03.11.2022

What is the formula of equilateral triangle .class-8

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09.07.2023, solved by verified expert
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Step-by-step explanation:

The perimeter of an equilateral triangle is:

P = 3a (where a any length of the triangle)

The area of an equilateral triangle is:

What is the formula of equilateral triangle .class-8, №18011049, 03.11.2022 15:01 (where a is the side length)

Using the area formula we can rearrange it to get the formula of the length of the equilateral triangle:

What is the formula of equilateral triangle .class-8, №18011049, 03.11.2022 15:01

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Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

The perimeter of an equilateral triangle is:

P = 3a (where a any length of the triangle)

The area of an equilateral triangle is:

A = \frac{\sqrt{3} }{4} a^{2} (where a is the side length)

Using the area formula we can rearrange it to get the formula of the length of the equilateral triangle:

a = \frac{2}{3} 3^{\frac{3}{4} } \sqrt{A}

Mathematics
Step-by-step answer
P Answered by PhD

(a)6 Equilateral Triangles.

(b)30-60-90 triangle.

(c)See Attached Triangle in Figure 2

(d)Length of the short leg = 2cm.

(e)Length of the hypotenuse= 4cm.

(f)Length of the long leg=2\sqrt{3}cm

(g)Apothem.

(h)Height of the Equilateral triangle=2\sqrt{3}cm

(i)Area of One Equilateral triangle =4\sqrt{3}cm^2

(j)Area of Hexagon ==24\sqrt{3}\:cm^2

Step-by-step explanation:

(a)From Figure 1, there are 6 Equilateral Triangles.

(b)If we cut an equilateral down the middle (green line), we create a 30-60-90 triangle.

(c)Triangle Attached in Figure 2.

(d)The length of the short leg of one of the 30-60-90 triangle is 2cm.

(e)The length of the hypotenuse of one of the 30-60-90 triangle is 4cm.

(f)Length of the long leg

We use Pythagoras Theorem to find the length of the long leg of the right triangle.

4^2=2^2+l^2\\l^2=4^2-2^2=12\\l=\sqrt{12}=2\sqrt{3}cm

(g)The vocabulary word for the long side of the 30-60-90 called in the polygon (green line) is Apothem.

It is line segment from the center to the midpoint of one of the sides of a polygon.

(h)Height of the Equilateral Triangle=2\sqrt{3}cm

(i)Area of One Equilateral triangle

Base =4 cm, Height =2\sqrt{3}cm

Area=0.5X4X2\sqrt{3}cm

=4\sqrt{3}\:cm^2

(j)Area of Hexagon =Area of One Equilateral Triangle X 6

=6X 4\sqrt{3}\\=24\sqrt{3}\:cm^2


Score for Question 3: ___ of 5 points) 3. Use the diagram of a REGULAR HEXAGON and follow these step
Score for Question 3: ___ of 5 points) 3. Use the diagram of a REGULAR HEXAGON and follow these step
Mathematics
Step-by-step answer
P Answered by PhD

Regular Hexagon area H = 24\sqrt{3}  sq. cm.

In a regular Hexagon, there are 6 equilateral triangles.

You create a 30-60-90 triangle when you cut an equilateral triangle in half.

The long side of the 30-60-90 triangle is called the "apothem"

Step-by-step explanation:

You have one side of 4cm  for the regular hexagon.

so then the shortest side of the 30-60-90 triangle is 2 cm.

the hypotenuse is therefore 4cm

and the long leg is equal to 2*root(3)

Height of one equilateral triangle = 2 root(3)  cm.

Area of one of these equilateral triangles : A =  (1/2)*2*root(3)*4cm

A = 4 root(3) sq. cm  is area of one equilateral triangle.

Hexagon area : H = 6*A = 6*4*root(3) = 24 root(3)

H = 24\sqrt{3}  sq. cm.

Mathematics
Step-by-step answer
P Answered by PhD
1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is \frac{ \sqrt{3} }{2} a

2. if a a=25 ft, then the height is \frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7 (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}

so the total area of the roof is \frac{ \sqrt{3} }{2} a^{2} +3al

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al

5. so the area now is \frac{ \sqrt{3} }{2} a^{2} +2al

6. now a=25 and l=2a=50

Area=\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2}  (\frac{ \sqrt{3} }{2} +4)=625*4.866

=3041.3 (ft squared)

1. the prism-shaped roof has equilateral triangular bases. create an equation that models the height
1. the prism-shaped roof has equilateral triangular bases. create an equation that models the height

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