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Physics : asked on lesleyy7278
 07.10.2021

Sorin hits a cricket ball straight up into the air. after 1.5\,\text{s}1.5s1, point, 5, start text, s, end text, the ball is falling straight down with a speed of 6.5\,\dfrac{\text{m}}{\text{s}}6.5
s
m

6, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. we want to find the initial vertical velocity of the ball. we can ignore air resistance.

. 54

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17.02.2022, solved by verified expert
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Ranjana Bhatt
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8.2 m/s upward

Explanation:

The motion of the ball is a free fall motion, so we can use the suvat equation:

Sorin hits a cricket ball straight up into the, №15221459, 07.10.2021 13:04

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

Choosing upward as positive direction:

Sorin hits a cricket ball straight up into the, №15221459, 07.10.2021 13:04

Sorin hits a cricket ball straight up into the, №15221459, 07.10.2021 13:04 (acceleration of gravity)

t = 1.5 s

Solving for u, we find the initial velocity:

Sorin hits a cricket ball straight up into the, №15221459, 07.10.2021 13:04

And the direction is upward.

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Faq

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Step-by-step answer
P Answered by Specialist
Options:
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Answer:
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Explanation:
In the picture
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Step-by-step explanation:

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