Physics : asked on pacangel
 28.03.2020

Consider a ball tossed from the ground into the air at 25 m/s. At a later time, the ball is measured to be moving downward at 11 m/s. a) Find how high the ball is off of the ground at the later time. b) Find the time interval between these two events. c) Sketch graphs of position, velocity, and acceleration versus time for the ball.

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24.06.2023, solved by verified expert
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The answer is below

Explanation:

a) According to Newton's law of motion, the distance travelled by a body going upward can be calculated using the formula:

v² = u² - 2gh

where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and h is the height of the ball.

g = 10 m/s², u = 25 m/s, v = 11 m/s

Substituting:

11² = 25² - 2(10)h

20h = 25² - 11²

20h = 504

h = 25.2 m

b) The time (t) can be gotten using:

v = u - gt

Substituting

11 = 25 - 10t

10t = 25 - 11

10t = 14

t = 1.4 s

c) the graph were plotted using an online graphing tool


Consider a ball tossed from the ground into the, №17887639, 28.03.2020 15:12
Consider a ball tossed from the ground into the, №17887639, 28.03.2020 15:12
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Physics
Step-by-step answer
P Answered by PhD

The answer is below

Explanation:

a) According to Newton's law of motion, the distance travelled by a body going upward can be calculated using the formula:

v² = u² - 2gh

where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and h is the height of the ball.

g = 10 m/s², u = 25 m/s, v = 11 m/s

Substituting:

11² = 25² - 2(10)h

20h = 25² - 11²

20h = 504

h = 25.2 m

b) The time (t) can be gotten using:

v = u - gt

Substituting

11 = 25 - 10t

10t = 25 - 11

10t = 14

t = 1.4 s

c) the graph were plotted using an online graphing tool


Consider a ball tossed from the ground into the air at 25 m/s. At a later time, the ball is measured
Consider a ball tossed from the ground into the air at 25 m/s. At a later time, the ball is measured
Physics
Step-by-step answer
P Answered by Master

Answer:

see below.

Step-by-step explanation:

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

Ei = Ef

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

pg = Eg/c

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

Physics
Step-by-step answer
P Answered by PhD

Answer:

9.6 meters

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

Physics
Step-by-step answer
P Answered by PhD

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics
Step-by-step answer
P Answered by PhD
Answer:
7.25 secs.

Explanation:
First find the distance it takes to stop
s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8
Next find the time it takes to go that distance , s = ut +[1/2] at^2
8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and
t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square
[t - (8.7/2.4)]^2=0
t = 8.7/2.4 = 3.625 secs
At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again
Total time , T =2t = 7.25 secs.

Note:
The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.
Physics
Step-by-step answer
P Answered by PhD
Weight of barbell (m) = 100 kg
Uplifted to height (h) = 2m
Time taken= 1.5 s
Work done by Jordan = potential energy stored in barbell = mgh
= 100×2×9.8
= 1960J
Power = energy/time
= 1960/1.5
1306.67watts
Physics
Step-by-step answer
P Answered by PhD
Weight of jasmine (m) = 400 N
Height climbed on wall (h) = 5m
Total time taken in climbing = 5 sec
Work done in climbing the wall = rise in potential energy = mgh
= 400×9.8×51
= 19600J
Power generated by Jasmine = potential energy / time
= 19600/5
= 3920Watts
Physics
Step-by-step answer
P Answered by PhD
Initial velocity (u) = 0
Time taken = 4.5 seconds
Gravitational acceleration (g) = 9.8m/s^2
By the second equation of motion under gravity,
The distance that object fell down (h)
h = ut + (1/2)gt^2
h = 0×4.5 + (1/2)×9.8×(4.5)^2
h = 99.225 m
Physics
Step-by-step answer
P Answered by PhD
Gravitational acceleration (g) = 9.8m/s^2
Time of flight = 12 seconds
Acceleration = velocity/time
Velocity = acceleration × time
= 9.8×12
= 117.6 m/s

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