If a:b =2:3 write b as a fraction of a, №18010974, 03.01.2020 03:25

Mathematics

If a:b =2:3 write b as a fraction of a

Step-by-step answer

P Answered by Specialist

given ,

$\fbox{a:b = 2:3}$

According to Question ,

we've to write b as a fraction of a.

thus , we know that

$a:b = \frac{a}{b} \\ \\ \dashrightarrow{2:3 = \frac{2}{3} }$

now to represent b as a fraction of a ,

we'll have to consider the ratio as b : a

which means ,

$b:a = inverse \: of \: a:b \\ \dashrightarrow{ b:a = \frac{b}{a} = \frac{3}{2} }$

_____________________________

hope helpful :D

Mathematics

Write 5 and 2 thirds as an improper fraction and as a mixed number a. 7/5, 2 3/5 b.13/5,2 3/5 c.15/3,5 2/3 d. 17/3,5 2/3

Step-by-step answer

P Answered by PhD

1

"D"

Step-by-step explanation: 5 and 2/3 is already a mixed number so we leave it how it is. Now we just have to write 5 and 2/3 as an improper fraction.

To write a mixed number as an improper fraction, first multiply the denominator by the whole number and then add the numerator. Finally, we put our new number over our original denominator.

Therefore, 5 and 2/3 can be written as the improper fraction 17/3.

$Write 5 and 2 thirds as an improper fraction and as a mixed number a. 7/5, 2 3/5 b.13/5,2 3/5 c.15/3$

Mathematics

Write 5 and 2 thirds as an improper fraction and as a mixed number a. 7/5, 2 3/5 b.13/5,2 3/5 c.15/3,5 2/3 d. 17/3,5 2/3

Step-by-step answer

P Answered by PhD

1

"D"

Step-by-step explanation: 5 and 2/3 is already a mixed number so we leave it how it is. Now we just have to write 5 and 2/3 as an improper fraction.

To write a mixed number as an improper fraction, first multiply the denominator by the whole number and then add the numerator. Finally, we put our new number over our original denominator.

Therefore, 5 and 2/3 can be written as the improper fraction 17/3.

$Write 5 and 2 thirds as an improper fraction and as a mixed number a. 7/5, 2 3/5 b.13/5,2 3/5 c.15/3$

Mathematics

Write a ratio with a fraction bar and as a decimal for the number of shaded shapes to the number of white shapes. a 7/10 0.7 b 2/3=0.6 c 3/2=1.5 d 7/3=23

Step-by-step answer

P Answered by Master

5

I believe the correct response is D.

D. 7/3 = 2 1/3 = 2.333.

Mathematics

Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. / ) for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. / ) for all fractions (e.g. 1/2 for 12). m= What would the perpendicular slope be? m= Step 2: Use the slope to find the y-intercept of the perpendicular line. b= Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10

Step-by-step answer

P Answered by Specialist

8

Point - Slope Form: (y - 3) = -5/4(x - 6)

Slope - Intercept Form: y = -5/4x + 10.5

Step-by-step explanation:

Rewrite: y = 4/5x + 2

I don't know what the rest is but I'll do it in two forms:

Point - Slope Form:

Slope = -5/4

(y - 3) = -5/4(x - 6)

Slope - Intercept Form:

y = -5/4x + b

3 = -7.5 + b

b = 10.5

y = -5/4x + 10.5

Mathematics

Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. / ) for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. / ) for all fractions (e.g. 1/2 for 12). m= What would the perpendicular slope be? m= Step 2: Use the slope to find the y-intercept of the perpendicular line. b= Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10

Step-by-step answer

P Answered by Master

8

Point - Slope Form: (y - 3) = -5/4(x - 6)

Slope - Intercept Form: y = -5/4x + 10.5

Step-by-step explanation:

Rewrite: y = 4/5x + 2

I don't know what the rest is but I'll do it in two forms:

Point - Slope Form:

Slope = -5/4

(y - 3) = -5/4(x - 6)

Slope - Intercept Form:

y = -5/4x + b

3 = -7.5 + b

b = 10.5

y = -5/4x + 10.5

Mathematics

1. using the numbers 3, 5, and 8, can you write nine proper fractions and nine improper fractions? you may use each number only once within a fraction. 2. name the numerator and the denominator in each fraction. a. 11⁄12 b. 7⁄512 c. 12⁄10 d. 0⁄78 3. indicate whether each of the following fractions is proper or improper. a. 4⁄16 b. 75⁄70 c. 2⁄15 d. 6⁄6 4; . insert the greater than, less than, or equal sign ( , , or =) to make each statement true. a. 45⁄45 b. 6⁄3 c. 2⁄7 d. 64⁄23 5. kim ate 3⁄10 of a bag of potato chips; sandy ate 3⁄7 of a bag; and

Step-by-step answer

P Answered by Specialist

39

1. Using 3, 5 and 8 we can write the proper fractions (when numerator is less than the denominator) as $\frac{3}{5} , \frac{3}{8} , \frac{5}{8}$ . As we can see these are just 3 in number.

