Mathematics : asked on ga142000

26.03.2023

B) x2 - 2x - 3

I need help with factorising :/

1

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09.07.2023, solved by verified expert

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B) x2 - 2x - 3 I need help with factorising :/, №18011146, 26.03.2023 05:48

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Mathematics

B) x2 - 2x - 3 I need help with factorising :/

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I know that answer

..............please mark as brainliest

B) x2 - 2x - 3 I need help with factorising :/

Mathematics

Find the solution to the system y = 2x2 - 2x - 3 y = -2x + 2 A) (-1,1) and (1.-3) B) (0.-1) and (-0.5, 0) C) (0.5, -3,5) and (0, -3) D) (2, 1) and (0,0)

Step-by-step answer

P Answered by Master

1

C

Step-by-step explanation:

i took this quiz

Mathematics

Find the solution to the system y = 2x2 - 2x - 3 y = -2x + 2 A) (-1,1) and (1.-3) B) (0.-1) and (-0.5, 0) C) (0.5, -3,5) and (0, -3) D) (2, 1) and (0,0)

Step-by-step answer

P Answered by Master

1

C

Step-by-step explanation:

i took this quiz

Mathematics

Given that f(x) = 4x + 5 and g(x) = x2 - 2x - 2, find (f + g)(x). A) (f + g)(x) = x2 + 2x+3 B) (f + g)(x) = x2 + 6x+ 3 C) (f + g)(x) = -x2 + 6x + 7 D) (f + g)(x) = – x2 + 2x - 7

Step-by-step answer

P Answered by Master

A

Step-by-step explanation:

We are given the two functions:

$f(x)=4x+5\text{ and } g(x)=x^2-2x-2$

And we want to find:

(f+g)(x)

This is equivalent to:

=f(x)+g(x)

Substitute:

=(4x+5)+(x^2-2x-2)

Rearrange:

=(x^2)+(4x-2x)+(5-2)

Combine like terms. Hence:

(f+g)(x)=x^2+2x+3

Our answer is A.

Mathematics

NEEDED ASAP !! For each pair of expressions, identify whether the expressions are equivalent. Write YES or NO, and justify your answer with math or words. a) and 1 1 + y x+y b) x² + x and x3 c) 3x – 12 and x - 4 d) -2(x - 3) and - 2x - 3 e) 5x2 and x² + 4x² f) x(y+z) and xy + 2x

Step-by-step answer

P Answered by PhD

1

Step-by-step explanation:

a) No

because

1/x + 1/y

= y + x/xy

b) No

because

x³ = x × x × x

c) Yes

because

3x - 12 = 0

3(x - 4) = 0

x - 4 = 0

d) No

because

-2(x - 3)

= -2x + 6

e) Yes

because

x² + 4x² = 5x²

f) Yes

because

x(y + z)

= xy + zx

Mathematics

Factor the polynomial. 6x2 - 7x - 3 a) (6x - 1)(x + 3) b) (6x + 3)(x - 1) c) (2x - 3)(3x + 1) d) (3x - 3)(2x + 1)

Step-by-step answer

P Answered by PhD

7

6x^2 - 7x - 3
= (3x + 1)(2x - 3)

answer
C)(2x - 3)(3x + 1)

hope it helps

Mathematics

Factor the polynomial. 6x2 - 7x - 3 a) (6x - 1)(x + 3) b) (6x + 3)(x - 1) c) (2x - 3)(3x + 1) d) (3x - 3)(2x + 1)

Step-by-step answer

P Answered by PhD

7

6x^2 - 7x - 3
= (3x + 1)(2x - 3)

answer
C)(2x - 3)(3x + 1)

hope it helps

Mathematics

Which equation does the graph of the systems of equations solve? it s a quadratic graph opening down and quadratic graph opening up. they intersect at (0,3) and (2,-5). (a)x2 - 2x + 3 = 2x2 - 8x - 3 (b)x2 - 2x + 3 = 2x2 - 8x + 3 (c)-x2 - 2x + 3 = 2x2 - 8x - 3 (d)-x2 - 2x + 3 = 2x2 - 8x + 3

Step-by-step answer

P Answered by Specialist

15

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Step-by-step explanation:

We are given that,

The graph of the system of equations is a 'quadratic graph opening down and a quadratic graph opening up'.

