a. 68% of the workers will earn between $47300 and $69700.
b. 2.5% of workers will earn above $89000
c. Approximately 0
Step-by-step explanation:
The standard normal distribution curve in the attached graph is used to solve this question.
a. The value $47300 is a standard deviation below the mean i.e. 58500-11200=47300. While $69700 is a standard deviation above the mean. I.e. 58500+12000=69700.
Between the first deviation below and above the mean, you have 34%+34%=68% of the salary earners within this range. So we have 68%of staffs earning within this range
b. The second standard deviation above the mean is $80900. i.e. 58500+11200+11200=$80900
We have 50%+13.5%+2.5%= 97.5% earning below $80900. Therefore, 100-97.5= 2.5% of the workers earn above this amount.
c. From the Standard Deviation Rule, the probability is only about (1 -0 .997) / 2 = 0.0015 that a normal value would be more than 3 standard deviations away from its mean in one direction or the other. The probability is only 0.0002 that a normal variable would be more than 3.5 standard deviations above its mean. Any more standard deviations than that, and we generally say the probability is approximately zero.
a. 68% of the workers will earn between $47300 and $69700.
b. 2.5% of workers will earn above $89000
c. Approximately 0
Step-by-step explanation:
The standard normal distribution curve in the attached graph is used to solve this question.
a. The value $47300 is a standard deviation below the mean i.e. 58500-11200=47300. While $69700 is a standard deviation above the mean. I.e. 58500+12000=69700.
Between the first deviation below and above the mean, you have 34%+34%=68% of the salary earners within this range. So we have 68%of staffs earning within this range
b. The second standard deviation above the mean is $80900. i.e. 58500+11200+11200=$80900
We have 50%+13.5%+2.5%= 97.5% earning below $80900. Therefore, 100-97.5= 2.5% of the workers earn above this amount.
c. From the Standard Deviation Rule, the probability is only about (1 -0 .997) / 2 = 0.0015 that a normal value would be more than 3 standard deviations away from its mean in one direction or the other. The probability is only 0.0002 that a normal variable would be more than 3.5 standard deviations above its mean. Any more standard deviations than that, and we generally say the probability is approximately zero.
For 1 flavor there are 9 topping
Therefore, for 5 different flavors there will be 5*9 choices
No of choices= 5*9
=45
The answer is in the image
The answer is in the image
For every 8 cars there are 7 trucks
Therefore,
Cars:Truck=8:7
Answer is B)8:7
The answer is in the image
Let the father's age be x and son's be y
10 years before-
Father age=x-10
sons age=y-10
Given,
x-10=10(y-10)
x-10=10y-100
Given present age of father=40
therefore,
x=40
40-10=10y-100
10y-100=30
10y=130
y=130/10
y=13
Therefore present age of son=13years
Cost before sale tax=$46.00
Cost after including tax=$48.76
Sale tax=$48.76-46.00
=$2.76
we know,
sale tax=((sales tax rate)/100) * cost before sale tax
2.76=((sales tax rate)/100) *46.00
sale tax rate=(2.76*100)/46
=276/46
=6%
There fore sales tax rate=6%
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