Alyssa is trying to decide where to spend this year's vacation. She could go snorkeling in the *Sea of Tranquility on the Moon or she could go skiing on *Mount Olympus on Mars. With the price of fuel, she is wondering how much she will save by traveling to the Moon instead of Mars. Round trip to Mars ( d1 ) is 122000000 km, but round trip to the Moon (d2 ) is only 812000 km. Her car gets 1.54 x 10^3 km/L of fuel. At a cost of $3.23 x 10^3 per liter of fuel, how much will she save by going snorkeling instead of skiing? Convert d1 and d2 to scientific notation before listing them in the Given.

To convert distances to scientific notation, we need to express them as a number between 1 and 10 multiplied by a power of 10.

The distance to Mars is given as km. To express this in scientific notation:
1. Determine the number between 1 and 10. In this case, it is 4.5.
2. Count the number of decimal places you moved to the left to get the number between 1 and 10. In this case, it is 8 decimal places.
3. Write the distance in scientific notation as 4.5 x 10^8 km.

The distance to the Moon is given as km. To express this in scientific notation:
1. Determine the number between 1 and 10. In this case, it is 3.8.
2. Count the number of decimal places you moved to the left to get the number between 1 and 10. In this case, it is 5 decimal places.
3. Write the distance in scientific notation as 3.8 x 10^5 km.

Now let's move on to the cost of fuel. The cost is given as per liter. There is no need to convert this to scientific notation since it is already a regular decimal number.

Continuing with the given information:
- Distance to Mars: 4.5 x 10^8 km
- Distance to the Moon: 3.8 x 10^5 km
- Fuel efficiency: km/L
- Cost per liter of fuel:

We now need to determine the difference in fuel consumption between the two trips:
1. Calculate the fuel consumption for each trip by dividing the distance by the fuel efficiency:
- Fuel consumption for the Mars trip: (4.5 x 10^8 km) / km/L
- Fuel consumption for the Moon trip: (3.8 x 10^5 km) / km/L

To simplify the calculations, we can cancel out the common "km" units in the division, leaving us with only liters.

2. Calculate the cost of fuel for each trip by multiplying the fuel consumption by the cost per liter of fuel:
- Cost for the Mars trip: (Fuel consumption for Mars trip) *
- Cost for the Moon trip: (Fuel consumption for Moon trip) *

Finally, we can determine the savings by subtracting the cost of the Moon trip from the cost of the Mars trip:
- Savings = (Cost for Mars trip) - (Cost for Moon trip)

Please provide the values for fuel efficiency and cost per liter of fuel so that we can proceed with the calculations.

Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.

Answer:

A

Step-by-step explanation:

The input force is 50 N. But it will not create not any change. No mechanical advantage is observed.

Answer:

52.6 gram

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.

Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g

Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g