Likewise, improper Fraction will be when the numerator is greater than the denominator and they are $\frac{5}{3}, \frac{8}{5} , \frac{8}{3}$ . As we can see even these are just three in number.

2. a 11 is the numerator and 20 is the denominator

b 7 is the numerator and 512 is the denominator

c 12 is the numerator and 10 is the denominator

d 0 is the numerator and 78 is the denominator

3 Please keep in mid that a fraction is proper when the numerator is lesser than the denominator and is improper when the numerator is greater than or equal to the denominator. Thus, keeping in mind this rule let us proceed and check the given fractions.

a Proper

b Improper

c Proper

d Improper

4. When the numerator is equal to denominator, the fraction's value will always be equal to 1. When the numerator is greater than the denominator the fraction's value will always be greater than 1 and when the numerator is less than the denominator the fraction's value will always less than 1. Keeping these rules in mind let us proceed with the fractions given.

a. =

b. <

c. <

d. >

Mathematics

1. using the numbers 3, 5, and 8, can you write nine proper fractions and nine improper fractions? you may use each number only once within a fraction. 2. name the numerator and the denominator in each fraction. a. 11⁄12 b. 7⁄512 c. 12⁄10 d. 0⁄78 3. indicate whether each of the following fractions is proper or improper. a. 4⁄16 b. 75⁄70 c. 2⁄15 d. 6⁄6 4; . insert the greater than, less than, or equal sign ( , , or =) to make each statement true. a. 45⁄45 b. 6⁄3 c. 2⁄7 d. 64⁄23 5. kim ate 3⁄10 of a bag of potato chips; sandy ate 3⁄7 of a bag; and

Step-by-step answer

P Answered by Specialist

39

1. Using 3, 5 and 8 we can write the proper fractions (when numerator is less than the denominator) as $\frac{3}{5} , \frac{3}{8} , \frac{5}{8}$ . As we can see these are just 3 in number.

Likewise, improper Fraction will be when the numerator is greater than the denominator and they are $\frac{5}{3}, \frac{8}{5} , \frac{8}{3}$ . As we can see even these are just three in number.

2. a 11 is the numerator and 20 is the denominator

b 7 is the numerator and 512 is the denominator

c 12 is the numerator and 10 is the denominator

d 0 is the numerator and 78 is the denominator

3 Please keep in mid that a fraction is proper when the numerator is lesser than the denominator and is improper when the numerator is greater than or equal to the denominator. Thus, keeping in mind this rule let us proceed and check the given fractions.

a Proper

b Improper

c Proper

d Improper

4. When the numerator is equal to denominator, the fraction's value will always be equal to 1. When the numerator is greater than the denominator the fraction's value will always be greater than 1 and when the numerator is less than the denominator the fraction's value will always less than 1. Keeping these rules in mind let us proceed with the fractions given.

a. =

b. <

c. <

d. >

Mathematics

Step 1: 5 = negative 2 (negative StartFraction 3 Over 10 EndFraction) + b. Step 2: 5 = StartFraction 6 Over 10 EndFraction + b. Step 3: 5 minus StartFraction 6 Over 10 EndFraction = StartFraction 6 Over 10 EndFraction minus StartFraction 6 Over 10 EndFraction + b. Step 4: StartFraction 50 Over 10 EndFraction minus StartFraction 6 Over 10 EndFraction = b. Step 5: StartFraction 44 Over 10 EndFraction = b. Step 6: y = negative 2 x minus 4.4. A student used the slope-intercept form to write the equation of a line that has a slope of -2 and passes through

Step-by-step answer

P Answered by Specialist

28

D.) Step 6: student needed to add the b value.

Step-by-step explanation:

I got it wrong and it gave me the right answer, which is what i provided, D.

Mathematics

1. find the digit that makes 3,71_ divisible by 9. a. 3 b. 7 c. 1 d. 5 2.list all the factors of the number 30. a. 1, 2, 3, 5, 6, 10, 15, 30 b. 2, 3, 4, 10, 20, 30, 40 c. 1, 2, 4, 5, 10, 15, 30 d. 1, 2, 4, 5, 8, 10, 20, 40 3. find the prime factorization of the number 168. a. 24 x 3 x 7 b. 23 x 3 x 7 c. 24 x 33 x 13 d. 23 x 33 x 7 4. find the gcf of the numbers 140 and 180. a. 20 b. 90 c. 30 d. 10 5. the weights of 3 bags containing footballs are 15 oz, 30 oz, and 60 oz. the greatest common factor of 15, 30, and 60 gives the weight of each ball

Step-by-step answer

P Answered by PhD

64

QUESTION 1

We want to find the digit that should fill the blank space to make

3,71-

divisible by 9.

