Chemistry: How many formula units are in 7.00 moles of NaCI

How many formula units are in 7.00 moles of NaCI, №13634120, 10.11.2021 17:53

Chemistry

1. how many moles are in 3.4 x 1024 molecules of hcl? 2. how many grams are in 2.59 x 1023 formula units of al2o3? 3. how many grams are in 9.05 x 1023 atoms of silicon? 4. if you had 7.00 moles of pto2, how many grams would you have? 5. how many moles are in 29.2 l of oxygen gas at stp? 6. what is the volume (liters) of 75.8 g of n2 at stp? show work for each one .

Step-by-step answer

P Answered by PhD

5

1. How many moles are in 3.4 x 10²⁴ molecules of HCl?

if there are 6.022 × 10²³ molecules in 1 mole of HCl

then there are 3.4 × 10²⁴ molecules in X moles of HCl

X = (3.4 x 10²⁴ × 1) / 6.022 × 10²³ = 5.6 moles of HCl

2. How many grams are in 2.59 x 10²³ formula units of Al₂O₃?

if there are 6.022 × 10²³ units in 1 mole of Al₂O₃

then there are 2.59 × 10²³ units in X moles of Al₂O₃

X = (2.59 x 10²³ × 1) / 6.022 × 10²³ = 0.43 moles of Al₂O₃

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of Al₂O₃ = 0.43 × 102 = 43.86 g

3. How many grams are in 9.05 x 1023 atoms of silicon?

if there are 6.022 × 10²³ atoms in 1 mole of silicon

then there are 9.05 × 10²³ atoms in X moles of silicon

X = (9.05 x 10²³ × 1) / 6.022 × 10²³ = 1.5 moles of silicon

mass = number of moles × molecular weight

mass of silicon = 1.5 × 28 = 42 g

4. If you had 7.00 moles of PtO₂, how many grams would you have?

mass = number of moles × molecular weight

mass of PtO₂ = 7 × 227 = 1589 g

5.How many moles are in 29.2 L of oxygen gas at STP?

At standard temperature and pressure (STP) we may use the following formula:

number of moles = volume (L) / 22.4 (L / mol)

number of moles of oxygen = 29.2 / 22.4 = 1.3

6. What is the volume (liters) of 75.8 g of N₂ at STP?

number of moles = mass / molecular weight

number of moles of N₂ = 75.8 / 28 = 2.7 moles

At standard temperature and pressure (STP) we may use the following formula:

number of moles = volume (L) / 22.4 (L / mol)

volume = number of moles × 22.4

volume of N₂ = 2.7 × 22.4 = 60.48 L

Chemistry

1. how many moles are in 3.4 x 1024 molecules of hcl? 2. how many grams are in 2.59 x 1023 formula units of al2o3? 3. how many grams are in 9.05 x 1023 atoms of silicon? 4. if you had 7.00 moles of pto2, how many grams would you have? 5. how many moles are in 29.2 l of oxygen gas at stp? 6. what is the volume (liters) of 75.8 g of n2 at stp? show work for each one .

Step-by-step answer

P Answered by PhD

5

1. How many moles are in 3.4 x 10²⁴ molecules of HCl?

if there are 6.022 × 10²³ molecules in 1 mole of HCl

then there are 3.4 × 10²⁴ molecules in X moles of HCl

X = (3.4 x 10²⁴ × 1) / 6.022 × 10²³ = 5.6 moles of HCl

2. How many grams are in 2.59 x 10²³ formula units of Al₂O₃?

if there are 6.022 × 10²³ units in 1 mole of Al₂O₃

then there are 2.59 × 10²³ units in X moles of Al₂O₃

X = (2.59 x 10²³ × 1) / 6.022 × 10²³ = 0.43 moles of Al₂O₃

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of Al₂O₃ = 0.43 × 102 = 43.86 g

3. How many grams are in 9.05 x 1023 atoms of silicon?

if there are 6.022 × 10²³ atoms in 1 mole of silicon

then there are 9.05 × 10²³ atoms in X moles of silicon

X = (9.05 x 10²³ × 1) / 6.022 × 10²³ = 1.5 moles of silicon

mass = number of moles × molecular weight

mass of silicon = 1.5 × 28 = 42 g

4. If you had 7.00 moles of PtO₂, how many grams would you have?

mass = number of moles × molecular weight

mass of PtO₂ = 7 × 227 = 1589 g

5.How many moles are in 29.2 L of oxygen gas at STP?

At standard temperature and pressure (STP) we may use the following formula:

number of moles = volume (L) / 22.4 (L / mol)

number of moles of oxygen = 29.2 / 22.4 = 1.3

6. What is the volume (liters) of 75.8 g of N₂ at STP?

number of moles = mass / molecular weight

number of moles of N₂ = 75.8 / 28 = 2.7 moles

At standard temperature and pressure (STP) we may use the following formula:

number of moles = volume (L) / 22.4 (L / mol)

volume = number of moles × 22.4

volume of N₂ = 2.7 × 22.4 = 60.48 L

Chemistry

One mole of zinc has a mass of 65.4 grams. Approximately how many atoms of zinc are present in one mole of zinc? (5 points) a 32 x 1023 atoms b 6 x 1023 atoms c 66 atoms d 65 atoms Question 2 (5 points) (05.01 LC) Which of the following best defines Avogadro s number? (5 points) a Mass, in grams, of each particle of the substance b Number of particles in one mole of a pure substance c Mass, in grams, of the nucleus of the substance s atoms d Total mass, in grams, of all the particles in one mole of the substance Question 3 (5 points) (05.01 MC)

