The photoelectron spectrum for the element boron is represented above. which of the following best explains how the spectrum is consistent with the electron shell model of the atom?

Explanation:

The figure attached is representation of the photoelectron spectrum for the element boron, which is the missing part of the question.

There are three peaks. Each peak represents one subshell: 1s, 2s, and 2p.

Indeed, Boron has 5 electrons: 2 in the subshell 1s, 2 in the subshell 2s and one in the subshell 2p.

The first peak, the peak to the left of the diagram, is as high as the second peak, meaining there are the same relative number of electrons in the 1s and 2s subshells.

The third peak, the one to the right of the diagram is half as high as the other two peaks, there are half electrons in the 2p subshell as in the 1s and 2s subshells.

Since Boron has five electrons, the photoelectrum spectrum shows that there are two electrons in the 1s subshell,  two electrons in the 2s subshell, and a single electron in the 2p subshell.

Then, as for the answer choices:

Explanation:

The figure attached is representation of the photoelectron spectrum for the element boron, which is the missing part of the question.

There are three peaks. Each peak represents one subshell: 1s, 2s, and 2p.

Indeed, Boron has 5 electrons: 2 in the subshell 1s, 2 in the subshell 2s and one in the subshell 2p.

The first peak, the peak to the left of the diagram, is as high as the second peak, meaining there are the same relative number of electrons in the 1s and 2s subshells.

The third peak, the one to the right of the diagram is half as high as the other two peaks, there are half electrons in the 2p subshell as in the 1s and 2s subshells.

Since Boron has five electrons, the photoelectrum spectrum shows that there are two electrons in the 1s subshell,  two electrons in the 2s subshell, and a single electron in the 2p subshell.

Then, as for the answer choices:

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 ×328 K

Solving:

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.