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06.01.2020

Define heat capacity of a substance.
Write the S.I unit of heat capacity.

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09.07.2023, solved by verified expert

Nitin Arora

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Mathematics, English, Physics. Research Scholar at Indian Institute of Technology, Roorkee

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Define heat capacity of a substance:

The heat capacity of a substance can be defined as the amount of heat required to change its temperature by one degree.

Write the S.I unit of heat capacity:

Joule per Kelvin

Joule per Celsius

-,-

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Physics

Define heat capacity of a substance. Write the S.I unit of heat capacity.

Step-by-step answer

P Answered by Specialist

Define heat capacity of a substance:

The heat capacity of a substance can be defined as the amount of heat required to change its temperature by one degree.

Write the S.I unit of heat capacity:

Joule per Kelvin

$\: \: \:$

Joule per Celsius

$\: \: \:$

-,-

Chemistry

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. the heat capacity of a certain substance has been measured to be2.76j·g°c suppose 466.g of the substance are heated until the temperature of the sample has changed by 39.4°c.write an equation that will let you calculate the heatqthat was needed for this temperature change. your equation should contain only symbols. be sure you define each symbol.

Step-by-step answer

P Answered by Master

Q=m*c*ΔT=50674.7 Joules

Explanation:

By the definition described, the specific heat c is defined like this:

$c=\frac{Q}{m*\Delta T}$

Where Q is the heat needed to change the temperature T of a mass m. So, multiplying both sides of the equation by m*ΔT we obtain

Q=m*c*ΔT

Then, we just substitute with the quantities and multiply them.

Chemistry

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The specific heat capacity of a certain substance has been measured to be 3.52 J/g °C. Suppose 420.0 g of the substance is heated until the temperature of the sample has changed by 43.8 °C. Write an equation that will let you calculate the last Q that was needed for this temperature change. Your equation should contain only symbols. Be sure to define

Step-by-step answer

P Answered by PhD

The answers to your questions are given below.

Explanation:

Data obtained from the question include:

Mass (M) = 420.0 g

Temperature change (ΔT) = 43.8 °C

Specific heat capacity (C) = 3.52 J/g °C

Heat needed (Q) =...?

The heat needed for the temperature change can be obtained by using the following formula:

Q = MCΔT

Where:

Q is the heat needed measured in joule (J).

M is the mass of substance measured in grams (g)

C is the specific heat capacity of the substance with unit J/g °C.

ΔT is the temperature change measured in degree celsius (°C).

Thus, we can calculate the heat needed to change the temperature as follow:

Q = MCΔT

Q = 420 x 3.52 x 43.8

Q = 64753.92 J

Therefore, the heat needed to cause the temperature change is 64753.92 J

Chemistry

A1.800-g sample of solid phenol (c6h5oh(s)) was burned in a bomb calorimeter, which has a total heat capacity of 11.66 kj/∘c. the temperature of the calorimeter plus its contents increased from 21.36∘c to 26.37∘c. (a)-write a balanced chemical equation for the reaction that takes place in the bomb calorimeter. express you answer as a chemical equation including phases. water vapor, h2o(g), will initially form as part of this reaction. however, the temperature of all substances will eventually equilibrate in the bomb calorimeter (to 26.37∘c), which

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P Answered by Specialist

Explanation:

(a) When combustion of phenol takes place then it yields carbon dioxide and water.

A balanced chemical equation for this reaction is as follows.

$C_{6}H_{5}OH(s) + 7O_{2}(g) \rightarrow 6CO_{2}(g) + 3H_{2}O(l)$

(b) Heat released by combustion is equal to the total heat absorbed by the system (total content of calorimeter).

Therefore, heat released will be calculated as follows.

Heat released = $C_{cal} \times \Delta T$

= $11.66 kJ/^{o}C \times (26.37 - 21.36)^{o}C$

= 58.4166 kJ

Hence, heat of combustion per gram phenol is as follows.

= $\frac{\text{-heat released}}{\text{mass of phenol}}$

= $\frac{-58.4166 kJ}{1.80 g}$

= -32.45 kJ/g

Therefore, heat of combustion per gram of phenol is -32.45 kJ/g.

Chemistry

Step-by-step answer

P Answered by Specialist

Explanation:

(a) When combustion of phenol takes place then it yields carbon dioxide and water.

A balanced chemical equation for this reaction is as follows.

