Physics : asked on fanny1211
 22.11.2021

The acceleration of free fall on a certain planet is 8.0 m s-2. An object gets dropped from a height and hits the ground after 1.5 s. From what height must the object have been dropped?

. 0

Step-by-step answer

09.07.2023, solved by verified expert
Unlock the full answer
Answer:Height from which the object is dropped is 9m

We are given that:

The acceleration of free fall on a certain planet is 8m/s². An object is dropped from the height and hits the ground after 1.5s

We need to find:

Height from which the object was dropped.

Using equations of motion:

➙ v² - u² = 2as

➙ v = u + at

here,

u = initial velocityv = final velocitya = accelerations = displacementt = time taken Solution:

From the given information, we can conclude that:

initial velocity of the object is 0 m/sacceleration due to gravity = 8 m/s²time taken = 1.5 seconds

Now, using equation of motion:

➝ v = u + at

➝ v = 0 + ( 8 × 1.5 )

➝ v = 0 + 12 .0

➝ v = 12 m/s

final velocity of object = 12 m/s

For, acceleration :

➝ v² - u² = 2as

➝ ( 12 )² - ( 0 )² = 2 × 8 × s

➝ 144 - 0 = 16s

➝ 16 s = 144

➝ s = 144 / 16

➝ s = 9m

Displacement = 9 m

The acceleration of free fall on a certain planet, №18010764, 22.11.2021 10:40 Since, we take displacement in terms of distance in some places, therefore we can say that the height from which the object was dropped is 9 meters .

It is was helpful?

Faq

Physics
Step-by-step answer
P Answered by Master
Answer:Height from which the object is dropped is 9m

We are given that:

The acceleration of free fall on a certain planet is 8m/s². An object is dropped from the height and hits the ground after 1.5s

We need to find:

Height from which the object was dropped.

Using equations of motion:

➙ v² - u² = 2as

➙ v = u + at

here,

u = initial velocityv = final velocitya = accelerations = displacementt = time taken Solution:

From the given information, we can conclude that:

initial velocity of the object is 0 m/sacceleration due to gravity = 8 m/s²time taken = 1.5 seconds

Now, using equation of motion:

➝ v = u + at

➝ v = 0 + ( 8 × 1.5 )

➝ v = 0 + 12 .0

➝ v = 12 m/s

final velocity of object = 12 m/s

For, acceleration :

➝ v² - u² = 2as

➝ ( 12 )² - ( 0 )² = 2 × 8 × s

➝ 144 - 0 = 16s

➝ 16 s = 144

➝ s = 144 / 16

➝ s = 9m

Displacement = 9 m

\dag Since, we take displacement in terms of distance in some places, therefore we can say that the height from which the object was dropped is 9 meters .

Physics
Step-by-step answer
P Answered by Specialist
Answer: Option B and C are True.

Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂:
w = T₁/cos 60° -----(1);
w = T₂/cos 30° ----(2);
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°;
T₁ cos 30° = T₂ cos 60°;
T₂/T₁ = cos 30°/cos 60°;
T₂/T₁ =1.73.
Therefore, option a is false since T₂ > T₁.
Option B is true since T₁ cos 30° = T₂ cos 60°.
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Answer: Option B and C are True.

Explanation:  
The weight of the two blocks acts downwards.
Le
Physics
Step-by-step answer
P Answered by PhD

Answer:

9.6 meters

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

Physics
Step-by-step answer
P Answered by PhD
Answer:
7.25 secs.

Explanation:
First find the distance it takes to stop
s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8
Next find the time it takes to go that distance , s = ut +[1/2] at^2
8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and
t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square
[t - (8.7/2.4)]^2=0
t = 8.7/2.4 = 3.625 secs
At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again
Total time , T =2t = 7.25 secs.

Note:
The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.
Physics
Step-by-step answer
P Answered by PhD
The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C
Physics
Step-by-step answer
P Answered by PhD
Weight of barbell (m) = 100 kg
Uplifted to height (h) = 2m
Time taken= 1.5 s
Work done by Jordan = potential energy stored in barbell = mgh
= 100×2×9.8
= 1960J
Power = energy/time
= 1960/1.5
1306.67watts
Physics
Step-by-step answer
P Answered by PhD
Weight of jasmine (m) = 400 N
Height climbed on wall (h) = 5m
Total time taken in climbing = 5 sec
Work done in climbing the wall = rise in potential energy = mgh
= 400×9.8×51
= 19600J
Power generated by Jasmine = potential energy / time
= 19600/5
= 3920Watts
Physics
Step-by-step answer
P Answered by PhD
The horizontal and vertical motions of balloons are independent from each other.
Let vertical component of initial velocity U' horizontal component of initial velocity U"
Time of landing (t) is found with the help of vertical motion.
Since vertical component of initial velocity of balloon is zero(U' = 0)
From equation h = U't + 1/2gt^2
h = 1/2gt^2
t = √(2h/g)
t = √( 2×150/9.8)
t = 5.53 sec
Horizontal velocity = 50m/s
Horizontal range of balloon, R = U"t
= 50× 5.53
= 27.65m
So the balloon will go 27.65 metre away from the bridge
Physics
Step-by-step answer
P Answered by PhD
Gravity acceleration (g) = 9.8m/s^2
Time (t) = 3sec
Acceleration = velocity/time
Velocity = acceleration×time
= 9.8×3
= 29.4m/s

Try asking the Studen AI a question.

It will provide an instant answer!

FREE