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Physics : asked on trevorhenyan51
 12.11.2021

A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300 kg. The motorcycle is moving at a speed of 30 m/s. The surface exerts a normal force of magnitude FN on the motorcycle.The motorcycle passes over the top of the hill again but now is moving at a speed of 33 m/s. How does the new normal force exerted on the motorcycle compare to FN

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24.06.2023, solved by verified expert
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Bhaskar Singh Bora
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A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Explanation:

From the question we are told that

Radius of curvatureA motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Mass A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

initial Speed of Motorcycle  A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Final  Speed of Motorcycle  A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Generally the equation Force at initial speed is  mathematically given as

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Generally the equation Force at Final speed is  mathematically given as

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

Therefore

A motorcycle passes over the top of a hill that, №17887085, 12.11.2021 03:38

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Faq

Physics
A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300 kg. The motorcycle is moving at a speed of 30 m/s. The surface exerts a normal force of magnitude FN on the motorcycle.The motorcycle passes over the top of the hill again but now is moving at a speed of 33 m/s. How does the new normal force exerted on the motorcycle compare to FN
Step-by-step answer
P Answered by PhD

F_NF_N'

Explanation:

From the question we are told that

Radius of curvaturer=100m

Mass M=300kg

initial Speed of Motorcycle  V_1=30m/s

Final  Speed of Motorcycle  V_2=33m/s

Generally the equation Force at initial speed is  mathematically given as

F_N=mg-\frac{mv^2}{R}

F_N=300*9.8-\frac{(300*30)^2}{100}

F_N=240N

Generally the equation Force at Final speed is  mathematically given as

F_N'=mg-\frac{mv'^2}{R}

F_N'=300*9.8-\frac{(300*33)^2}{100}

F_N'=-327N

Therefore

F_NF_N'

Physics
The system shown above consists of two identical blocks that are suspended using four cords, each of a different length. Which of the following claims are true about the magnitudes of the tensions in the cords?
Step-by-step answer
P Answered by Specialist
Answer: Option B and C are True.

Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂:
w = T₁/cos 60° -----(1);
w = T₂/cos 30° ----(2);
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°;
T₁ cos 30° = T₂ cos 60°;
T₂/T₁ = cos 30°/cos 60°;
T₂/T₁ =1.73.
Therefore, option a is false since T₂ > T₁.
Option B is true since T₁ cos 30° = T₂ cos 60°.
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Answer: Option B and C are True. Explanation: The weight of the two blocks acts downwards. Le
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Abbey always gets zits on her chin and she can t figure out the best method to get rid of them. She decides to test several products to see which clears her face up fastest: washing with soap and water, washing with an acne face wash from the pharmacy, and washing her face with organic oils. For one week she just washes her face with water. The next week she washes every day with soap and water. The following week she uses the acne wash, and the last week she uses the organic oils. Each week she records the number of zits she has on her chin at
Step-by-step answer
P Answered by PhD

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

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a screw has a head diameter of 0.812 m and a thread width of 0.318 cm. What is the ideal mechanical advantage?
Step-by-step answer
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The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

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compare the momentum of a 6,300 kg elephant walking 0.11 m/s and a 50-kg dolphins swimming 10.m/s
Step-by-step answer
P Answered by PhD
First sum applied the Newton's second law motion: F = ma
Force = mass* acceleration
This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,
force=(mass*velocity)/time
such that, (mass*velocity)/time=momentum/time
Therefore we get mass*velocity=momentum
Momentum=mass*velocity
Elephant mass=6300 kg; velocity=0.11 m/s
Momentum=6300*0.11
P=693 kg (m/s)
Dolphin mass=50 kg; velocity=10.4 m/s
Momentum=50*10.4
P=520 kg (m/s)
The elephant has more momentum(P) because it is large.
Physics
An electrical kettle supplies 20,000j of energy to heat 0.5kg of water. What is the temperature change? The specific heat capacity of water is 4200j/kg.
Step-by-step answer
P Answered by PhD
The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C
Physics
Jordan lifts a 100-kilogram barbell from the floor to a height of 2.0 meters in 1.5 seconds. The amount of power he generates is about ____ watts.
Step-by-step answer
P Answered by PhD
Weight of barbell (m) = 100 kg
Uplifted to height (h) = 2m
Time taken= 1.5 s
Work done by Jordan = potential energy stored in barbell = mgh
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Jasmine, who weighs 400 newtons, moves up a 5.0-meter climbing wall in 15 seconds. The amount of power generated by Jasmine as she climbs the wall is about ____ watts.
Step-by-step answer
P Answered by PhD
Weight of jasmine (m) = 400 N
Height climbed on wall (h) = 5m
Total time taken in climbing = 5 sec
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Step-by-step answer
P Answered by PhD
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Time of landing (t) is found with the help of vertical motion.
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Horizontal range of balloon, R = U"t
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Step-by-step answer
P Answered by PhD
Gravity acceleration (g) = 9.8m/s^2
Time (t) = 3sec
Acceleration = velocity/time
Velocity = acceleration×time
= 9.8×3
= 29.4m/s
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