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Answers are in explanation part.

Step-by-step explanation:

Law of Cosines for side c:

a) c = 3.561

b) c = 4.136

c) c = 3.09

d) c = 12.5

e) c = 1.978

f) c = 9.173

g) c = 5.196

Law of Cosines for angle C:

h) C = 82.819°

i) C = 60°

j) C = 21.787°

k) C = 68.676°

l) Sides (8, 5, 1) cannot form a triangle. It is impossible.

m) C = 118.454°

see attached

Explanation:

Two methods are shown in attached notes... Method I is based upon Experimental Rate Trends; Method II is the 'Ratio Method'.

Solution :

#include

//Converts to binary string.

* hexadecimalBinary(char* hexdec)

{

long = 0;

char *string = (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

strcat(string, "0000");

break;

strcat(string, "0001");

strcat(string, "0010");

strcat(string, "0011");

strcat(string, "0100");

strcat(string, "0101");

strcat(string, "0110");

strcat(string, "0111");

strcat(string, "1000");

strcat(string, "1001");

case 'A':

case 'a':

strcat(string, "1010");

case 'B':

case 'b':

strcat(string, "1011");

case 'C':

case 'c':

strcat(string, "1100");

case 'D':

case 'd':

strcat(string, "1101");

case 'E':

case 'e':

strcat(string, "1110");

case 'F':

case 'f':

strcat(string, "1111");

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

return string;

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

The solution is in the following image

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

It will provide an instant answer!