15

SUVAT:

Substituting values into SUVAT formula:

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

The answer is in the image 

The total nom of  code that can be used is equal to 5+3 = 8

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The answer is in the image 

The solution is given in the image below

Here,

tip=18%of $32

tip=(18/100)*32

=0.18*32

=$5.76

Total payment=32+5.76=$37.76

Speed=Distance/time

Here,

distance=15m

time=1sec

speed=15/1=15m/sec

Distance=Speed*time

time=15min=15*60sec=900sec

Distance travelled in 15 min=15*900=13,500m

=13500/1000 km=13.5Km