If a number is divisible by 9 then the sum of the digits should be a multiple of 9.

The sum of the given digits is,

3 + 7 + 1 = 11

Since

11 + 7 = 18

which is a multiple of 9.

This means that

3,717

is divisible by 9.

The correct answer is B

QUESTION 2

The factors of the number 30 are all the numbers that divides 30 exactly without a remainder.

These numbers are ;

1,2,3,5,6,10,15,30

The correct answer is A.

QUESTION 3.

We want to find the prime factorization of the number 168.

The prime numbers that are factors of 168 are

$2,3 \: and \: 7$

We can write 168 as the product of these three prime numbers to obtain,

$168={2}^{3}\times 3\times7$

We can also use the factor tree as shown in the attachment to write the prime factorization of 168 as

$168 ={2}^{3}\times 3\times7$

The correct answer is B.

QUESTION 4.

We want to find the greatest common factor of

$140\:\:and\:\:180$

We need to express each of these numbers as a product of prime factors.

The prime factorization of 140 is

$140={2}^{2}\times 5\times7.$

The prime factorization of 180 is

$180={2}^{2} \times{3}^{2}\times5.$

The greatest common factor is the product of the least degree of each common factor.

$GCF={2}^{2}\times5$

GCF=20

The correct answer is A.

QUESTION 5.

We want to find the greatest common factor of

$15,30\: and\:60.$

We need to first find the prime factorization of each number.

The prime factorization of 15 is

$15=3\times5.$

The prime factorization of 30 is

$30=2\times 3\times 5.$

The prime factorization of 60 is

$60={2}^{2}\times3 \times5$

The greatest common factor of these three numbers is the product of the factors with the least degree that is common to them.

$GCF=3 \times5$

GCF=15

The correct answer is C.

QUESTION 6

We want to determine which of the given fractions is equivalent to

$\frac{3}{8}.$

We must therefore simplify each option,

$A.\: \: \frac{15}{32}=\frac{15}{32}$

$B.\:\:\frac{12}{32}=\frac{4\times 3}{4\times8}=\frac{3}{8}$

$C.\:\:\:\:\frac{12}{24}=\frac{12\times1}{12\times 2}=\frac{1}{2}$

$D.\:\:\frac{9}{32}=\frac{9}{32}$

The simplification shows that

$\frac{12}{32}\equiv \frac{3}{8}$

The correct answer is B.

QUESTION 7.

We want to express

$\frac{10}{22}$

in the simplest form.

We just have to cancel out common factors as follows.

$\frac{10}{22}=\frac{2\times5}{2 \times11}$

This simplifies to,

$\frac{10}{22}=\frac{5}{11}$

The correct answer is C.

QUESTION 8.

We were given that Justin visited of the states.

The question requires that we express as a fraction of 50.

This will give us

$\frac{25}{50}=\frac{25\times1}{25\times2}$

We must cancel out the common factors to have our fraction in the simplest form.

$\frac{25}{50}=\frac{1}{2}$

The correct answer is C.

QUESTION 9.

We want to write

$2\frac{5}{8}$

as an improper fraction.

We need to multiply the 2 by the denominator which is 8 and add the product to 5 and then express the result over 8.

This gives us,

$2 \frac{5}{8}=\frac{2\times8+5}{8}$

this implies that,

$2\frac{5}{8}=\frac{16+5}{8}$

$2\frac{5}{8}=\frac{21}{8}$

Sarah needed

$\frac{21}{8}\:\:yards$

The correct answer is D.

QUESTION 10

See attachment

QUESTION 11

We wan to write

$3\: and\:\:\frac{7}{8}$

as an improper fraction.

This implies that,

$3+\frac{7}{8}=3\frac{7}{8}$

To write this as a mixed number, we have,

$3\frac{7}{8}=\frac{3\times8+7}{8}$

This implies that,

$3\frac{7}{8}=\frac{24+7}{8}$

This gives

$3\frac{7}{8}=\frac{31}{8}$

The correct answer is B.

QUESTION 12

We want to find the LCM of and using prime factorization.

The prime factorization of 30 is $30=2\times 3\times 5$

The prime factorization of 46 is $40=2\times 23$ .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times \times3 5\times 23$

LCM=690

The correct answer is D.

QUESTION 13

We want to find the least common multiple of 3,6 and 7.

The prime factorization of is .

The prime factorization of 6 is $6=2\times 3$ .

The prime factorization of 7 is .

The LCM is the product of the common factors with the highest degrees. This gives us,

$LCM=2\times3 \times7$

LCM=42 .

The LCM is 42, therefore 42 days will pass before all three bikes will at the park on the same day again.

The correct answer is B.

See attachment for continuation.

1. find the digit that makes 3,71_ divisible by 9. a. 3 b. 7 c. 1 d. 5 2.list all the factors of the

If a:b =2:3 write b as a fraction of a

Step-by-step answer

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