Chemistry : asked on sp81135
 08.02.2022

Alyssa is trying to decide where to spend this year's vacation. She could go snorkeling in the *Sea of Tranquility on the Moon or she could go skiing on *Mount Olympus on Mars. With the price of fuel, she is wondering how much she will save by traveling to the Moon instead of Mars. Round trip to Mars ( d1 ) is 122000000 km, but round trip to the Moon (d2 ) is only 812000 km. Her car gets 1.54 x 10^3 km/L of fuel. At a cost of $3.23 x 10^3 per liter of fuel, how much will she save by going snorkeling instead of skiing? Convert d1 and d2 to scientific notation before listing them in the Given.

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30.10.2022, solved by verified expert
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Round trip to Mars ( d1 ) is 122000000 km

 Round trip to the Moon (d2 ) is only 812000 km.

 Her car gets 1.54 x 10^3 km/L of fuel.

1.54 x 10^3 km is travelled in 1L fuel

1 km is travelled in = 1/1.54 x 10^3 L

812000km is travelled in = (1/1.54 x 10^3 )812000

      = 527.27 lit

Cost of fuel travelled to moon = 527.27 ×3.23 ×10^3

= $1703.08 ×10^3

Distance travelled to mars= 122000000

1.54 x 10^3 km  travelled in 1L

1km travelled in = 1/1.54 x 10^3 L

122000000 travelled in = (1/1.54 x 10^3 km)122000000

= 79220.78 Lit

Cost of travelleling mars = 79220.78×3.23×10^3

 = $255883.12 ×10^3

Saved money =( 2.55883.12 ×10^3)- (1703.08×10^3)

= $254180.04 × 10^3

 At a cost of $3.23 x 10^3 per liter of fuel, how much will she save by going

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StudenGPT
Step-by-step answer
P Answered by Studen AI
To convert distances to scientific notation, we need to express them as a number between 1 and 10 multiplied by a power of 10.

The distance to Mars is given as km. To express this in scientific notation:
1. Determine the number between 1 and 10. In this case, it is 4.5.
2. Count the number of decimal places you moved to the left to get the number between 1 and 10. In this case, it is 8 decimal places.
3. Write the distance in scientific notation as 4.5 x 10^8 km.

The distance to the Moon is given as km. To express this in scientific notation:
1. Determine the number between 1 and 10. In this case, it is 3.8.
2. Count the number of decimal places you moved to the left to get the number between 1 and 10. In this case, it is 5 decimal places.
3. Write the distance in scientific notation as 3.8 x 10^5 km.

Now let's move on to the cost of fuel. The cost is given as per liter. There is no need to convert this to scientific notation since it is already a regular decimal number.

Continuing with the given information:
- Distance to Mars: 4.5 x 10^8 km
- Distance to the Moon: 3.8 x 10^5 km
- Fuel efficiency: km/L
- Cost per liter of fuel:

We now need to determine the difference in fuel consumption between the two trips:
1. Calculate the fuel consumption for each trip by dividing the distance by the fuel efficiency:
- Fuel consumption for the Mars trip: (4.5 x 10^8 km) / km/L
- Fuel consumption for the Moon trip: (3.8 x 10^5 km) / km/L

To simplify the calculations, we can cancel out the common "km" units in the division, leaving us with only liters.

2. Calculate the cost of fuel for each trip by multiplying the fuel consumption by the cost per liter of fuel:
- Cost for the Mars trip: (Fuel consumption for Mars trip) *
- Cost for the Moon trip: (Fuel consumption for Moon trip) *

Finally, we can determine the savings by subtracting the cost of the Moon trip from the cost of the Mars trip:
- Savings = (Cost for Mars trip) - (Cost for Moon trip)

Please provide the values for fuel efficiency and cost per liter of fuel so that we can proceed with the calculations.
Chemistry
Step-by-step answer
P Answered by Master
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarity * L
mol = 0.15 * 0.03 = 0.0045 mol
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarit
Chemistry
Step-by-step answer
P Answered by Specialist
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation:
A mechanical device using which we can change the direction or magnitude of force applied is known as simple machine.
For example, in the given diagram there are two individual simple machines.
The machine helps in changing the direction or magnitude of force applied by the man. As a result, it becomes easy for him to carry different things easily from one place to another.
Thus, we can conclude that the statement Fiona is correct because the diagram shows two individual simple machines, is correct.
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation
Chemistry
Step-by-step answer
P Answered by PhD

Answer:

52.6 gram

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

Chemistry
Step-by-step answer
P Answered by PhD

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry
Step-by-step answer
P Answered by PhD

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N ×328 K

Solving:

Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry
Step-by-step answer
P Answered by PhD
15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.
Chemistry
Step-by-step answer
P Answered by PhD
Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g
Chemistry
Step-by-step answer
P Answered by PhD
Answer: B. carbon tetrachloride, CCI4
Explanation: The other options are incorrect. Let's write the correct formulas:
A. Diarsenic pentoxide - As2O5
C. Sodium dichromate - Na2Cr2O7
D. magnesium phosphide - Mg3P2
Chemistry
Step-by-step answer
P Answered by PhD
Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified in terms of hydrogen ions or hydroxide ions, or in terms of electron pairs. (look at the picture)
Let us note that from the pH scale, a pH of;
0 - 6.9 is acidic
7 is neutral
8 - 14 is basic

But pH= - log [H^+]
pOH = -log [OH^-]
Then;
pH + pOH = 14
Hence;
pH = 14 - pOH

a. [H+] = 6.0 x 10-10M
pH= 9.22 is basic
b. [OH-] = 30 × 10-2M
pH = 13.5 is basic
C. IH+1 = 20× 10-7M
pH = 0.56 is acidic
d. [OH-] = 1.0 x 10-7M
pH = 7 is neutral
Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified

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