$C_{6}H_{5}OH(s) + 7O_{2}(g) \rightarrow 6CO_{2}(g) + 3H_{2}O(l)$

(b) Heat released by combustion is equal to the total heat absorbed by the system (total content of calorimeter).

Therefore, heat released will be calculated as follows.

Heat released = $C_{cal} \times \Delta T$

= $11.66 kJ/^{o}C \times (26.37 - 21.36)^{o}C$

= 58.4166 kJ

Hence, heat of combustion per gram phenol is as follows.

= $\frac{\text{-heat released}}{\text{mass of phenol}}$

= $\frac{-58.4166 kJ}{1.80 g}$

= -32.45 kJ/g

Therefore, heat of combustion per gram of phenol is -32.45 kJ/g.

Chemistry

You are writing energy balances for a compound for which you cannot find heat capacity or latent heat data. All you know about the material are its molecular formula (C7H12N) and that it is a liquid at room temperature and has a normal boiling point of 200°C. Use this information to estimate the enthalpy of the vapor of this substance at 200°C relative to the liquid at 25°C.

Step-by-step answer

P Answered by Specialist

$\mathbf{\Delta H =97.815 \ kJ/mole}$

Explanation:

Given that:

The molecular formula = $C_7H_{12}N$

The normal boiling point = 200°C

The enthalpy of the vapor = 200°C

The liquid temperature = 25°C.

By applying Kopp's rule:

$C_p = 6 \times (0.012) + 12 (0.018)+1(0.033)$

C_p = 0.071+ 0.216+0.033

C_p = 0.32 kJ/mole

For Trouton's rule;

ΔHV = 0.088 Tb(t) for non polar liquid

ΔHV = 0.088(200)°C

ΔHV = 0.088(200+ 273.15)

ΔHV = 41.637 kJ/mol

ΔHV ≅ 41.637 kJ/mol

∴

$\Delta H = \int \limits^ {250}_{25} C_p dT + \Delta HV (200^0C)$

Replacing the values from above; we have:

$\Delta H = 0.321(200-25) \ kJ/mole+ 41.64 \ kJ/mole$

$\Delta H = 0.321(175) \ kJ/mole+ 41.64 \ kJ/mole$

$\Delta H =56.175 \ kJ/mole+ 41.64 \ kJ/mole$

$\mathbf{\Delta H =97.815 \ kJ/mole}$

Physics

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance of 2.7 meters. Calculate the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard.

Step-by-step answer

P Answered by Specialist

Options:
a. 0.08 meters
b. 0.16 meters
c. 0.32 meters
d. 1.8 meters

Answer:
b. 0.16 meters

Explanation:
In the picture
Options:
a. 0.08 meters
b. 0.16 meters
c. 0.32 meters
d. 1.8 meters

Answer:
b. 0.16 meters

Physics

The system shown above consists of two identical blocks that are suspended using four cords, each of a different length. Which of the following claims are true about the magnitudes of the tensions in the cords?

Step-by-step answer

P Answered by Specialist

Answer: Option B and C are True.

Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂:
w = T₁/cos 60° -----(1);
w = T₂/cos 30° ----(2);
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°;
T₁ cos 30° = T₂ cos 60°;
T₂/T₁ = cos 30°/cos 60°;
T₂/T₁ =1.73.
Therefore, option a is false since T₂ > T₁.
Option B is true since T₁ cos 30° = T₂ cos 60°.
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Answer: Option B and C are True.

Explanation:
The weight of the two blocks acts downwards.
Le

Physics

Abbey always gets zits on her chin and she can t figure out the best method to get rid of them. She decides to test several products to see which clears her face up fastest: washing with soap and water, washing with an acne face wash from the pharmacy, and washing her face with organic oils. For one week she just washes her face with water. The next week she washes every day with soap and water. The following week she uses the acne wash, and the last week she uses the organic oils. Each week she records the number of zits she has on her chin at

Step-by-step answer

P Answered by PhD

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

Physics

Sandra has five cubes each made of a different metal. Each cube has a mass of 100 grams. Which procedure should Sandra use to best determine which metal cube transfers to most heat to 500 grams of water? A. Heat each cube to a the same temperature, place each cube into different containers with 500 grams of water at different temperatures, and measure the temperature of the water. B. Heat each cube to a different temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of

Step-by-step answer

P Answered by PhD

Answer:

Option D

Step-by-step explanation:

D.
Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.

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