Step-by-step answer

P Answered by PhD

1) Answer: b. 6 x 1023 atoms
1 mole of a substance is 6*10^23 atoms (Avogadro number) and the ratio of the mass of zinc to the molar mass is 1:1.
2) Answer: b
Number of particles in one mole of a pure substance
3) Answer: b
2.408 x 1024
Explanation: let's find the amount of substance
n=m/M=97.22 g/24g / mol= 4.05 mol
let's find the number of atoms
N=n*Na=4,05*6,02*10²³=24,08*10²³
4) Answer: c
molar mass of N + 3 x molar mass of H
Explanation: In order to calculate the molar mass of a compound (complex substance), the index indicating the number of atoms of each element in one mole should be multiplied by the molar mass of this element and the data obtained should be added.
5) Answer: b. 3
Explanation: Molar mass of mgco3 = 84.3139 g/mol.
n=m/M= 252,939 / 84,3139 = 3
6) Answer: a
Write the mole ratio.
7) Answer: b
15.1 grams
Explanation: Molar mass of Na2CO3 = 105.99 g/mol
n(Na2CO3) = 20 / 105,99 = 0,188
n(NaOH)=2n(Na2CO3)=2*0,188=0,376
m(NaOH)=0,376*40=15.1 grams
8) Answer: b
4.2 moles
Explanation: 2С2Н6+7О2=4СО2+6Н2О
3n(С2Н6)=n(H2O)
n(H2O)= 1,4*3=4,2
9) Answer: b
The ratio of measured yield over theoretical yield
10) Answer: c
87.3%
Explanation: 2,72 / 3,12 × 100% = 87,3 %
11) Answer: 145,314 g
Explanation: 61,33 / 22,9898 = 2,7
M (NaCl) = 58.5 g/mol
m(NaCl) = 2,7 × 58,5 = 157,95 g - the theoretical yield
the percentage yield of the reaction is 157,95*0.92=145,314 g

Chemistry

1.)if you are given the number of particles in a substance sample, what is the first step you should take to determine how many grams are present in that sample? find the molar mass of the substance. convert the grams to particles. convert the moles to mass. convert the number of particles to moles. 2.)phosphoric acid, which is a component of many soft drinks, has a molar mass of 98.00 grams per mole. a sample of phosphoric acid contains 3.1 percent hydrogen, 31.6 percent phosphorus, and 65.3 percent oxygen by mass. what is the molecular formula

Step-by-step answer

P Answered by PhD

1

1-Find the molar mass of the substance.

2-H3PO4

3-New atoms are created.

4-The ratios of the number of moles of each substance that react and that are produced.

5-conservation of mass

6-The number of atoms for every element is equal on both sides of the equation.

7-1:1

8-1:03

9-5.50%

Chemistry

1.)if you are given the number of particles in a substance sample, what is the first step you should take to determine how many grams are present in that sample? find the molar mass of the substance. convert the grams to particles. convert the moles to mass. convert the number of particles to moles. 2.)phosphoric acid, which is a component of many soft drinks, has a molar mass of 98.00 grams per mole. a sample of phosphoric acid contains 3.1 percent hydrogen, 31.6 percent phosphorus, and 65.3 percent oxygen by mass. what is the molecular formula

Step-by-step answer

P Answered by PhD

1

1-Find the molar mass of the substance.

2-H3PO4

3-New atoms are created.

4-The ratios of the number of moles of each substance that react and that are produced.

5-conservation of mass

6-The number of atoms for every element is equal on both sides of the equation.

7-1:1

8-1:03

9-5.50%

Chemistry

6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperature (23°C) and 3.00 atm pressure? b) How many grams of oxygen are needed? (Hint: Since moles have been asked, which equation has the moles listed in the equation. Use that to solve this problem. Also don’t forget to use the equation 1 mole = Formula weight or Molecular weight to calculate the grams of O2).

Step-by-step answer

P Answered by Specialist

3

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

Volume of the chamber (V): 200. LRoom temperature (T): 23 °CPressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

Chemistry

6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperature (23°C) and 3.00 atm pressure? b) How many grams of oxygen are needed? (Hint: Since moles have been asked, which equation has the moles listed in the equation. Use that to solve this problem. Also don’t forget to use the equation 1 mole = Formula weight or Molecular weight to calculate the grams of O2).

Step-by-step answer

P Answered by Specialist

3

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

Volume of the chamber (V): 200. LRoom temperature (T): 23 °CPressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

Chemistry

How many moles of HF are in 30.mL of 0.15MHF(aq) ?

Step-by-step answer

P Answered by Master

Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarity * L
mol = 0.15 * 0.03 = 0.0045 mol
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarit

Chemistry

What elements combined with Strontium, St, in a 1:1 ratio?

Step-by-step answer

P Answered by PhD

Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.

Chemistry

LaToya uses 50 newtons (N) of force to pull a 500 N cart. Which statements are correct about calculating LaToya s mechanical advantage? Select all that apply.A. The input force is 50 N.B. The output force is 50 N.C. The input force is 500 N.D. The output force is 450 N.E. The mechanical advantage is 10.F. The mechanical advantage is 100.

Step-by-step answer

P Answered by Master

Answer:

A

Step-by-step explanation:

The input force is 50 N. But it will not create not any change. No mechanical advantage is observed.

How many formula units are in 7.00 moles of NaCI

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