Physics : asked on makaylahunt
 03.11.2021

Long flights at midlatitudes in the Northern Hemisphere encounter the jet stream, an eastward airflow that can affect a plane’s speed relative to Earth’s surface. If a pilot maintains a certain speed relative to the air (the plane’s airspeed), the speed relative to the surface (the plane’s ground speed) is more when the flight is in the direction of the jet stream and less when the flight is opposite the jet stream. Suppose a round-trip flight is scheduled between two cities separated by 4000 km, with the outgoing flight in the direction of the jet stream and the return flight opposite it. The airline computer advises an airspeed of 1000 km/h, for which the difference in flight times for the outgoing and return flights is 70.0 min. What jet-stream speed is the computer using?

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Step-by-step answer

24.06.2023, solved by verified expert
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The jet stream speed used by the computer is 142.Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31 km/h

Explanation:

The given parameters are;

The distance between the two cities the plane flies = 4,000 km

The difference in flight times for outgoing and return flights = 70.0 min

We note that 70 min = 70 min × 1 h/60 min = 7/6 h

The airspeed recommended by the airline computer = 1,000 km/h

Let 'a' represent the jet stream speed

The time it takes the plane moving in the same direction as the jet stream between the two cities, 't₁', is given as follows;

Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31

The time it takes the plane moving in the opposite direction as the jet stream between the two cities, 't₂', is given as follows;

Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31

The difference in flight times for outgoing and return flights, Δt = t₂ - t₁

Therefore, we have;

Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31

From which we get;

Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31

By cross multiplying, we have;

-48,000·a = 7·a²- 7,000,000

∴ 7·a² + 48,000·a - 7,000,000 = 0

Factorizing with a graphic calculator gives;

(7·a - 1,000)·(a + 7,000) = 0

∴ a = 1,000/7, or a = -7000

Therefore, the jet stream speed the computer is using, a = 1,000/7 km/h = 142.Long flights at midlatitudes in the Northern, №17887872, 03.11.2021 07:31 km/h.

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Physics
Step-by-step answer
P Answered by PhD

The jet stream speed used by the computer is 142.\overline {857142} km/h

Explanation:

The given parameters are;

The distance between the two cities the plane flies = 4,000 km

The difference in flight times for outgoing and return flights = 70.0 min

We note that 70 min = 70 min × 1 h/60 min = 7/6 h

The airspeed recommended by the airline computer = 1,000 km/h

Let 'a' represent the jet stream speed

The time it takes the plane moving in the same direction as the jet stream between the two cities, 't₁', is given as follows;

t_1 = \dfrac{4000}{1000 + a}

The time it takes the plane moving in the opposite direction as the jet stream between the two cities, 't₂', is given as follows;

t_2 = \dfrac{4000}{1000 - a}

The difference in flight times for outgoing and return flights, Δt = t₂ - t₁

Therefore, we have;

\Delta t = t_2 - t_1 = \dfrac{4000}{1000 - a} - \dfrac{4000}{1000 + a} = \dfrac{7}{6}

From which we get;

-\dfrac{8000 \cdot a}{a^2 -1,000,000} = \dfrac{7}{6}

By cross multiplying, we have;

-48,000·a = 7·a²- 7,000,000

∴ 7·a² + 48,000·a - 7,000,000 = 0

Factorizing with a graphic calculator gives;

(7·a - 1,000)·(a + 7,000) = 0

∴ a = 1,000/7, or a = -7000

Therefore, the jet stream speed the computer is using, a = 1,000/7 km/h = 142.\overline {857142} km/h.

Physics
Step-by-step answer
P Answered by Master

Answer:

see below.

Step-by-step explanation:

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

Ei = Ef

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

pg = Eg/c

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

Physics
Step-by-step answer
P Answered by PhD

Answer:

9.6 meters

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

Physics
Step-by-step answer
P Answered by PhD

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics
Step-by-step answer
P Answered by PhD
First sum applied the Newton's second law motion: F = ma
Force = mass* acceleration
This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,
force=(mass*velocity)/time
such that, (mass*velocity)/time=momentum/time
Therefore we get mass*velocity=momentum
Momentum=mass*velocity
Elephant mass=6300 kg; velocity=0.11 m/s
Momentum=6300*0.11
P=693 kg (m/s)
Dolphin mass=50 kg; velocity=10.4 m/s
Momentum=50*10.4
P=520 kg (m/s)
The elephant has more momentum(P) because it is large.
Physics
Step-by-step answer
P Answered by PhD
The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C
Physics
Step-by-step answer
P Answered by PhD
Weight of barbell (m) = 100 kg
Uplifted to height (h) = 2m
Time taken= 1.5 s
Work done by Jordan = potential energy stored in barbell = mgh
= 100×2×9.8
= 1960J
Power = energy/time
= 1960/1.5
1306.67watts
Physics
Step-by-step answer
P Answered by PhD
The horizontal and vertical motions of balloons are independent from each other.
Let vertical component of initial velocity U' horizontal component of initial velocity U"
Time of landing (t) is found with the help of vertical motion.
Since vertical component of initial velocity of balloon is zero(U' = 0)
From equation h = U't + 1/2gt^2
h = 1/2gt^2
t = √(2h/g)
t = √( 2×150/9.8)
t = 5.53 sec
Horizontal velocity = 50m/s
Horizontal range of balloon, R = U"t
= 50× 5.53
= 27.65m
So the balloon will go 27.65 metre away from the bridge
Physics
Step-by-step answer
P Answered by PhD
Gravity acceleration (g) = 9.8m/s^2
Time (t) = 3sec
Acceleration = velocity/time
Velocity = acceleration×time
= 9.8×3
= 29.4m/s

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