The amount of silver nitrate that has been used for producing 6.75 mol of cupric nitrate has been 13.75 mol. The student chooses the right tile, but the tile has to be flipped in order to cancel the units. Thus. option B is correct.
The balanced chemical equation for the reaction has been:
According to the balanced chemical equation, 2 moles of silver chloride have been required to produce 1 mole of cupric nitrate.
The amount of silver nitrate that has been required to produce 6.75 moles of cupric nitrate has been:
1-mole cupric nitrate = 2moles silver nitrate
6.75 moles cupric nitrate = 6.75 × 2 moles silver nitrate
6.75 moles cupric nitrate = 13.5 moles silver nitrate.
The amount of silver nitrate that has been used for producing 6.75 mol of cupric nitrate has been 13.75 mol.
The student chooses the right tile for the determination of the solution to the problem, but the tile has to be flipped in order to cancel the units. Thus. option B is correct.
For more information about the moles of product, refer to the link: