Mathematics : asked on emma3216
 23.11.2020

Given circle E with diameter CD and radius EA. AB is tangent to E at A. if AD = 15 and EC = 14, solve for AC.

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Step-by-step answer

09.07.2023, solved by verified expert
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AC ≈ 23.6 units

Step-by-step explanation:

m∠CAD = 90°

CD = 2×14 = 28 , AD = 15

CD² = AD² + AC² ⇒ AC² = CD² - AD²

AC² = 28² - 15² = ( 28 - 15 )( 28 + 15 ) = 13 × 43 = 559

AC ≈ 23.6


Given circle E with diameter CD and radius EA., №18011158, 23.11.2020 09:07
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Mathematics
Step-by-step answer
P Answered by Specialist

AC ≈ 23.6 units

Step-by-step explanation:

m∠CAD = 90°

CD = 2×14 = 28 , AD = 15

CD² = AD² + AC² ⇒ AC² = CD² - AD²

AC² = 28² - 15² = ( 28 - 15 )( 28 + 15 ) = 13 × 43 = 559

AC ≈ 23.6


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