This means that one quadratic equation will have leading co-efficient positive and other will have leading co-efficient negative.

So, we get that options A and B are discarded.

Further it is provided that the graph intersect at ( 0,3 ) and ( 2,-5 ).

This means that the pair of points must satisfy the given system of equations.

So, according to the options:

C. $-x^{2} -2x+3=2x^{2} -8x-3$

Putting x = 0, gives 3 = -3, which is not possible.

So, option C is dicarded.

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Putting x = 0 gives 3 = 3 and x = 2 gives -5 = -5.

Hence, the graph of the given system solves the equation $-x^{2} -2x+3=2x^{2} -8x+3$ .

Mathematics

Which equation does the graph of the systems of equations solve? it s a quadratic graph opening down and quadratic graph opening up. they intersect at (0,3) and (2,-5). (a)x2 - 2x + 3 = 2x2 - 8x - 3 (b)x2 - 2x + 3 = 2x2 - 8x + 3 (c)-x2 - 2x + 3 = 2x2 - 8x - 3 (d)-x2 - 2x + 3 = 2x2 - 8x + 3

Step-by-step answer

P Answered by Specialist

15

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Step-by-step explanation:

We are given that,

The graph of the system of equations is a 'quadratic graph opening down and a quadratic graph opening up'.

This means that one quadratic equation will have leading co-efficient positive and other will have leading co-efficient negative.

So, we get that options A and B are discarded.

Further it is provided that the graph intersect at ( 0,3 ) and ( 2,-5 ).

This means that the pair of points must satisfy the given system of equations.

So, according to the options:

C. $-x^{2} -2x+3=2x^{2} -8x-3$

Putting x = 0, gives 3 = -3, which is not possible.

So, option C is dicarded.

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Putting x = 0 gives 3 = 3 and x = 2 gives -5 = -5.

Hence, the graph of the given system solves the equation $-x^{2} -2x+3=2x^{2} -8x+3$ .

Mathematics

1. find the zeros of the function. f(x) = 9x2 + 6x - 8 (2 points) a) -2 and 4 b) negative two divided by three. and four divided by three. c) two divided by three. and negative four divided by three. d) 2 and -4 2. find the zeros of the function. f(x) = 9x3 - 45x2 + 36x (2 points) a) 0, 1, and 4 b) -1 and -4 c) 1 and 4 d) 0, -1, and -4 3. find the zeros of the polynomial function and state the multiplicity of each. f(x) = 4(x + 7)2(x - 7)3 (2 points) a) 4, multiplicity 1; -7, multiplicity 3; 7, multiplicity 3 b) -7, multiplicity 3; 7, multiplicity

Step-by-step answer

P Answered by PhD

6

1. f(x) = 9x² + 6x - 8
f(x) = (3x - 2)(3x + 4)
When (3x - 2) = 0, then x = 2/3
When (3x + 4) = 0, then x = -4/3

The zeros are two divided by three and negative four divided by three.

2. f(x) = 9x³ - 45x² + 36x
f(x) = 9x(x² - 5x + 4)
= 9x(x - 1)(x - 4)
When 9x = 0, then x = 0
When (x-1) = 0, then x = 1
When (x-4) = 0, then x = 4

0, 1 and 4

3. f(x) = 4(x+7)²(x-7)³
When (x+7)² = 0, then x = -7 (twice)
When (x-7)³ = 0, then x = 7 (thrice)

7, multiplicity 2; -7 multiplicity 3

4. The zeros of f(x) are √5, -√5, -7
The factors of f(x) are (x-√5)(x+√5)(x+7)
Note that (x-√5)(x+√5) = x² - (√5)² = x² - 5
f(x) = (x²-5)(x+7)
= x³ + 7x² - 5x - 35

f(x) = x³ + 7x² - 5x - 35

5. Expand (2x + 4)³
From Pascal's Triangle, the coefficients are 1 3 3 1
Therefore
(2x + 4)³ = 1(2x)³(4)⁰ + 3(2x)²(4)¹ + 3(2x)¹(4)² + 1(2x)⁰(4)³
= 8x³ + 48x² + 96x + 64

8x³ + 48x² + 96x + 64

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